Please help! Correct answer only, please! Consider the matrix shown below: Using your calculator find the inverse of the matrix Q (i.e. Find Q^-1).
Answers
Answer: C
Step-by-step explanation:
In order to find the inverse, transpose the matrix then find the determinant of each 2 x 2 matrix within it.
[tex]Q=\left[\begin{array}{ccc}2&2&3\\1&1&1\\3&2&1\end{array}\right] \qquad \rightarrow \qquad Q^T=\left[\begin{array}{ccc}2&1&3\\2&1&2\\3&1&1\end{array}\right][/tex]
[tex]det\left[\begin{array}{cc}1&2\\1&1\end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&2\\3&1\end{array}\right]=\bold{-4}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\\\\\\\det\left[\begin{array}{cc}1&3\\1&1\end{array}\right] =\bold{-2}\qquad det\left[\begin{array}{cc}2&3\\3&1\end{array}\right]=\bold{-7}\qquad det\left[\begin{array}{cc}2&1\\3&1\end{array}\right] =\bold{-1}\\[/tex]
[tex]det\left[\begin{array}{cc}1&3\\1&2 \end{array}\right] =\bold{-1}\qquad det\left[\begin{array}{cc}2&3\\2&2\end{array}\right]=\bold{-2}\qquad det\left[\begin{array}{cc}2&1\\2&1\end{array}\right] =\bold{0}[/tex]
[tex]Q^{-1}=\large\left[\begin{array}{ccc}1&-4&1\\-2&7&-1\\-1&-2&0\end{array}\right][/tex]
Related Questions
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit. Select all that apply.
{f(x) = 2(3)^x
{g(x) = 10log(x+3)
(-1.9, 15.9)
(-2, 0.2)
(1.9, -15.9)
(2, -0.2) (1.9, 15.9)
Answers
Answer:
closest choice: (-2, 0.2)
Step-by-step explanation:
The attached image from a graphing calculator shows the solutions (to the nearest tenth) to be ...
(-1.9, 0.2)
(1.0, 6.0)
The closest of the offered choices is (-2, 0.2). None are actually correct.
Mathematics
ose the correct answer:
. What number should be added to (-5/16) to get ( 7/24)?
Answers
Answer:
0.6042 or 29/48
Step-by-step explanation:
-5/16 = -0.3125
7/24 = 0.2917
0.2917 - -0.3125 = 0.6042
0.6042 ≅ 29/48
Answer:
29/48
Step-by-step explanation:
-5/16 + x= 7/24
x= 7/24-(-5/16)
x=7/24+5/16
x= 2*7/2*24+ 3*5/3*16
x=29/48
According to 2013 report from Population Reference Bureau, the mean travel time to work of workers ages 16 and older who did not work at home was 30.7 minutes for NJ State with a standard deviation of 23 minutes. Assume the population is normally distributed.
Required:
a. If a worker is selected at random, what is the probability that his travel time to work is less than 30 minutes?
b. Specify the mean and the standard deviation of the sampling distribution of the sample means, for samples of size 36.
c. What is the probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes?
Answers
Answer:
a) 48.80% probability that his travel time to work is less than 30 minutes
b) The mean is 30.7 minutes and the standard deviation is of 3.83 minutes.
c) 13.13% probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 30.7, \sigma = 23[/tex]
a. If a worker is selected at random, what is the probability that his travel time to work is less than 30 minutes?
This is the pvlaue of Z when X = 30. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{30 - 30.7}{23}[/tex]
[tex]Z = -0.03[/tex]
[tex]Z = -0.03[/tex] has a pvalue of 0.4880.
48.80% probability that his travel time to work is less than 30 minutes
b. Specify the mean and the standard deviation of the sampling distribution of the sample means, for samples of size 36.
[tex]n = 36[/tex]
Applying the Central Limit Theorem, the mean is 30.7 minutes and the standard deviation is [tex]s = \frac{23}{\sqrt{36}} = 3.83[/tex]
c. What is the probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes?
