What is the lengthening of a muscle without damage? And what is the shortening of a muscle?

Answers

Answer 1

Answer:

Stretching is the lengthening and contraction is the shortening

Explanation:

Unless it's asking for eccentric as the stretching and concentric as the shortening


Related Questions

True or false. Law of action/reaction: for every action there is an equal and the same reaction. Pls don’t give me a link and tell me the answe

Answers

false. for every action there is a reaction equal in magnitude and opposite in direction
False cuz for every action there is a equal reaction in magnitude/ oppisiye direction

What is orbit? A. An increase in centripetal motion and mass friction. B. Resistance of an object to avoid friction. C. Gravity causing a curved path as an object tries to go straight. D. How well an object floats.

Answers

Answer:

C. gravity causing a curved path as an object tries to go straight.

What is the speed of sound in dry air at 20°C?

Answers

343 meters per second

Many bones get their name from the bone they are

Answers

What? What do you mean here?

The elemental composition of propane gas (C3H8) is 81.68% C and 18.32% H by mass. What is the maximum amount of C3H8 in grams that can be formed from 160.0 g C and 160.0 g H

Answers

Molar mass of C3H8 = C 3 (12.01 g/mol) = 36.03 (g/mol)

H 8 (1.008 g/mol) = 8.064 (g/mol)

44.09 (g/mol)

74.6 g propane x 1 mole propane x 6.022 x 10

23

molecules

44.09 g propane 1 mole propane

= 1.02 x 10

24 molecules propane

A balloon is filled
with 35.0 L of
helium when the
temperature is
200K. If the tem-
perature rises to
450K, what is the
new volume of the
balloon?

Answers

Answer:

78.75L

Explanation:

According to Charle's Law:

V1/T1=V2/T2

35/200=V2/450

V2=(35*450)200

V2=78.75L

When NH3(g) reacts with O2(g) to form N2O(g) and H2O(l), 342 kJ of energy are evolved for each mole of NH3(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer: [tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

Explanation:

The skeletal thermochemical equation for the reaction is:

[tex]NH_3(g)+O_2(g)\rightarrow N_2O(g)+H_2O(l)+342kJ[/tex]

The balanced  thermochemical equation for the reaction is:

[tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

When 1 mole of [tex]NH_3[/tex] reacts with oxygen , heat released = 342 kJ

Thus when 2 moles of [tex]NH_3[/tex] reacts with oxygen , heat released = [tex]\frac{2}{1}\times 342 kJ=684kJ[/tex]

Help meee??
HNO 3 is an example of Select one :
Triprotic Acid
O Diprotic Acid
O Monoprotic Acid
Tetraprotic Acid​

Answers

Answer: Monoprotic Acid

what is the mass concentration in ppm of NaCl of 0.01% mass/mass

A-10
B-100
C-10^3
D-10^4
E-10^5

Answers

Answer:

B-100

Explanation:

ppm is an unit of concentration that could be defined as the mass in mg of solute (In this case, NaCl) per kg of solution.

Now, a solution of NaCl that is 0.01% by mass, contains 0.01g of NaCl in 100g of solution.

To solve this question, we must convert the mass of NaCl to mg and the mass of solution to kg:

Mass NaCl:

0.01g * (1000mg / 1g) = 10mg

Mass Solution:

100g * (1kg / 1000g) = 0.10kg

The ppm are:

10mg / 0.10kg =

100ppm

Right answer is:

B-100

The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: In the analysis of a 1.54-g sample, 0.0596 g of barium iodate was recovered. Express the results of this analysis as percent potassium iodide.

Answers

Answer: The percentage of potassium iodide in the sample is 2.63 %.

