URGENT!!! A factory process requires 3 steps to finish a product. The steps each have a mean completion time of A= 10 seconds and a standard deviation of o = 5 seconds. The time it takes to complete each step is independent from the other steps. Let T be the total completion time for the 3 steps.

Find the standard deviation of T.

Choose 1 answer:

OT = 15 seconds

Or = 75 seconds

or 15 seconds

or = v75 seconds

Answers

Answer 1

Answer:

d

Step-by-step explanation:

Answer 2

The standard deviation of T is equivalent to 5.

What is standard deviation?In statistics, the standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean (also called the expected value) of the set, while a high standard deviation indicates that the values are spread out over a wider range.Mathematically, we can write -

       [tex]$\sigma={\sqrt {\frac {\sum(x_{i}-{\mu})^{2}}{N}}}[/tex]

Given is that a factory process requires 3 steps to finish a product. The steps each have a mean completion time of A = 10 seconds and a standard deviation of O = 5 seconds. The time it takes to complete each step is independent from the other steps.

We can write that -

5 = √∑(x{i} - 10)²/√3

√∑(x{i} - 10)² = 5√3

(√∑(x{i} - 10)²)² = (5√3)²

∑(x{i} - 10)² = 25 x 3

∑(x{i} - 10)² = 75

Now, we can write that -

σ = √(75/3)

σ = √25

σ = 5

Therefore, the standard deviation of T is equivalent to 5.

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That triangle is isosceles, so the bottom two angles will always be equal. With that said, the equation will be 2(65), and that equals 130. After that, subtract 180-130, and that gives you x! In total, your calculations should look like this:
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Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}} : [/tex]

[tex] \angle \: ABC = 65 \degree[/tex]

[tex] \underline{ \underline{ \text{To \: Find}}} : [/tex]

Value of x

[tex] \underline{ \underline { \text{Solution}}} : [/tex]

[tex] \angle \: ACB = \angle \: ABC = 65 \degree[/tex] [ Base angles of isosceles triangle are equal ]

[tex] x \degree + 65 \degree + 65 \degree = 180 \degree[/tex] [ Sum of angle of a triangle ]

⟼ [tex] x \degree + 130 \degree = 180 \degree[/tex]

⟼ [tex] x \degree = 180 \degree - 130 \degree[/tex]

⟼ [tex] x = 50 \degree[/tex]

[tex] \red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline{ \tt{x = 50 \degree}}}}}}}[/tex]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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How is this number read?

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A. eighteen seventy-three
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Answers

Answer:

the answer is d to the qu5

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The answer is c

Step-by-step explanation:

I took the quiz on K12

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Answers

B- at the same point. 3/9 simplified would be 1/3....

In comparison to 1/3 to 3/9, both numbers are located at the same point on a number line.

What is a number line?

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

It is given that:

In comparison 1/3 to where would 3/9 be located on a number line

As we know, a number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.

1/3 = 0.333

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If we plot the above fractions on a number line we will see these two fractions are on the same point.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

Thus, in comparison to 1/3 to 3/9, both numbers are located at the same point on a number line.

Learn more about the number line here:

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Answers

Answer:

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Step-by-step explanation:

Suppose Juan bought a total of [tex]x[/tex] tickets. Then Alex bought 65 more, which is [tex]x+65[/tex]. The sum of both totals is [tex](x)+(x+65) = 2x + 65[/tex], but we are also given that this is equal to 343. So [tex]2x+65 = 343[/tex], and as such [tex]2x = 343-65=278[/tex], so [tex]x = \frac{278}{2} = 139[/tex]. Therefore, Juan bought 139 tickets and Alex bought 65 more, which is 204.

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Answer:

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Step-by-step explanation:

In each case, we can use the relation that the length of an arc (s) is found by ...

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__

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__

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__

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Answers

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