55c + 13 < 75c + 39
Solve for c

Answer:

$9

Step-by-step explanation:

Let the price of one order of wings be w.

Let the price for one order of soft drinks be s.

Three friends went to a restaurant and ordered two orders of wings and three soft drinks. Their bill totaled $22.50. This means that:

2w + 3s = 22.50 _____________(1)

Five friends went to the same restaurant and ordered three orders of wings and a soft drink each. Their bill totaled $34.50. This means that:

3w + 5s = 34.50 ______________(2)

We have a system of quadratic equations:

2w + 3s = 22.50 _____________(1)

3w + 5s = 34.50 ______________(2)

Multiply (1) by 5 and (2) by 3:

10w + 15s = 112.50 _______(3)

9w + 15s = 103.50 _______(4)

Subtract (4) from (3):

w = $9

Therefore, the price of one order of wings is $9.

Answer: Y=3x -7

Y=x-1

X=Y=

Step-by-step explanation:

Answer:

  (5x -6)(5x +6) = 0

Step-by-step explanation:

Subtract 36 to put the equation in standard form. In this form, it looks like the difference of squares, so can be factored as such.

  25x^2 -36 = 0

  (5x)^2 -6^2 = 0

  (5x -6)(5x +6) = 0

Answer:

111.60

Question:

Ania bought two books in a bookstore and paid 37.20, and Jurek paid three times more for his. How much did Jurek pay?

Step-by-step explanation:

This is a question on multiplying decimals by natural numbers.

Number if books bought by Ania = 2

Cost for the two books = 37.20

Jurek paid = 3 times the amount Ania paid

Amount Jurek paid = 3×37.20

To multiply decimals with whole numbers, first multiply without the decimals

3×3720 = 11160

3 has no decimal place

37.20 has 2 decimal place

Therefore the answer would be in two decimal place = 111.60

So 3× 37.2= 111.60

Step-by-step explanation:

-23d + 81 < - 98d + 1

81 - 1 < - 98d + 23d

80 < - 75d

80/ - 75 < d

10/ - 3 < d

the answer is A: 146 ≤ 9c + 10

Answer:

true

Step-by-step explanation:

just took test

Answer:

height = 6 mm

Step-by-step explanation:

The prism is a rectangular prism. The base area of the prism is 24 mm². The volume of the prism is given as 144 mm³.

The height of the prism can be solved as follows.

Volume of the rectangular prism = Bh

where

B = base area

h = height

Volume = 144 mm³

B = 24 mm²

volume = Bh

144 = 24 × h

144 = 24h

divide both sides by 24

h = 144/24

h = 6 mm

Answer:

c

Step-by-step explanation:

edg 2022

Answer:

[tex]\dfrac{5\pm\sqrt{47}}{6}[/tex]

Step-by-step explanation:

Let's start by setting y to 0 to find the roots of the quadratic.

[tex]x=\dfrac{5\pm \sqrt{25+12}}{6}=\\\\\dfrac{5\pm\sqrt{47}}{6}[/tex]

Hope this helps!

Answer:

Area = PI * radius^2

radius^2 = Area / PI

radius^2 = 169*PI/PI

radius^2 = 169

radius = 13

Step-by-step explanation:

Answer: 360ᴼ

Step-by-step explanation:

If a figure goes 360ᴼ around the graph, it will be mapped onto itself.

360ᴼ is full circle (number of degrees in a circle), so the figure just went around in a circle, back into the same location before it rotated.

Answer:

360

Step-by-step explanation:

i took the text

Answer:

The answer is 13

Step-by-step explanation:

Two positive and consecutive old numbers are x and x - 2.

=> x(x - 2) = 143

=> x^2 - 2x - 143 = 0

=> x^2 + 11x - 13x - 143 = 0

=> x(x + 11) - 13(x + 11) = 0

=> (x + 11)(x - 13) = 0

=>  x = -11 (invalid)

or x = 13 (valid), the remaining number is 13 - 2 = 11

=> The two numbers are 11 and 13, and the greater number is 13.

Hope this helps!

:)

Answer:

top: 2

bottom: 13

Step-by-step explanation:

step

by

step

explanation

Answer:

(See explanation below for further details)

Step-by-step explanation:

The domain of the function is:

[tex]x \in \mathbb{R} - \{ \pm \pi \cdot i \}[/tex] for [tex]i \in \mathbb{N}_{O}[/tex]

The range of the function is:

[tex]f(x) \in \{-\infty, +\infty \}[/tex]

There are no absolute extrema and such function is not bounded.

Function is symmetric, whose period is π.

Lastly, the set of asymptotes is:

[tex]x = \pm \pi \cdot i[/tex], for [tex]i \in \mathbb{N}_{O}[/tex]

Answer:

Step-by-step explanation:

edge

Answer:

if the 5 numbers are different, the maximum difference is 64

Step-by-step explanation:

We have 5 positive (different) integers, a, b, c, d and e (suppose that are ordered from least to largest, so a is the smallest and b is the largest.

