The hypotnuse of a right triangle is three times the length of its first leg. Theblength of the other leg is four feet. Find the lengths of the first leg and the hypotnduse and enter them in the below squares in this order. For non-integer answer(s), round your answer(s) to the nearest tenth.

Answer:

x=3

Step-by-step explanation:

We want to find the value of x where the two graphs intersect

The graphs intersect at ( 3,8)

The value of x is 3

Answer:

11/35

Step-by-step explanation:

Answer:

The height of the tower is:

24 meters

Step-by-step explanation:

1 meter = 100 centimeters

10 centimeters = 10/100 = 0.1 meters

8 centimeters = 8/100 = 0.08 meters

On a three rule:

0.1 meters is to 0.08 meters

30 meters is to A meters

A = 30*0.08/0.1

A = 24 meters

Related task:

https://brainly.lat/tarea/14821170

Answer:

(-15,3)

Step-by-step explanation:

Answer:

No, Beth is not correct. The function g(x) has an h value of 5 and a k value of 1. This would be a horizontal translation of the square root function of 5 units to the right, rather than the left. Beth was correct about the vertical translation of the square root function of 1 unit up. The point (0, 0) from the square root function would be translated to the point (5, 1) on the graph of g(x).

Step-by-step explanation:

This came right from Edg

Answer:

x(x^2 + x + 1)

Step-by-step explanation:

x^3 + x^2 + x = x(x^2 + x + 1)

Answer:

53 degrees

Step-by-step explanation:

Complementary angles add to 90 degrees

a+b = 90

a=37

37+b = 90

Subtract 37 from each side

37+b-37 = 90-37

b =53

Answer: 53 degrees

Step-by-step explanation: We can find the measure of <b by taking 90 minus the measure of <a which is 90 - 37 or 53 degrees.

Answer:

D, or the last option.

Step-by-step explanation:

See how the rotation does not say whether it is Clockwise or Counterclockwise?

Now, what that means, is that it will, default, be CCW. I don't know why, but math teachers are like that.

Now, 80* and 10* add up to 90* (because they are both unmarked and going to the same direction).

So, 90* rotation CCW. Simple! Thus, the last option should be correct.

Hope this helps!

P.S. Stay Safe!

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]

Cross multiply:

[tex] XY*sin(43) = 24*sin(67) [/tex]

[tex] XY*0.68 = 24*0.92 [/tex]

Divide both sides by 0.68 to solve for XY

[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]

[tex] XY = 32.47 [/tex]

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

Step-by-step explanation:

(a) Your computer may be programmed to allocate borderline cases to the

next group down, or the next group up; and it may or may not manage

to follow this rule consistently, depending on its handling of the numbers

involved. Following a rule which says 'move borderline cases to the next

group up', these are the five classifications.

(i) 1.0-1.2 1.2-1.4 1.4-1.6 1.6-1.8 1.8-2.0 2.0-2.2 2.2-2.4

6 6 4 8 4 3 4

2.4-2.6 2.6-2.8 2.8-3.0 3.0-3.2 3.2-3.4 3.4-3.6 3.6-3.8

6 3 2 2 0 1 1

(ii) 1.0-1.3 1.3-1.6 1.6-1.9 1.9-2.2 2.2-2.5

10 6 10 5 6

2.5-2.8 2.8-3.1 3.1-3.4 3.4-3.7

7 3 1 2

(iii) 0.8-1.1 1.1-1.4 1.4-1.7 1.7-2.0 2.0-2.3

2 10 6 10 7

2.3-2.6 2.6-2.9 2.9-3.2 3.2-3.5 3.5-3.8

6 4 3 1 1

(iv) 0.85-1.15 1.15-1.45 1.45-1.75 1.75-2.05 2.05-2.35

4 9 8 9 5

2.35-2.65 2.65-2.95 2.95-3.25 3.25-3.55 3.55-3.85

7 3 3 1 1

(V) 0.9-1.2 1.2-1.5 1.5-1.8 1.8-2.1 2.1-2.4

6 7 11 7 4

2.4-2.7 2.7-3.0 3.0-3.3 3.3-3.6 3.6-3.9

7 4 2 1 1

(b) Computer graphics: the diagrams are shown in Figures 1.9 to 1.11

Answer:

George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today

Step-by-step explanation:

Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.

Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.

Mathematically;

time = distance/speed

He walks 1 mile at 3 miles per hour.

Thus, the total amount of time he spend each normal day would be;

time = 1/3 hour or 20 minutes

Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.

Let the unknown speed be x miles/hour

Mathematically;

We shall be using the formula for time by dividing the distance by the speed

1/3 = 1/2/(2) + 1/2/x

1/3 = 1/4 + 1/2x

1/2x = 1/3 - 1/4

1/2x = (4-3)/12

1/2x = 1/12

2x = 12

x = 12/2

x = 6 miles per hour

Answer:

20

Step-by-step explanation:

let the number be n then twice the number is 2n and half the number is [tex]\frac{1}{2}[/tex] n

Then the difference is

2n - [tex]\frac{1}{2}[/tex] n = 30 ( multiply through by 2 to clear the fraction )

4n - n = 60, that is

3n = 60 ( divide both sides by 3 )

n = 20

Answer:

Step-by-step explanation:

a) "Equilibrium" means the final temperatures of everything in the calorimeter are the same. The final temperature of the metal is the same as that of the water: 29.8C.

__

b) The temperature change of the water is ...

  final temp - initial temp = 29.8C -23.6C = 6.2C

__

c) The temperature change of the metal is ...

  final temp - initial temp = 29.8C -70.4C = -40.6C

Answer:

29.8C

6.2C

-40.6C

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the coordinates P(-2, -3). Q(2, - 6). R(6. - 3). S(2, 1), to determine the type of shape the quadrilateral is, we need to find the measure of the sides. To get the measure of each sides, we will take the distance between the adjacent coordinates using the formula to formula for calculating the distance between two points as shown;

D = √(x₂-x₁)²-(y₂-y₁)²

For the side PQ with the coordinate P(-2, -3). Q(2, - 6)

PQ = √(2-(-2))²-(-6-(-3))²

PQ = √(2+2)²-(-6+3)²

PQ = √4²-(-3)²

PQ = √16-9

PQ = √7

For the side QR with the coordinate Q(2, - 6) and R(6, -3)

QR = √(6-2))²-(-3-(-6))²

QR = √(4)²-(3)²

QR = √16-9

QR = √7

For the side RS with the coordinate R(6. - 3) and S(2, 1)

RS = √(2-6)²-(1-(-3))²

RS = √(-4)²-(1+3)²

RS = √16-(4)²

RS = √16-16

RS = 0

For the side PS with the coordinate P(-2, -3) and S(2, 1)

PS = √(2-(-2))²-(1-(-3))²

PS = √(4)²-(1+3)²

PS = √16-(4)²

PS = √16-16

PS = 0

For the quadrilateral to be a rectangle, then two of its sides must be equal and parallel to each other. A rectangle is a plane shape that has two of its adjacent sides equal and parallel to each other. Since two of he sides are equal i.e RS = PS and PQ = QR then the quadrilateral PQRS is a rectangle. Both rhombus and square has all of its sides equal thereby making them wrong.

Answer:

Step-by-step explanation:

i.

[tex] \frac{1}{3} [/tex] part of work can be done in 6 days.

Days taken to complete the whole work:

= 6 * 3

= 18 days

ii. Whole work will be done in 18 days.

So, 1 day work = [tex] \frac{1}{18} [/tex]

iii. Work done in 9 days :

[tex] \frac{1}{18} \times 9 [/tex]

[tex] = \frac{1}{2} [/tex]

So, remaining work :

[tex]1 - \frac{1}{2} [/tex]

[tex] = \frac{1 \times 2 - 1}{2} [/tex]

[tex] = \frac{2 - 1}{2} [/tex]

[tex] = \frac{1}{2} [/tex] part of work

Hope this helps...