Explanation:

The chemical equation for the reaction of iodide ions with bromine gas follows:

[tex]I^-+3Br_2+3H_2O\rightarrow 6Br^-+IO_3^-+6H^+[/tex]                (i)

The chemical equation for the reaction of iodate ions with barium ions follows:

[tex]Ba^{2+}+2IO_3^-\rightarrow Ba(IO_3)_2[/tex]                 ......(ii)

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of barium iodate = 0.0596 g

Molar mass of barium iodate = 487.13 g/mol

Using equation 1:

[tex]\text{Moles of barium iodate}=\frac{0.0596 g}{487.13 g/mol}\\\\\text{Moles of barium iodate}=1.22\times 10^{-4} moles[/tex]

By Stoichiometry of the reaction (ii):

1 mole of barium iodate is produced by 2 moles of iodate ions

So, [tex]1.22\times 10^{-4} moles[/tex] of barium iodate will be produced by [tex]\frac{2}{1}\times 1.22\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodate ions

By the stoichiometry of the reaction (i):

1 mole of iodate ions are produced by 1 moles of iodine ions

So, [tex]2.44\times 10^{-4} moles[/tex] of iodate ions will be produced by [tex]\frac{1}{1}\times 2.44\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodine ions

Moles of potassium iodide = Moles of iodide ions = [tex]2.44\times 10^{-4}[/tex]

Since, the molar mass of potassium iodide = 166 g/mol

Using equation 1:

[tex]\text{Mass of potassium iodide}=2.44\times 10^{-4}mol\times 166 g/mol\\\\\text{Mass of potassium iodide}=0.0405 g[/tex]

To calculate the percentage by mass of a substance, the equation used is:

[tex]\text{Percent by mass}=\frac{\text{Mass of a substance}}{\text{Mass of solution}}\times 100[/tex]

Mass of a solution = 1.54 g

Mass of potassium iodide = 0.0405 g

Using above equation:

[tex]\text{Percent potassium iodide}=\frac{0.0405 g}{1.54g}\times 100\\\\\text{Percent potassium iodide}=2.63\%[/tex]

Hence, the percentage of potassium iodide in the sample is 2.63 %.

Expressing the results of potassium iodide in percentage = 2.63%

The chemical reaction of iodine ions with Bromine gas can be expressed as :

I⁻  + 3Br₂  + 3H₂O  -- > 6Br⁻ + IO₃ + 6H⁺ ----- ( 1 )

Chemical reaction between iodate ions with barium ions  can be expressed as :  Ba²⁺  + 2IO⁻₃ ------> Ba ( IO₃ )₂   --------- ( 2 )

Step 1 : Calculate the number of Barium iodate moles

mass of Barium iodate = 0.0596 g

molar mass of Barium iodate = 487.13 g/mol

from equation ( 1 )

moles of Barium iodate = ( 0.0596 ) / ( 487.13 ) = 1.22 * 10⁻⁴ moles

also from equation ( 1 ) the moles of potassium iodide = moles of iodide ions

= 2.44 * 10⁻⁴

molar mass of potassium iodide = 166 g/mol

Next step : Determine the mass of potassium iodide

moles of potassium * molar mass

= 2.44 * 10⁻⁴  * 166 g/mol  = 0.0405 g

Final step : Determine the percentage of potassium iodide in the solution

Percentage = ( mass of potassium iodide / mass of solution ) * 100

                   = ( 0.0405 / 1.54 ) * 100

                   = 2.63%

Hence we can conclude that potassium iodide in percentage = 2.63%

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Select the valid ways to make an ammonia/ammonium buffer for use in the laboratory. Mix equal volumes of 1 M NH3 and 0.01 M NH 4. Mix some volume of 1 M NH3 with half as much 1 M HCl. Mix equal volumes of 1 M NH3 and 1 M NH 4. Mix equal volumes of 1 M NH3 and 1 M HCl.

Answers

Answer:

The answer is "Option b and Option c".

Explanation:

This buffer is a buffer of ammonia and ammonium ion. Thus it requires the solution [tex]NH_3 \ \ and \ \ NH_4^{+}[/tex].

In point 1:

The solution containing [tex]NH_3 \ \ and \ \ NH_4^{+}[/tex] at 1M concentration would be given by mixing the two solutions. Thus, this buffer is a legitimate route.

In point 2:

It gives the ions you want but they are not the same.

In point 3:

[tex]1 M[/tex] [tex]NH_3[/tex] and [tex]1 M[/tex][tex]HCl[/tex] volume would not produce the same [tex]NH_3 \ \ and \ \ NH_4^{+}[/tex] concentrations. Therefore, this buffer isn't a valid route.