This is 1 subtracted by the pvalue of Z when X = 35. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{35 - 30.7}{3.83}[/tex]
[tex]Z = 1.12[/tex]
[tex]Z = 1.12[/tex] has a pvalue of 0.8687
1 - 0.8687 = 0.1313
13.13% probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes
Composition of the function is commuatative
Answers
Answer:
The functions g and f are said to commute with each other if g ∘ f = f ∘ g. Commutativity is a special property, attained only by particular functions, and often in special circumstances. For example, |x| + 3 = |x + 3| only when x ≥ 0. ... The composition of one-to-one functions is always one-to-one.
\
In a group of 50 patrons, 14 patrons like lattes and espressos, 11 patrons like
espressos and cappuccinos, 7 patrons like lattes and cappuccinos, and 3
patrons like all 3 coffee drinks. Altogether, 22 patrons like lattes, 30 patrons
like espressos, and 23 patrons like cappuccinos. How many patrons don't like
any of these coffee drinks?
Answers
Answer:the answer would be 4. Hope this helps.
Step-by-step explanation:
Using the formula of union of three events, the number of patrons who didn't like any of given coffee drinks = 4.
What is union of three events?Union of three events : P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C).
n (latte ∩ espressos) = 14
n (espressos ∩ cappuccinos) = 11
n (lattes ∩ cappuccinos) = 7
n (latte ∩ espressos ∩ cappuccinos) = 3
n (lattes) = 22
n (espressos) = 30
n (cappuccinos) = 23
n(latte ∪ espressos ∪ cappuccinos) =
= n (lattes) + n (espressos) + n (cappuccinos) - n (latte ∩ espressos) - n (espressos ∩ cappuccinos) - n (lattes ∩ cappuccinos) + n (latte ∩ espressos ∩ cappuccinos)
= 22 + 30 + 23 - 14 - 11 - 7 + 3
= 46
n (universe) = 50
Number of patrons who didn't like any of these drinks =
= n (universe) - n (latte ∪ espressos ∪ cappuccinos) = 50 - 46 = 4
Learn more about union of three events here
https://brainly.com/question/14614116
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Here is a solid square-based pyramid.
The base of the pyramid is a square of side 12cm.
The height of the pyramid is 8cm.
X is the midpoint of QR and XT = 10cm.
A) Draw the front elevation of the pyramid from the direction of the arrow. Use a scale of 1 square to 1cm.
B) Work out the total surface area of the pyramid.
Answers
Answer:
Step-by-step explanation:
A. The front elevation of the pyramid in the direction of the arrow is herewith attached to this answer.
B. Base of the pyramid is a square of side 12 cm.
The height of the pyramid is 8 cm.
Slant height, XT, is 10 cm.
The total surface area of the pyramid can be determined by adding the surface areas that make up the shape.
Area of the triangular face = [tex]\frac{1}{2}[/tex] × base × slant height
= [tex]\frac{1}{2}[/tex] × 12 × 10
= 60 [tex]cm^{2}[/tex]
Area of the square base = length × length
= 12 × 12
= 144 [tex]cm^{2}[/tex]
Total surface area of the pyramid = area of the base + 4 (area of the triangular face)
= 144 + 4(60)
= 144 + 240
= 384 [tex]cm^{2}[/tex]
Therefore, total surface area of the pyramid is 384 [tex]cm^{2}[/tex].
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts College, and 30% of the students were in the Education College. To see whether or not the proportions have changed, a sample of 300 students from the university was taken. Ninety of the sample students are in the Business College, 120 are in the Liberal Arts College, and 90 are in the Education College. This problem is an example of a a. Marascuilo procedure. b. multinomial population. c. z test for proportions. d. test for independence.
Answers
Answer:
The correct answer will be Option B (multinomial population).
Step-by-step explanation:
The population is considered as multinomial whether its information is prescriptive or corresponds to the set of discreet non-overlapping groups. The hypothesis again for fitness test besides multinomial distribution is that even though the approximately normal f I seem to be equivalent to the required number e I across each segment.Here, because we have been testing whether the sampling data matches the hypothesized proportions as mentioned, this is indeed a multinomial population issue (because there have been more least two generations).Other given options are not connected to the given situation. So that Option B seems to be the perfect solution.
Having integrated with respect to ϕ and θ, you now have the constant 4π in front of the integral and are left to deal with ∫[infinity]0A21(e−r/a)2r2dr=A21∫[infinity]0r2(e−r/a)2dr.
What is the value of A21∫[infinity]0r2(e−r/a)2dr?Express your answer in terms of A1 and a.