Good luck on your assignment..

Answer:

(1)C- Trapezoid

(2)D-20 square feet

Step-by-step explanation:

Question 1

A cross-section of a rectangular pyramid cut perpendicular to the base but not passing through the top will have two parallel sides where one of the sides will be longer. Therefore, the shape which describes the cross-section will be a trapezoid.

Question 2

The base of the Triangle = 5 feet

Height of the Triangle = 8 feet

[tex]\text{Area of a triangle}=\dfrac12 \times $Base \times Height\\=\dfrac12 \times 5 \times 8\\=20 ft^2[/tex]

Answer:

????

Step-by-step explanation:

Where is the question????

Answer:

Hey there!

We must use what we are given, so even though it looks like there might be four isosceles triangles, we are only given CA=CE, so that only allows us to conclude mathematically that there is only 1 isosceles triangle.

Hope this helps :)

Answer:

d. will always be unbiased.

Step-by-step explanation:

When some of variables are omitted the estimator on indulge charge regressor may still be unbiased. If there is a special case where T = 2 then the FE estimator will be unbiased. Fixed effect regression model has different intercepts.

Answer:

30 s

Step-by-step explanation:

When the ball hits the ground h=0. To find the time t when this happens we must solve the equation h=0.

●h= 0

● -12t^2+360t =0

● t(-12t +360) = 0

● t = 0 or -12t +360 =0

● t=0 or -12t = -360

● t=0 or 12t =360

● t=0 or t=360/12

● t=0 or t= 30

The equation has two solutions.

The ball was fired with an initial speed of 800 feet per second so it cannot hit the ground at t=0.

So the ball hits the ground after 30 s.

Answer:

v = 10.997

Step-by-step explanation:

For this, simply use the law of cosines.

v^2 = (16)^2 + (6)^2 - 2(16)(6)cos(27)

v^2 = 256 + 36 - 171.073

v^2 = 120.927

v = 10.997

Cheers.

Answer:

Step-by-step explanation:

To solve the length of UW, you can use the Law of Cosines for a SAS case:

[tex]\boxed{v^2=\sqrt{u^2+w^2-2(uw)cos(V)} }[/tex]

Substitute the values and solve with a calculator:

[tex]\boxed{\sqrt{16^2+6^2-2(16*6)cos(27)} = 10.99666983 \approxeq 11}[/tex]

The length of UW is 11 units.

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be [tex]d(s) = 0.0056\cdot s^{2} + 0.14\cdot s[/tex], where [tex]d[/tex] is the stopping distance measured in metres and [tex]s[/tex] is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of [tex]d(s)[/tex].

2) Add the function [tex]d = 7\,m[/tex].

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

By the factor theorem, we have

[tex]x^2+5x+3=(x-p)(x-q)\implies\begin{cases}3=pq\\-5=p+q\end{cases}[/tex]

[tex]x^2+bx+c=(x-p^2)(x-q^2)\implies\begin{cases}c=p^2q^2\\-b=p^2+q^2\end{cases}[/tex]

Then

[tex]c=p^2q^2=(pq)^2=3^2=9[/tex]

and

[tex]p+q=-5\implies(p+q)^2=p^2+2pq+q^2=25\implies b=-(p^2+q^2)=-19[/tex]

So we have b + c = -19 + 9 = -10.

The given roots of the equation x² + 5x + 3 = 0 as p and q, and x² + bx + c = 0 as p² and q², gives us the value of b + c = -10.

If the quadratic equation ax² + bx + c = 0, has roots as α and β, then:

In the question, we are informed that the roots of the expression x² + 5x + 3 = 0 are p and q, and the roots of the expression x² + bx + c = 0 are p² and q².

We are asked to find the value of b + c.

Since the roots of the equation x² + 5x + 3 = 0 are given as p and q.

So, we can say that:

Now, we are informed that the roots of the equation x² + bx + c = 0 are p² and q². So, we can say that:

∴ b + c = -19 + 9 = -10.