In point 4:

Some [tex]1 M[/tex] [tex]NH_3[/tex] volume and half [tex]HCl[/tex] . This offers the same rate as half.

What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains of A1 and A2 relative to the training dataset For A3, which is a continuous attribute, compute the information gain for every possible split. C. What is the best split (among A1,A2, and A3) according to the information gain

Answers

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

[tex]$P(+) = \frac{4}{9}$[/tex]   and

[tex]$P(-) = \frac{5}{9}$[/tex]

The entropy of the training examples is given by :

[tex]$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$[/tex]

= 0.9911

b). For the attribute all the associating increments and the probability are :

  [tex]$a_1$[/tex]   +   -

  T   3    1

  F    1    4

Th entropy for   [tex]$a_1$[/tex]  is given by :

[tex]$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$[/tex]

= 0.7616

Therefore, the information gain for [tex]$a_1$[/tex]  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute [tex]$a_2$[/tex]  the associating counts and the probabilities are :

  [tex]$a_2$[/tex]  +   -

  T   2    3

  F   2    2

Th entropy for   [tex]$a_2$[/tex] is given by :

[tex]$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$[/tex]

= 0.9839

Therefore, the information gain for [tex]$a_2$[/tex] is

  0.9911 - 0.9839 = 0.0072

[tex]$a_3$[/tex]     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for [tex]$a_3$[/tex]  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that [tex]$a_1$[/tex] produces the best split.

Why is SpaceX likely to succeed in a mission to Mars?
A. It only hires expert NASA employees as its employees.
B. It takes more risks than NASA, which cannot afford them.
C. It is run by Elon Musk, who is determined to get to Mars.
D. It has fewer restrictions than NASA does.

Answers

Answer:

C

Explanation:

It is run by Elon Musk, who is determined to get to Mars.

All chemical reactions use reactants in a specific proportion or stoichiometry to regulate the amount of products produced. The __________ reactant is consumed completely during the reaction but some of the __________ reactant is left over.
a. limiting, excess
b. excess, limiting
c. proportional, ideal
d. chemical, stoichiometric

Answers

Answer: The answer is a. limiting, excess. I took the test.

Explanation:

Atoms in the same GROUP have the same...

A . Size
B. Temperature
C. Number of energy levels
D. Reactivity

Answers

Answer:

reactivity

Explanation:

for example atoms in group 7 react by gaining 1 electron to become stable but they do not have the same number of energy levels


20 points!

Which two structures produce energy that cells can
use?

A and B

B and C

C and D


D and A

Answers

Answer:

c and d

Explanation:

mitochondria and vacoule

Answer:

It is actually D and A

Explanation:

I took this assignment before on edge and the guy who said C and D is wrong

Which oficial the following organisms si not an autotroph

A. mushroom
B. grass
C. tree
D. moss​

Answers

Answer:

A. mushroom

Explanation:

Maybe option A because mushrooms ain't makes their food.


What is the molarity of the resulting solution when 300. mL of a 0.400 M solution is diluted to 800.
mL?

Answers

Answer:

0.150M

Explanation:

hope it helps!!!!!!!!!!!!

The molarity of the resulting solution when 300. mL of a 0.400 M solution is diluted to 800 mL is 0.15M.

Molarity is defined as the ratio of the number of moles of solute present in a solution, to the volume of that particular solution in litres.

It is calculated by using the formula

M₁V₁ = M₂V₂

M₁= initial molarity of the solution

V₁ = initial volume of the solution

M₂ = final molarity of the solution

V₂ = final volume of the solution

Given data,

M₁ = 0.400 M (initial molarity)

V₁ = 300 mL (initial volume)

V₂ = 800 mL (final volume)

Substituting the values we get

M₁V₁ = M₂V₂

.4× 300/800 = M₂

Therefore, molarity of the resulting solution = .15

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which of the following, when dissolved in water, forms a weak acid.A. HNO3B. HClO4C. HBrD. HClOE. NH3

Answers

Answer:

The weak acid is - E. [tex]NH_3[/tex]

Explanation:

Ammonia is a strong base, which in turn make it to be a weak acid.