Find the unique positive value of A1.
Express your answer in terms of a and π.
Answers
Answer:
Step-by-step explanation:
[tex]\int\limits^{\infty}_0 {A^2_1} (e^{-r/a})r^2dr= {A^2_1}\int\limits^{\infty}_0r^2(e^{-r/a})^2\, dr)[/tex]
[tex]=A_1^2\int\limits^{\infty}_0 r^2e^{-2r/a}\ dr[/tex]
[tex]=A_1^2[\frac{r^2e^{2r/a}}{-2/a} |_0^{\infty}-\int\limits^{\infty}_0 2r\frac{e^{-2r/a}}{-2/a} \ dr][/tex]
[tex]=A^2_1[0+\int\limits^{\infty}_0 a\ r\ e^{-2r/a}\ dr][/tex]
[tex]=A^2_1[\frac{a \ r \ e^{-2r/a}}{-2/a} |^{\infty}_0-\int\limits^{\infty}_0 \frac{a \ e^{-2r/a}}{-2/a} \ dr][/tex]
[tex]=A_0^2[0-0+\int\limits^{\infty}_0 \frac{a^2}{2} e^{-2r/a}\ dr\\\\=A_1^2\frac{a^2}{2} \int\limits^{\infty}_0 e^{-2r/a}\ dr\\\\=A_1^2\frac{a^2}{2} [\frac{e^{-2r/a}}{-2/a} ]^{\infty}_0[/tex]
[tex]=\frac{A_1^2a^2}{2} -\frac{a}{2} [ \lim_{r \to \infty} [e^{-2r/a} -e^0]\\\\=\frac{A_1^2a^2}{2} -(\frac{a}{2}) (0-1)[/tex]
[tex]=\frac{A_1^2a^3}{4}[/tex]
[tex]\therefore A_1^2\int\limits^{\infty}_0 r^2(e^{-r/a}) \ dr =\frac{A_1^2a^3}{4}[/tex]
Find the unique positive value of A1
[tex]=4\pi (\frac{A_1^2a^3}{4} )\\\\=A_1^2a^3\pi\\\\A_1^2=\frac{1}{a^3\pi} \\\\A_1=\sqrt{\frac{1}{a^3\pi} }[/tex]
Among fatal plane crashes that occurred during the past 55 years, 415 were due to pilot error, 96 were due to other human error, 169 were due to weather, 622 were due to mechanical problems, and 68 were due to sabotage. Construct the relative frequency distribution. What is the most serious threat to aviation safety, and can anything be done about it?
Answers
Answer:
Relative frequency:
[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]
The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.
Step-by-step explanation:
We have the data for fatal plane crashes. The sum of plane crashes is
We can calculate the relative frequency as:
[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]
We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.
Point R has coordinates (-5, -7) and point T has coordinates (3,-3).
Which point is located 1/4 of the distance from point R to point T?
Enter x-coordinate of the point here .......
and the y-
coordinate of the point here....
Answers
Answer:
(x, y) = (-3, -6)
Step-by-step explanation:
The (x, y) distance from R to T is ...
(Δx, Δy) = T - R = (3, -3) -(-5, -7) = (3 -(-5), -3 -(-7)) = (8, 4)
Then 1/4 of the distance is ...
(Δx, Δy)/4 = (8, 4)/4 = (2, 1)
This is added to the R coordinates to find the desired point:
point = R +(2, 1) = (-5, -7) +(2, 1) = (-5+2, -7+1) = (-3, -6)
The coordinates are ...
x-coordinate: -3
y-coordinate: -6
Solve the equation 3 Z + 5 = 35
Answers
Answer:
z=10 i hope this will help you
Step-by-step explanation:
3z+5=35
3z=35-5
3z=30
z=10
Answer:
Z = 10
Step-by-step explanation:
3Z+5=35
Subtract 5 from both sides
3Z=30
Divide both sides by 3
Z=10
"How much room is there to spread frosting on the cookie?" Clare says, "The radius of the cookie is about 3 cm, so the space for frosting is about 6 cm." Andre says, "The diameter of the cookie is about 3 inches, so the space for frosting is about 2.25 sq. in."