The mean will be:

M = (a + b + c + d + e)/5 = 15.

Now, if we want to find the largest difference between a and e, then we must first select the first 4 numbers as the smallest numbers possible, this is:

a = 1, b = 2, c = 3 and d = 4

M = (1 + 2 + 3 + 4 + d)/5 = 15

M = (10 + d)/5 = 15

10 + d = 15*5 = 75

d = 75 - 10 = 65

then the difference between a and d is = 65 - 1 = 64.

Now, if we take any of the first 4 numbers a little bit bigger, then we will see that the value of d must be smaller, and the difference between d and a will be smaller.

Answer:

A meter is not part of the metric system. It's part of the U.S. customary system.

If it is asking if that equation is the quadratic formula, then the answer is false. The reason why is that the first 'b' should be negative

The quadratic formula is

[tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

Answer: always “X”

Step-by-step explanation:

Answer:

i would use the variable b because b = brochures.

Step-by-step explanation:

i hope this helped heh

Complete Question

A box is formed by cutting squares from the four corners of a sheet of paper and folding up the sides. However, the size of the paper is unknown!

Answer:

(a)[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)f(1.3)-f(0.2)

(d) f(5.6)-f(5.5)

Step-by-step explanation:

Let the Length of the paper =l  (in inches)

Let the Width of the paper =w  (in inches)

Let the length of the cutout square = x (in inches)

Volume of the box: [tex]f(x)=x(l-2x)(w-2x)[/tex]

(a)When the cutout length is 0.2 inches.

x=0.2

Volume of the box (in cubic inches) ,

[tex]f(0.2)=0.2(l-0.4)(w-0.4)[/tex]

(b)When the cutout length is 01.3 inches.

x=1.3

Volume of the box (in cubic inches) ,

[tex]f(1.3)=1.3(l-2.6)(w-2.6)[/tex]

(c)If the cutout length increases from 0.2 inches to 1.3 inches.

Change In volume (in cubic inches):

[tex]f(1.3)-f(0.2)\\=1.3(l-2.6)(w-2.6)-0.2(l-0.4)(w-0.4)[/tex]

(d)If the cutout length increases from 5.5 inches to 5.6 inches.

Change In volume (in cubic inches):

[tex]f(5.6)-f(5.5)\\=5.6(l-11.2)(w-11.2)-5.5(l-11)(w-11)[/tex]

Answer:

y = -2x + 5

slope = -2

y intercept = 5

Step-by-step explanation:

Slope intercept form of equation of line is given by y = mx + c

where m is the slope of line

c is the y intercept i.e point where given line intersect y axis.

________________________________________________

given equation 4x + 2y = 10

we have to re-write this equation in form y = mx + c

4x + 2y = 10

subtraction 4x from LHS and RHS

4x + 2y - 4x= 10 - 4x

2y = 10- 4x

we have to eliminate 2 from y for that we

divide  LHS and RHS by 2 we

2y /2 = 10/2- 4x/2

y = 5 - 2x

rearranging it in y = mx+c form

y = -2x + 5

thus, m = -2 , c = 5

Answer:

The probability that at least one defective card appears in the sample

P(D) = 0.9644 or 96.44%

Step-by-step explanation:

Given;

Total number of cards t = 140

Number of defective cards = 20

Number of non defective cards x = 140-20 = 120

The probability that at least one defective card = 1 - The probability that none none is defective

P(D) = 1 - P(N) ........1

For 20 selections; r = 20

-- 20 cards are selected from the lot without replacement for functional testing

The probability that none none is defective is;

P(N) = (xPr)/(tPr)

P(N) = (120P20)/(140P20)

P(N) = (120!/(120-20)!)/(140!/(140-20)!)

P(N) = (120!/100!)/(140!/120!) = 0.035618370821

P(N) = 0.0356

The probability that at least one defective card appears in the sample is;

P(D) = 1 - P(N) = 1 - 0.0356 = 0.9644

P(D) = 0.9644 or 96.44%

Note: xPr = x permutation r

Answer:

Option 4: at the vertices of the feasible region.

I completed the quiz

Answer:

at the vertices of the feasible region

Step-by-step explanation:

this is the correct answer

hope i helped

Answer:

D

Step-by-step explanation:

shifting 4 units to the right means that the new root = old root + 4

what that means is that the equation must have a transformation such that it equates to 0 with the root being 4 larger.

the root/vertex for x^4 is at x=0

we want the root to be at x=4

so that means we can subtract 4 from x

and get (x-4)^4

Answer:

Chicken: 36%

Beef: 34%

Black Bean: 30%

Hope this helps!

Answer:

There is a probability of 86.6% that the sample mean falls within 0.03 percent of the raw purity mean.

Step-by-step explanation:

We have a population standard deviation of σ ≈ 0.1.

We have a sample of size n=25.

