The perimeter of the rectangle is below 76 units. Find the length of side AD. AB on rectangle 3y + 3 CB 2y

The Perimeter Of The Rectangle Is Below 76 Units. Find The Length Of Side AD. AB On Rectangle 3y + 3

Answers

Answer 1

Answer:

14 units

Step-by-step explanation:

The perimeter of a figure is the sum of the lengths of all the sides.

Here, we know that ABCD is a rectangle, so by definition, AB = CD and AD = BC. We also are given that AB = 3y + 3 and BC = 2y, which means that:

AB = CD = 3y + 3

AD = BC = 2y

Adding up all the side lengths and setting that equal to the perimeter, which is 76 units, we get the expression:

AB + CD + AD + BC = 76

(3y + 3) + (3y + 3) + 2y + 2y = 76

10y + 6 = 76

10y = 70

y = 7

We want to know the length of AD, which is written as 2y. Substitute 7 in for y:

AD = 2y = 2 * 7 = 14

The answer is thus 14 units.

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Answer 2

Answer:

14

Step-by-step explanation:

The perimeter of a rectangle is found by

P = 2 (l+w)

P = 2( 3y+3+2y)

Combine like terms

P = 2(5y+3)

We know the perimeter is 76

76 = 2(5y+3)

Divide each side by 2

76/2 = 2/2(5y+3)

38 = 5y+3

Subtract 3 from each side

38-3 = 5y+3-3

35 = 5y

Divide each side by 5

35/5 = 5y/5

7 =y

We want the length of AD = BC = 2y

AD = 2y=2*y = 14


Related Questions

Solve for in the diagram below.

Answers

Answer:

x = 20

Step-by-step explanation:

The sum of the three angles in the diagram is 180 degrees since they form a straight line

x + 100 + 3x = 180

Combine like terms

100 +4x = 180

Subtract 100 from each side

100+4x-100 =180-100

4x= 80

Divide each side by 4

4x/4 = 80/4

x = 20

The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs at minimum number of swimmers to sign up in order to be cost effective. Last year's data showed that during 8 swim sessions the average number of entry-level swimmers attending was 15. Suppose the instructor wants to conduct a hypothesis test. The alternative hypothesis for this hypothesis test is: "the population mean is less than 15". The sample size is 8, LaTeX: \sigmaσ is known, and alpha =.05, the critical value of z is _______. Group of answer choices

Answers

Answer:

The signficance level is 0.05 and then based in the alternative hypothesis we can find a critical value who accumulates 0.05 of the area in the normal standard curve in the left and we got:

[tex] z_{\alpha/2}= -1.64[/tex]

Step-by-step explanation:

[tex]n=8[/tex] the same size given

[te]\sigma[/tex] the population deviation is known

For this case we want to test if the population mean is less than 15 and that represent the alternative hypothesis and the complement would be the null hypothesis. So then the system of hypothesis are:

Null hypothesis: [tex]\mu \geq 15[/tex]

Alternative hypothesis:  [tex]\mu <15[/tex]

The signficance level is 0.05 and then based in the alternative hypothesis we can find a critical value who accumulates 0.05 of the area in the normal standard curve in the left and we got:

[tex] z_{\alpha/2}= -1.64[/tex]

Gary buys a 3 1/2 pound bag of dog food every 3 weeks. Gary feeds his dog the same amount of food each day. Which expression can Gary use to determine the number of pounds of dog food his dog eats each year?

Answers

Answer:

7/2 x 52/3

Step-by-step explanation:

Steps:

Since 1 year = 52 weeks

52*7/2*3= 7/2*52/3

Since 1 year equal 52 weeks meaning we have to times 52 by 7/2 then times by 3 the weeks. The answer is below.

Answer: 7/2 x 52/3

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Hope this helps.

The total energy need during pregnancy is normally distributed, with a mean of 2600 kcal/day and a standard deviation of 50 kcal/day. Include your Normal curve for all parts! a) [4 pts] If one pregnancy is randomly selected, find the probability that the total energy need is more than 2650 kcal/day. b) [4 pts] The middle 30% of total energy need during pregnancy are between what values? c) [4 pts] What is the probability that a random sample of 20 pregnant women has a mean energy need of more than 2625 kcal/day?

Answers

Answer:

a) 0.3085

b) 2574

c) 0.0125

Step-by-step explanation:

mean (μ) = 2600 kcal/day and a standard deviation (σ) = 50 kcal/day

a) The z score is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

[tex]z=\frac{x-\mu}{\sigma}=\frac{2650-2600}{50}=1[/tex]

From the normal distribution table, P(x > 2650) = P(z > 1) = 1 - P(z < 1) = 1 - 0.8413 = 0.1587

b) A probability of 30% corresponds with a z score of -0.52

[tex]z=\frac{x-\mu}{\sigma}\\-0.52=\frac{x-2600}{50} \\x-2600=-26\\x=2600-26\\x=2574[/tex]

c) For a sampling distribution of sample mean, the standard deviation is [tex]\frac{\sigma}{\sqrt{n} }[/tex]

The z score is given by:

[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} }}[/tex]

n = 20

[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} }}=\frac{2625-2600}{\frac{50}{\sqrt{20} }}=2.24[/tex]

From the normal distribution table, P(x > 2625) = P(z > 2.24) = 1 - P(z < 2.24) = 1 - 0.9875 = 0.0125

Find the area of the circle

Answers

Answer:

615.44

Step-by-step explanation:

The area in terms of π is 196π

196 * 3.14 = 615.44

Answer:

615.75

Step-by-step explanation:

Area equals pi times r times 2

A equals 3.14 times 14 times 2

Find the area of the triangle

Answers

Answer:

Step-by-step explanation:

The formula for the area of a triangle is base*height divided by 2. Remember this because itll be important for everything you do in math relating to geometry and calculus. Assuming you go that far

[tex]\frac{base*height}{2} =\frac{14*8}{2} =\frac{112}{2} = 56 units^2[/tex]

Answer:

A =56 units^2

Step-by-step explanation:

The area of a triangle is given by

A =1/2 bh where 14 is the base and 8 is the height

A = 1/2 (14)8

A =56 units^2

5/2 = 11/x
What is x

Answers

Answer:

X=22/5

Step-by-step explanation:

By cross multiplication

5/2 =11/x

5x = 2(11)

5x =22

X=22/5

Hope this helps..

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