A. Is this question talking about area or circumference? Pick one. Why?
B. Which person is most likely correct, Clare or Andre? Why?
Answers
Answer:
(a)Area
(b)Andre is Right
Step-by-step explanation:
(a)Frost is spread on the surface of a cookie, therefore the question is talking about the area of the circular cookie.
(b)
Andre says, "The diameter of the cookie is about 3 inches, so the space for frosting is about 2.25 sq. in
Area of a Circle[tex]=\pi r^2[/tex]
Radius =Diameter/2 =3/2=1.5 Inches
Therefore, Space for frosting on the cookie
[tex]=\pi *1.5^2\\=2.25\pi$ in^2[/tex]
Andre is right.
If f(x) = (-x)^3, what is f(-2)?
-6
-8
8
6
Answers
Answer:
The answer is 8
Step-by-step explanation:
Plug -2 in for x. The double-negative inside the parenthesis makes it positive, then do the exponent.
Answer:
-(-2)^3 = 2^3 = 8
Answer is C
Step-by-step explanation:
So we plug in the numbers. We have -2 as x. (-(-2)^3 would be our thing. Thats because our x is the negative so the negative of -2 is 2.
2^3 = 8
therefore its 8
Three added to the product of -4 and a number X is less than 5 added to the product of -3 and the number. What is the number?
Answers
Answer:
x=-2
Step-by-step explanation:
3 + -4x = 5+ -3x
-4x = 2 - 3x
-x = 2
x = -2
What’s the correct answer for this question?
Answers
Answer:
Height = 12 inches
Step-by-step explanation:
Volume = Area × Height
1080 = 90 × H
H = 1080/90
H = 12 inches
Find the x-intercept(s) and the coordinates of the vertex for the parabola.
Answers
Answer:
see explanation
Step-by-step explanation:
Given
y = x² - 2x - 8
To find the x- intercepts let y = 0 , that is
x² - 2x - 8 = 0 ← in standard form
(x - 4)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x + 2 = 0 ⇒ x = - 2
x- intercepts : x = - 2, x = 4
The x- coordinate of the vertex is mid way between the x- intercepts, that is
[tex]x_{vertex}[/tex] = [tex]\frac{-2+4}{2}[/tex] = [tex]\frac{2}{2}[/tex] = 1
Substitute x = 1 into the equation for corresponding y- coordinate
y = 1² - 2(1) - 8 = 1 - 2 - 8 = - 9
vertex = (1, - 9 )
There are 15 marbles in a bag; 10 are blue, 4 are red and 1 is green. Marbles are drawn and NOT replaced 8 times, with the number of red marbles being recorded. What is the probability of getting exactly 3 red marbles? (Write as a percentage, correct to two decimals. eg: 12.34%)
Answers
Answer: There is a 0.88% chance of pulling three red marbles in a row.
Step-by-step explanation:
First pull = 4/15 (26.67%)
second pull = 3/14 (21.43%)
Third pull = 2/13 (15.38%)
You need to multiply these three fractions to get the probability of pulling three reds in a row, doing that will get you 4/455 or 0.88%
A rectangle has an area of 96 cm2 The length of the rectangle is 4 cm longer than the width. Work out the length and width of the rectangle.
Answers
length: 4+W
Area: 2(4+W) + 2W = 96
8+2W+2W = 96
8+4W = 96
4W = 88
W= 22cm
Calculate for length: 2L + 2(22) = 96
2L + 44 = 96
2L = 52
L = 26cm
• The length is 26cm and width is 22 cm.
01:30:4
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the
solution set of this problem?
Answers
Answer:
x<_ 21
Step-by-step explanation:
5(x+27)>_ =6(x+26)
5x +135 >_ 6x +156
5x >_6x +21
-x>_21
x<_21
There are 4 blue tiles, 12 red tiles, and 6 green tiles in a bag. Which model represents the probability, P, that Luke will pick a red tile from the bag?
Answers
Answer:
The Probability that will pick a red tile from the bag
[tex]P(E) = \frac{6}{11}[/tex] = 0.545
Step-by-step explanation:
Explanation:-
Given data 4 blue tiles, 12 red tiles, and 6 green tiles in a bag
Total = 4 B + 12 R + 6 G = 22 tiles
Total number of exhaustive cases
n (S) = [tex]22 C_{1} = 22 ways[/tex]
The Probability that will pick a red tile from the bag
[tex]P(E) = \frac{n(E)}{n(S)} = \frac{12 C_{1} }{22 C_{1} } = \frac{12}{22}[/tex]
[tex]P(E) = \frac{6}{11}[/tex]
P(E) = 0.545
Final answer:-
The Probability that will pick a red tile from the bag = 0.545
HELP PLEASE!!!!!!!!!!!!!!
