Suppose 275 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

I attached the image of the equation for reference

Suppose 275 G Of NO3- Flows Into A Swamp Each Day. What Volume Of CO2 Would Be Produced Each Day At 17.0C

Answers

Answer 1

Answer:

264.28 L of CO₂

Explanation:

We'll begin by calculating the number of moles present in 275 g of NO₃¯. This can be obtained as follow:

Mass of NO₃¯ = 275 g

Molar mass of NO₃¯ = 14 + (16×3) = 14 + 48 = 62 g/mol

Mole of NO₃¯ =?

Mole = mass / molar mass

Mole of NO₃¯ = 275 / 62

Mole of NO₃¯ = 4.44 moles

Next, we shall determine the number of mole of CO₂ produced from the reaction. This can be obtained as follow:

2NO₃¯ + 5CO + 2H⁺ —> N₂ + H₂O + 5CO₂

From the balanced equation above,

2 moles of NO₃¯ reacted to produced 5 moles of CO₂.

Therefore, 4.44 moles of NO₃¯ will react to produce = (4.44 × 5) / 2 = 11.1 moles of CO₂.

Thus, 11.1 moles of CO₂ were produced from the reaction.

Finally, we shall determine the volume of CO₂ produced each day. This can be obtained as follow:

Temperature (T) = 17 °C = 17 °C + 273 = 290 K

Pressure (P) = 1 atm

Number of mole (n) of CO₂ = 11.1 moles

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of CO₂ =?

PV = nRT

1 × V = 11.1 × 0.0821 × 290

V = 264.28 L

Thus, 264.28 L of CO₂ would be produced each day.

Answer 2

The volume of [tex]\rm CO_2[/tex] produced has been 264.28 L.

The volume of the carbon dioxide gas produced can be calculated with the ideal gas equation.

The moles of [tex]\rm NO_3^-[/tex] has been:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of 275 g  [tex]\rm NO_3^-[/tex] has been:

Moles = [tex]\rm \dfrac{275}{62}[/tex]

Moles of  [tex]\rm NO_3^-[/tex] = 4.44 moles

The balanced equation gives that with the reaction of 2 moles [tex]\rm NO_3^-[/tex] , 5 moles carbon dioxide has been formed.

Moles of carbon dioxide formed with 4.44 mol [tex]\rm NO_3^-[/tex] has been:

2 moles [tex]\rm NO_3^-[/tex] = 5 moles [tex]\rm CO_2[/tex]

4.44 moles [tex]\rm NO_3^-[/tex]  = 11.1 moles [tex]\rm CO_2[/tex].

The volume of the [tex]\rm CO_2[/tex] can be calculated as:

Pressure [tex]\times[/tex] Volume = moles [tex]\times[/tex] Rydberg constant [tex]\times[/tex] temperature

For the [tex]\rm CO_2[/tex] produced:

1 atm [tex]\times[/tex] Volume = 11.1 mol [tex]\times[/tex] 0.0821 atm.L/K.mol [tex]\times[/tex] 290 K

Volume = 264.28 L.

The volume of [tex]\rm CO_2[/tex] produced has been 264.28 L.

For more information about the volume of gas, refer to the link:

https://brainly.com/question/15265703


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Explanation:

I might be wrong though.

Answer:

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Answers

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Answers

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Answers

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Hello!

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Answers

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Answers

Answer:

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Answers

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Answers

Answer:

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Answer:

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Answers

Answer:

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Answers

The density in lbs/in³ units : 0.697

Further explanation

Given

Density of gold is 19.3 g/cm³

Required

Conversion to  lbs/in³

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

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[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]

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1 cm³ = 0,0610237 in³

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[tex]\tt 19.3~\dfrac{g}{1~cm^3}\times \dfrac{cm^3}{0.0610237~in^3}\times \dfrac{0.00220462~lbs}{1~g}=0.697~lbs/in^3[/tex]

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a. It is the smoke that a smoker inhales from a cigarette.

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Answers

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5. What is the wavelength of a radio station emitting its signal at 95.5 MHz? Estimate your
answer to the nearest power of ten.

Answers

Answer:

[tex]\lambda=314\times 10^{-2}\ m[/tex]

Explanation:

Given that,

Frequency, f = 95.5 MHz

We need to find the wavelength of a radio station emitting its signal.

The relation between the frequency and the wavelength is given by :

[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{95.5\times 10^6}\\\\=3.14\ m[/tex]

or

[tex]\lambda=314\times 10^{-2}\ m[/tex]

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Suppose an AM talk radio station broadcasts radio waves with a frequency of 930. kHz. Calculate the wavelength of these radio waves.
Round your answer to 3 significant digits.

Answers

Answer:

323 m.

Explanation:

From the question given above, the following data were:

Frequency (f) = 930 KHz

Wavelength (λ) =?

Next, we shall convert 930 KHz to Hz. This can be obtained as follow:

1 KHz = 1000 Hz

Therefore,

930 KHz = 930 KHz × 1000 Hz / 1 KHz

930 KHz = 93×10⁴ Hz

Thus, 930 KHz is equivalent to 93×10⁴ Hz

Wavelength (λ) of a wave and the frequency (f) are related according to the equation:

Velocity = wavelength × frequency

v = λf

With the above formula, we can obtain the wavelength of radio wave as follow:

Frequency (f) = 93×10⁴ Hz

Velocity (v) of electromagnetic wave = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 93×10⁴

Divide both side by 93×10⁴

λ = 3×10⁸ / 93×10⁴

λ = 323 m

Thus, the wavelength of the radio wave is 323 m

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