∴ The given roots of the equation x² + 5x + 3 = 0 as p and q, and x² + bx + c = 0 as p² and q², gives us the value of b + c = -10.

Learn more about the sum and product of the roots of a quadratic equation at

https://brainly.com/question/10666510

#SPJ2

Answer:

(a) P(none) = 0.0488

(b) P(at least one) = 0.9512

(c) P(at most one) = 0.2186

(d) No, it doesn't appear that the 24% share value is wrong.

Step-by-step explanation:

We are given that among the TV sets in use, 24% were tuned to Lett3rs.

A pilot survey begins with 11 households have TV sets in use at the time of a Lett3rs broadcast.

Let X = Number of households that are tuned to Lett3rs

The above situation can be represented through binomial distribution;

[tex]P(X = r)=\binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......[/tex]

where, n = number of samples (trials) taken = 11 households

           r = number of success

           p = probability of success which in our question is % of  

                 households that were tuned to Lett3rs, i.e; 24%

So, X ~ Binom{n = 11, p = 0.24}

(a) The probability that none of the households are tuned to Lett3rs is given by = P(X = 0)

     P(X = 0) =  [tex]\binom{11}{0}\times 0.24^{0} \times (1-0.24)^{11-0}[/tex]

                   =  [tex]1\times 1 \times 0.76^{11}[/tex]

                   =  0.0488

(b) The probability that at least one households are tuned to Lett3rs is given by = P(X [tex]\geq[/tex] 1)

     P(X [tex]\geq[/tex] 1) = 1 - P(X = 0)

                   =  1 - 0.0488

                   =  0.9512

(b) The probability that at most one households are tuned to Lett3rs is given by = P(X [tex]\leq[/tex] 1)

     P(X [tex]\leq[/tex] 1) =  P(X = 0) + P(X = 1)

                   =  [tex]\binom{11}{0}\times 0.24^{0} \times (1-0.24)^{11-0}+\binom{11}{1}\times 0.24^{1} \times (1-0.24)^{11-1}[/tex]

                   =  [tex]1\times 1\times 0.76^{11}+11\times 0.24^{1} \times 0.76^{10}[/tex]

                   =  0.2186

No, it doesn't appear that the 24% share value is wrong because the probability that at most one household is tuned to Lett3rs is somewhere close to 24% and this probability is also not unusual as it is way more than the criteria of more than 5%.

Answer:

Ratio of sugar and flour

2:7

Ratio of milk and oil

3:1

Step-by-step explanation:

Here in this question, we shall be writing ratios based on the given number of cups in the question.

We start with ratio of sugar to flour.

We have;2 cups of sugar and 7 cups of flour. Thus we have the ratio of sugar to flour as 2:7

Also we want the ratio of milk and oil

we have 3 cups of milk and 1 cup of oil

So the ratio of milk and oil is 3:1

Answer: TO be short for it its B! :D

A cake mix calls for these ingredients.

2 cups of sugar

7 cups of flour

3 cups of milk

1 cup of oil

Write the ratios of sugar to flour and milk to oil. Which correctly compares the ratios?

3/7 > 2/1

2/7<3/1

7/1<2/3

3/2>1/7

2

SEE ANSWERS

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Answer

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jazminlowery

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5 answers

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2/7<3/1

with 2 cups of sugar to 7 cups of flour that is a small ratio/ fraction while as

3 cups of milk to 1 cup of oil is a larger ratio/fraction.

douwdek0 and 60 more users found this answer helpful

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Answer

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ColinJacobus

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3.7K answers

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Answer:  The correct option is (B).

The ratio of  sugar to flour is  and the ratio of milk to oil is

Step-by-step explanation:  Given that a cake mix calls for the following ingredients:

2 cups of sugar , 7 cups of flour , 3 cups of milk  and 1 cup of oil.

We are given to write the ratios of sugar to flour and milk to oil and select the correct comparison of the ratios.

The ratio of sugar to flour is given by

and the ratio of milk to oil is given by

Since

so have

Thus, the ratio of  sugar to flour is  and the ratio of milk to oil is  The correct comparison is

Option (B) is CORRECT.