Answers
Answer:
Savannah
Step-by-step explanation:
Emery has solved it incorrectly;
x = 100
I don’t know this one
Answers
Answer:
C
Step-by-step explanation:
2/3x - 5>3
Add 5 to each side
2/3x - 5+5>3+5
2/3x > 8
Multiply each side by 3/2
3/2 *2/3x > 8*3/2
x > 12
There is an open circle at 12 and the lines goes to the right
Problem PageQuestion A Web music store offers two versions of a popular song. The size of the standard version is 2.6 megabytes (MB). The size of the high-quality version is 4.2 MB. Yesterday, the high-quality version was downloaded four times as often as the standard version. The total size downloaded for the two versions was 4074 MB. How many downloads of the standard version were there?
Answers
Answer:
There were 210 downloads of the standard version.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of downloads of the standard version.
y is the number of downloads of the high-quality version.
The size of the standard version is 2.6 megabytes (MB). The size of the high-quality version is 4.2 MB. The total size downloaded for the two versions was 4074 MB.
This means that:
[tex]2.6x + 4.2y = 4074[/tex]
Yesterday, the high-quality version was downloaded four times as often as the standard version.
This means that [tex]y = 4x[/tex]
How many downloads of the standard version were there?
This is x.
[tex]2.6x + 4.2y = 4074[/tex]
Since [tex]y = 4x[/tex]
[tex]2.6x + 4.2*4x = 4074[/tex]
[tex]19.4x = 4074[/tex]
[tex]x = \frac{4074}{19.4}[/tex]
[tex]x = 210[/tex]
There were 210 downloads of the standard version.
A rectangular fish tank is 50 cm long, 40 cm wide, and 20 cm high. a) How many cubic centimeters of water will the tank hold? b) How many milliliters of water will the tank hold? c) How many liters of water will the tank hold?
Answers
Answer:
40 litres
Step-by-step explanation:
V = l x w x h
50 x 40 x 20 = 40000
40000 cm^3
1cm^3 = 1ml
40000 cm^3/ 1cm^3 = 40000ml
40000 x 10^-3 = 40 litres
Assume that 2 cards are drawn from a standard 52-card deck. Find the following probabilities.
a) Assume the cards are drawn without replacement. Find the probability of drawing a club followed by a club.
b) Assume the cards are drawn with replacement. Find the probability of drawing a club followed by a club.
a. The probability of drawing a club followed by a club without replacement is
(Simplify your answer.)
b. The probability of drawing a club followed by a club with replacement is
(Simplify your answer.)
Answers
Answer:
A.0.059 , B.0.063
Step-by-step explanation:
1. There are 13 clubs in a pack of 52 cards;
Hence the probability of picking the first club is 13/52;
The probability of picking the second is 12/ 51( remember one card has been removed already so the total number of cards decreases).
Probability of picking two clubs in succession is ;
13/52 × 12/51 = 0.0588 = 0.059( to the nearest thousandth).
2. The probability of drawing a club followed by a club with replacement is;
13/52 × 13 /52 = 0.0625 = 0.063( to the nearest thousandth)
Hypothetical Situation: A scientist notices that her bees may be avoiding a specific pollen from flower "X" despite its abundance in the area. To test to see if this behavior is reproducible and not anecdotal, she decides to provide a choice test to her bees. She does this by putting the bees in a small cage with two dishes. One with pollen from flower "X" the other is pollen from a flower that she knows her bees collect, flower "Y." She counts how many times the bees chooses Flower "X" vs Flower "Y" and collects this data.
What is experimental group?
Answers
Answer:
The experimental group in this case are the group of bees that are put in the small cage.
Step-by-step explanation:
The experimental group is the group of subjects that participate in the test. They are usually assigned to the treatments in study. In some cases there is a control group, with no assigned treatment.
In this case, the bees that she put in the cage, and they are not assigned to a particular treatment. It can be considered a control group.