Then, we have a sampling distribution, which has a standard deviation for the sample mean that is:

[tex]\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{0.1}{\sqrt{25}}=\dfrac{0.1}{5}=0.02[/tex]

Now, we can calculate a z-score for a deviation of 0.03 percent from the mean as:

[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{0.03}{0.02}=\dfrac{0.03}{0.02}=1.5[/tex]

Note: we considered that the margin is ±0.03.

Then, the probability is:

[tex]P(|X-\mu|<0.03\%)=P(|z|<1.5)=0.866[/tex]

Answer:

(a) Probability distribution is prepared below.

(b) The probability that two or fewer heads are observed in three tosses is 0.875.

(c) The probability that at least one head is observed in three tosses is 0.875.

(d) The expected value of X is 1.5.

(e) The standard deviation of X is 2.121.

Step-by-step explanation:

The complete question is: A fair coin is tossed three times. Let X be the number of heads observed in three tosses of this fair coin.

(a) Find the probability distribution of X.

(b) Find the probability that two or fewer heads are observed in three tosses. (Round your answer to three decimal places.)

(c) Find the probability that at least one head is observed in three tosses. (Round your answer to three decimal places.)

(d) Find the expected value of X. (Round your answer to one decimal place.)

(e) Find the standard deviation of X. (Round your answer to three decimal places.)

Now, firstly the sample space obtained in three tosses of a fair coin is given as;

Sample Space (S) = {HHH, HHT, HTH, THH, HTT, TTH, THT, TTT}

(a) The Probability distribution of X is given below;

   Number of Heads (X)         P(X)            [tex]X \times P(X)[/tex]               [tex]X^{2} \times P(X)[/tex]

              0                               [tex]\frac{1}{8}[/tex] = 0.125            0                           0

              1                                [tex]\frac{3}{8}[/tex] = 0.375         0.375                     0.375  

              2                               [tex]\frac{3}{8}[/tex] = 0.375         0.75                          3

              3                               [tex]\frac{1}{8}[/tex] = 0.125          0.375                    3.375

           Total                                                    1.5                        6.75          

(b) The probability that two or fewer heads are observed in three tosses is given by = P(X [tex]\leq[/tex] 2)

      P(X [tex]\leq[/tex] 2) = P(X = 0) + P(X = 1) + P(X = 2)

                     = 0.125 + 0.375 + 0.375

                     = 0.875

(c) The probability that at least one head is observed in three tosses is given by = P(X [tex]\geq[/tex] 1)

      P(X [tex]\geq[/tex] 1) =  1 - P(X = 0)

                    =  1 - 0.125

                    =  0.875

(d) The expected value of X = E(X) =  [tex]\sum (X \times P(X))[/tex]

                                                              =  1.5

(e) The Variance of X = V(X) = [tex]E(X^{2} ) - ( E(X))^{2}[/tex]

                                      =  [tex]\sum (X^{2} \times P(X))- (\sum (X \times P(X)))^{2}[/tex]

                                      =  [tex]6.75 - 1.5^{2}[/tex]  = 4.5

Now, Standard deviation of X = [tex]\sqrt{V(X)}[/tex]

                                                  = [tex]\sqrt{4.5}[/tex]  = 2.121.

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: μ = 904

For the alternative hypothesis,

Ha: μ < 904

This is a left tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 10,

Degrees of freedom, df = n - 1 = 10 - 1 = 9

t = (x - µ)/(s/√n)

Where

x = sample mean = 805

µ = population mean = 904

s = samples standard deviation = 158

t = (805 - 904)/(158/√10) = - 1.98

We would determine the p value using the t test calculator. It becomes

p = 0.039

Since alpha, 0.05 > than the p value, 0.03953, then we would reject the null hypothesis. Therefore, the correct option is:

2. P-value 0.039, there is sufficient evidence to conclude the mean lifetime of its SuperGlo light bulbs is less than 904 hours.

Answer:

41-60 => 5

Step-by-step explanation:

41-50 => 2

51-60 => 3

So 2+3 =5

Answer:

5

Step-by-step explanation:

Add up the number of children between 41 and 60

41-50: 2

51-60: 3

------------

total 5

Answer:

[tex]\sqrt{17}[/tex] or ≈4.12

Step-by-step explanation:

Use the distance formula

d= √(x₂ - x₁) ² + (y₂-y₁) ²

d= √(4-0)² + (1-0)²

d= √16 + 1

d= √17

Answer:

[tex]1[/tex]

Step-by-step explanation:

Universal set contains all elements and of which all other sets are subsets.

The number of race times recorded as portrayed by the number of data points is seven(7).

From the task content;

Additionally, it follows from the task content that the times recorded were; 6.8,7.3,7.1 ,7.0,7.2,7.3 and 7.0.

On this note, the number of race times recorded as portrayed by the number of data points is seven(7).

Read more on data points;

https://brainly.com/question/3514929