Step-by-step explanation:

Answer: m-a+k+b

Step-by-step explanation:

m-(a-k-b)= m+-1*(a-k-b). Then, simply use distributive property to simplify the equation into m-a+k+b

Hope it helps <3

Answer:

[tex]x = -2[/tex] and [tex]y = \frac{5}{3}[/tex]

Step-by-step explanation:

Given

[tex]y = \frac{2}{3}x + 3[/tex]

[tex]x = -2[/tex]

Required

Determine the solution to the equations

From the second equation, we have the value of x already;

The next step is to substitute -2 for x in the first equation

[tex]y = \frac{2}{3}x + 3[/tex] becomes

[tex]y = \frac{2}{3}(-2) + 3[/tex]

[tex]y = \frac{-4}{3} + 3[/tex]

[tex]y = -\frac{4}{3} + 3[/tex]

Take LCM

[tex]y = \frac{-4 + 9}{3}[/tex]

[tex]y = \frac{5}{3}[/tex]

Hence,

[tex]x = -2[/tex] and [tex]y = \frac{5}{3}[/tex]

Answer:

[tex]x = 1.25[/tex]

[tex]y = 0[/tex]

Step-by-step explanation:

Given

[tex]4x - 5y = 5[/tex]

[tex]0.08x + 0.10y = 0.10[/tex]

Required

Determine the solution

Make x the subject of formula in: [tex]4x - 5y = 5[/tex]

[tex]4x = 5 + 5y[/tex]

Divide both sides by 4

[tex]\frac{4x}{4} = \frac{5 + 5y}{4}[/tex]

[tex]x = \frac{5 + 5y}{4}[/tex]

Substitute [tex]x = \frac{5 + 5y}{4}[/tex] in [tex]0.08x + 0.10y = 0.10[/tex]

[tex]0.08(\frac{5 + 5y}{4}) + 0.10y = 0.10[/tex]

Solve the fraction

[tex]0.02(5 + 5y) + 0.10y = 0.10[/tex]

Open the bracket

[tex]0.1 + 0.1y + 0.10y = 0.10[/tex]

[tex]0.1 + 0.2y = 0.10[/tex]

Subtract 0.1 from both sides

[tex]0.1-0.1 + 0.2y = 0.10 - 0.1[/tex]

[tex]0.2y = 0[/tex]

Divide both sides by 0.2

[tex]y =0[/tex]

Substitute 0 for y in [tex]x = \frac{5 + 5y}{4}[/tex]

[tex]x = \frac{5 + 5*0}{4}[/tex]

[tex]x = \frac{5 + 0}{4}[/tex]

[tex]x = \frac{5 }{4}[/tex]

[tex]x = 1.25[/tex]

Answer: 2 fl oz

Step-by-step explanation:

Division with remainders

128/6=21.33333..

[tex]21\cdot 6=126[/tex]

128-126=2

2 fl oz was left in the jug

Answer:

[tex] s = 14.1 [/tex]

Step-by-step explanation:

Find s using the Law of Cosines:

m < S = 31°

SR = q = 21

SQ = r = 9

QR = s = ?

Thus,

[tex] s^2 = r^2 + q^2 - 2(r)(q)*cos(S) [/tex]

[tex] s^2 = 9^2 + 21^2 - 2(9)(21)cos(31) [/tex]

[tex] s^2 = 81 + 441 - 378*0.8572 [/tex]

[tex] s^2 = 522 - 324.0216 [/tex]

[tex] s^2 = 197.9784 [/tex]

[tex] s = \sqrt{197.9784} [/tex]

[tex] s = 14.07 [/tex]

[tex] s = 14.1 [/tex] (to the nearest tenth)

Answer:

Step-by-step explanation:

The figure above is a quadrilateral

Angles in a quadrilateral add up to 360°

To find x add up all the angles and equate them to 360°

That's

6x + 4x + 3x + x + 10 = 360

14x = 350

Divide both sides by 14

x = 25°

Hope this helps you