Given the two parallel lines determine the value of x
Answers
Answer:
D. 150°
Step-by-step explanation:
x= 150°
Choice D
4) If the data below contained an outlier, which coordinate would best represent the outlier?
(MGSE8.SP.1)
100
90
80
70
60
50
Weight
(kgs)
40
30
20
10
0
0
200
250
100 150
Height (cms)
A. (150, 60)
B. (50,20)
C. (200, 100)
D. (250, 80)
Answers
Answer:
D. (250, 80)
Step-by-step explanation:
a) Outliers are values that "lie outside" the other values in a dataset, because their values are "far away" from the main group of data.
b) In this case, the values of A, B, and C have ratios of their coordinates of about 2.5, but the coordinate ratio of D is more than 3. This makes it to lie far away from the group of data, and therefore an outliner.
c) The Ratios of the Coordinate Values are calculated as follows: A = 2.5 (150/60), B = 2.5 (50/20), C = 2 (200/100), while D = 3.125 (250/80).
Determine whether the following sequence converges or diverges and describe whether it does do so monotonically or by oscillation. Give the limit when the sequence converges.
{(-1.00000005)^n}
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
a. The sequence diverges by oscillation.
b. The sequence converges monotonically. It converges to:________
c. The sequence converges by oscillation. It converges to:________
d. The sequence diverges monotonic ally.
Answers
Answer:
a
Step-by-step explanation:
(-1.00000005)^n
as n becomes very large, the function increases in both positive and negative direction.
If n=1, -1.00000005
if n=2, 1.0000001
if n= 3, -1.00000015
if n=20, 1.000001
if n=21, -1.00000105
To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the three treatments. You are given the results below. Treatment Observation A 20 30 25 33 B 22 26 20 28 C 40 30 28 22 The test statistic to test the null hypothesis equals _____.
Answers
Answer:
The test statistic to test the null hypothesis equals 1.059
Step-by-step explanation:
From the given information; we have:
Treatment Observations
A 20 30 25 33
B 22 26 20 28
C 40 30 28 22
The objective is to find the test statistic to test the null hypothesis; in order to do that;we must first run through a series of some activities.
Let first compute the sum of the square;
Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex] + Error sum of squares (ESS)
where:
(TSS) = [tex]\sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}oo)^2[/tex] with (n-1) df
[tex](T_r SS)[/tex] [tex]= \sum \limits ^v_{i=1} n_i( \overline yio- \overline {y}oo)^2[/tex] with (v-1) df
[tex](ESS) = \sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}io)^2[/tex] with (n-v) df
where;
v= 3
[tex]n_i=[/tex]4
i = 1,2,3
n =12
[tex]y_{ij}[/tex] is the [tex]j^{th[/tex] observation for the [tex]i^{th[/tex] treatment
[tex]\overline{y}io[/tex] is the mean of the [tex]i^{th[/tex] treatment i = 1,2,3 ; j = 1,2,3,4
[tex]\overline y oo[/tex] is the overall mean
From the given data
[tex]\overline y oo = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij)^2= 27[/tex]
[tex]TSS = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij- 27)^2 = 378[/tex]
[tex]T_r SS= \sum \limits^3_{i=1}4 (\overline y io - \overline yoo)^2[/tex]
[tex]=4(27-27)^2+4(24-27)^2+4(30-27)^2 = 72[/tex]
Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex] + Error sum of squares (ESS)
(TSS) = 378 - 72
(TSS) = 306
Now; to the mean square between treatments (MSTR); we use the formula:
MSTR = TrSS/df(TrSS)
MSTR = 72/(3 - 1)
MSTR = 72/2
MSTR = 36
The mean square within treatments (MSE) is:
MSE = ESS/df(ESS)
MSE = 306/(12-3)
MSE = 306/(9)
MSE = 34
The test statistic to test the null hypothesis is :
[tex]T = \dfrac{ \dfrac{TrSS}{\sigma^2}/(v-1) }{ \dfrac{ESS}{\sigma^2}/(n-v) } = \dfrac{MSTR}{MSE} \ \ \ \approx \ \ T(\overline {v-1}, \overline {n-v})[/tex]
[tex]T = \dfrac{36}{34}[/tex]
T = 1.059