The amount of time, in hours, that a computer functions before breakingdown is a continuous random variable with probability density functiongiven byfX(x) ={1100e−x/100x≥00x <0.What is the probability that1. a computer will function between 50 and 150 hours before breakingdown (3 pts)2. It will function less than 100 hours? (3 pts)3. It will function exactly 100 hours before breaking down? (3 pts)

Answers

Answer 1

Answer:

[tex]P(50 < x < 150) =0.3834[/tex]

[tex]P(x = 100) =0.0074[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \left \{ {{\frac{1}{100}e^{-x/100}\ x\ge 0} \atop {0\ x<0}} \right.[/tex]

Solving (a): Probability that it will function between 50 and 150 hr before it breaks down

This is represented as:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {f(x)} \, dx[/tex]

So, we have:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(50 < x < 150) =- e^{-x/100}|\limits^{150}_{50}[/tex]

This gives:

[tex]P(50 < x < 150) =- e^{-150/100} - - e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-150/100} + e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-1.5} + e^{-0.5}[/tex]

[tex]P(50 < x < 150) =- 0.2231 + 0.6065[/tex]

[tex]P(50 < x < 150) =0.3834[/tex]

Solving (a): Probability that it will function exactly 100 hr before it breaks down

This is represented as:

[tex]P(x= 100)[/tex]

This can be rewritten as:

[tex]P(x= 100) = P(99<x<101)[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {f(x)} \, dx[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(99 < x < 101) =- e^{-x/100}|\limits^{101}_{99}[/tex]

This gives:

[tex]P(99 < x < 101) =- e^{-101/100} - - e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-101/100} + e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-1.01} + e^{-0.99}[/tex]

[tex]P(99 < x < 101) =- 0.3642 + 0.3716[/tex]

[tex]P(99 < x < 101) =0.0074[/tex]

Hence:

[tex]P(x = 100) =P(99 < x < 101) =0.0074[/tex]


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Step-by-step explanation:

Let's define the variables:

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Explain steps.

Answers

Answer:

71 is 10% of 710

52 is 97% of 5200/97

Step-by-step explanation:

Let’s start with 71 is 10% of what number.

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Answers

[tex]\huge\text{Hey there!}[/tex]

“ [tex]\mathsf{Is\ 9a^2 +25\ the\ difference\ of\ 2\ squares?}[/tex]

[tex]\textsf{Well, when you see or hear the word difference it usually MEANS SUBTRACT}\\\textsf{or SUBTRACTION especially in MATHEMATICS!}[/tex]

[tex]\mathsf{\bold{+}\ usually\ means\ sum\ or\ more\ than}[/tex]

[tex]\textsf{So therefore to \boxed{\textsf{Answer}} to this giving question \boxed{\boxed{\huge \text{\bf No}}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day}[/tex]!

~[tex]\frak{Amphitrite1040:)}[/tex]

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Answers

Answer:

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Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has a graduate degree.

Event B: Has over 10 years of experience.

Out of 469 applicants for a job, 159 have over 10 years of experience and 116 have over 10 years of experience and have a graduate degree.

This means that:

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[tex]P(A \cap B) = \frac{116}{469}[/tex]

Desired probability:

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[tex]\frac{116}{159} = 0.7296[/tex] probability that a randomly chosen applicant has over 10 years of experience, given that the applicant has a graduate degree.

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Answers

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Answers

Answer:

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sorry i don't have time to explain but if u have doubts don't hesitate to ask

Make two equations
O = orange, A = allele
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(8O + 5A = 3.68) 3
Make one of them same coefficient
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Solution:
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One orange = $0.26

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