As, the rest of the options are acid and therefore furnish hydrogen ions when dissolved in water, making them strong acid.

And ammonia dissolves in water to form its conjugate ammonium ion and hydroxide ion, therefore making the solution basic.

Hence, from the given options, the correct option is E. [tex]NH_3[/tex]

The compound which when dissolved in water, forms a weak acid is; Choice E: NH3

According to the question;

we are required to determine which compound forms a weak acid when dissolved in water.

Unlike other compounds (HNO3, HClO, HBr, HClO) which dissolve in water to yield H+ ion, Ammonia dissolves in water to form ammonium ion and hydroxide ion, OH-.

In essence, NH3 is a strong base when dissolved in water and consequently, is a weak acid when dissolved in water.

Read more:

https://brainly.com/question/15192126

You rub a comb on your hair and then the comb is able to pick up pieces of paper. Explain why this happens​

Answers

Answer:

This happened because,the comb was charged with static electricity when it was rubbed on your hair.

(¬_¬)ノ( ˘ ³˘)♥

How did the industrial Revolution impact the population of peppered moths in Britain?

The Industrial Revolution caused the proportions of each color morph in the population to become equal.

The light-colored moths became more common

The dark-colored moths became more common

The Industrial Revolution caused the proportions of each color morph in the population to become unequal

Answers

Answer:

due to the pollution the light months tended to stand out against the the wood that was dark due to the smoke the darker months population grew due to the fact that they were more harder to see for the predators

Answer:

The dark colored months became more common

Explanation:

Thats the answer !

What do the symbols in the parentheses indicate

Answers

Answer:

(C) the physical state of each reactant and product

Explanation:

Hope this helps

How many grams are in 3.0 moles of sodium chloride (NaCl)?

Answers

Answer:

175.5

Explanation:

What is the percent yield of water from the combustion of propane (C3H8), if my theoretical yield is 8.17g of water and my actual yield was 6.13 g water?

A)Answer not shown

B)0.75%

C)75%

D)1.33%

Answers

Answer:

im not sure

Explanation:

i went on here looking nobody answered yet

Potential and kinetic energy are similar in that -
COME ON BESTIES I NEED HELP​

Answers

Answer:

They refer to energy that moves. Kinetic energy is energy that is currently moving. Potential refers to energy that has yet to move, or simply energy in wait

Explanation:

Answer:

I'm not 100% but a possible answer could be: No energy could either be created or destroyed

LMK if not but good luck!

The trait that shows up in the first generation.
Recessive
Dominant
Ok

Answers

Answer:

Dominant

Explanation:

hope this help

How many protons are in nitrogen

Answers

Answer:

Explanation:

There are 7 protons in nitrogen

7 TYPE OF NITRONGEN

. . .

How many molecules of O2 will be formed from 0.500 grams of KCIO3

Answers

Answer:

3.7 x 10²¹ O₂ molecules

Explanation:

2KClO₃ => 2KCl + 3O₂

given 0.500g KClO₃ => 0.500g/122.55g/mol = 0.0041 mole KClO₃

0.0041 mole KClO₃ => 3/2(0.0041) mole O₂ = 0.0061 mole O₂

0.0061 mole O₂ = 0.0061 mole O₂ x 6.02 x 10²³ molecules O₂/mole O₂

= 3.7 x 10²¹ molecules O₂

HELP QUICK!!!!!!
How many valence electrons do the atoms in Group 13 have?

Answers

Answer:

The answer is 3 valance electrons.

Explanation:

Hope this helped Mark BRAINLIEST!!!

Answer:

3 valence electrons

Explanation:

The atoms in group 13 have three valence electrons.


Which equation is an example of a redox reaction?

A. Ca(OH)2 + H2SO3 + 2H20 + CaSO3

B. HCI + KOH + KCI + H20

C. 2K+ CaBr +2KBr + Ca

D. BaCl2 + Na2SO4 + 2NaCl + BaSO4

Answers

Answer:

The answer is C.

Explanation:

A P E X approved :)

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