Solve the inequality for x

Answer:

its probably a. x>-53

my appolgies if it's wrong

Answer:

Top right

Step-by-step explanation:

The solution to a system of equation is where the two graphs cross

The top right lines cross at (5,-3)

Answer:

B. Average of the data set

Step-by-step explanation:

The mean is defined as the average of a data set and it's formula is

Mean = [tex]\frac{sum of observations}{number of observations}[/tex]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

The proportion of the tires that would be denied for being underweight through the given process would be:

[tex]0.347[/tex]% of the total tires will be rejected as underweight.

Given that,

Interquartile Range [tex]= 1.5[/tex]

Standard Deviation [tex]= 0.76[/tex]

Considering Mean = 0

and Standard Deviation = 1

Since lower quartile = -0.67448

Upper quartile  = +0.67448

IQ range =  1.34896

To find,

The proportion of tires would be rejected due to being underweight through the process would be:  

1.5 of Interquartile Range = 1.5 × [tex]1.34896 = 2.02344[/tex]

Now,

1.5 of the IQ range below the lower quartile [tex]= (lower quartile) - (1.5 of Interquartile range)[/tex]

[tex]= -0.67448 - 2.02344[/tex]

[tex]= -2.69792[/tex]

The proportion of tires that would be under 1.5 of the interquartile range below the lower quartile:

[tex]= P(x < -2.69792)[/tex] ≈ [tex]P(x < -2.70)[/tex]

Using data through the Normal Distribution Table,

[tex]P(x < -2.70)[/tex] [tex]= 0.00347[/tex]

[tex]= 0.347[/tex]%

Thus, 0.347% of the total tires would be rejected as underweight.

Learn more about "Proportion" here:

brainly.com/question/2548537

Answer:

The steps Erin has to take for the reconciliation of her account and activities is as follows: Select the reconciled transactions, Select Batch actions, and Modify the selected ones.

Step-by-step explanation:

Solution

Since Erin could not detect any matches for the transactions she has entered before and enrolled, she needs to take the following processes to reconcile back all her credit activities which is stated below:

Process 1 :Select the reconciled transactions

Process 2 :Batch Actions

Process 3: Modify Selected

From the process stated above Erin can first of all choose the reconciled transactions, after that she can select the batch actions and lastly modify the ones that was selected with the aim of putting or adding them back in the account reconciliation.

Answer:

A) (3,2)

Step-by-step explanation:

Conditions:

A) (3,2)

B) (0,7)

Answer:

  5 and 13

Step-by-step explanation:

Let x represent the smaller number. Then the larger number is 2x+3, and the difference is ...

  (2x+3) -(x) = 8

  x = 5

The two numbers are 5 and 13.

_____

Check

Twice the smaller number is 10. 3 more than that is 13, the larger number. Their difference is 13 -5 = 8.

Answer:

[tex]y-x = 16[/tex]

Step-by-step explanation:

Given

Set 1: (9,5,y,2,x)

Set 2: (8,x,4,1,3)

Required

(y - x)

First the mean values of set 1 and set 2 has to be calculated

For set 1

[tex]Mean _1 = \frac{(9+5+y+2+x)}{5}[/tex]

Collect like terms

[tex]Mean _1 = \frac{9+5+2+y+x}{5}[/tex]

[tex]Mean _1 = \frac{16+ y+x}{5}[/tex]

For set 2

[tex]Mean _2 = \frac{(8+x+4+1+3)}{5}[/tex]

Collect like terms

[tex]Mean _2 = \frac{8+4+1+3+x}{5}[/tex]

[tex]Mean _2= \frac{16+ x}{5}[/tex]

Given that the mean of set 1 is twice the mean of set 2;

[tex]Mean_1 = 2Mean_2[/tex]

[tex]\frac{16+ y+x}{5} =2 * \frac{16+x}{5}[/tex]

Multiply both sided by 5

[tex]5 * \frac{16+ y+x}{5} = 5 * 2 * \frac{16+x}{5}[/tex]

[tex]16+ y+x = 2 * (16+x)[/tex]

Open bracket

[tex]16+ y+x = 32 + 2x[/tex]

Subtract 16 from both sides

[tex]16+ y+x- 16 = 32 + 2x - 16[/tex]

[tex]16 - 16 + y+x = 32 - 16 + 2x[/tex]

[tex]y+x = 16 + 2x[/tex]

Subtract 2x from both sides

[tex]y+x-2x = 16 + 2x-2x[/tex]

[tex]y-x = 16[/tex]

Answer:

The area of the rectangle increasing at the rate of 140 cm²/s

Step-by-step explanation:

Rectangle area:

A rectangle has two dimensions, length l and width w.

It's area is:

A = l*w.

When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?

We apply implicit differentiation to solve this question:

[tex]A = l*w[/tex]

So

[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]

Length is 20, so [tex]l = 20[/tex].

Width is 10, so [tex]w = 10[/tex]

The length of a rectangle is increasing at a rate of 8 cm/s and its width is increasing at a rate of 3 cm/s.

This means that [tex]\frac{dl}{dt} = 8, \frac{dw}{dt} = 3[/tex]

So

[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]

[tex]\frac{dA}{dt} = 20*3 + 10*8 = 140[/tex]

Area in cm².

So

The area of the rectangle increasing at the rate of 140 cm²/s

Answer:

i think its 64.95cm

Step-by-step explanation:

Answer:

A-using the associative property

Step-by-step explanation:

Answer:

could be c might be a also

Step-by-step explanation:

Answer:

  Exponential; $376.32

Step-by-step explanation:

Generally, an increase of 12% in a month means the prices are 12% more than they were in the previous month. That is, the value has been multiplied by 1.12.

The same would be true for the second month, so the overall multiplier for the two months is ...

  (1.12)(1.12) = 1.12^2 = 1.2544

This makes the food bill for the second month amount to ...

  1.2544 × $300 = $376.32

_____

As with all percentages, you need to be clear about what base is being used. Here, we have assumed the base for a monthly increase is the value at the beginning of the month.

If, instead, it is the value at the beginning of the year, then the increase is linear, not exponential. 12% of the value at the beginning of the year is the same throughout the year.

Answer:

557

Step-by-step explanation:

l x w

13x24

13x7

22x7

557

f(3x - 1) = 6x - 1

Rewrite 6x - 1 as a function of 3x - 1:

6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1

That is,

f(3x - 1) = 2(3x - 1) + 1

which means

f(x) = 2x + 1

and so

f(0) = 2*0 + 1 = 1

Answer:

The average of the extracted scores  = 133.33

Step-by-step explanation:

Given data the average mark of candidates in an aptitude test was 138.5 with a standard deviation of 10.6

mean of the aptitude test = 138.5

Standard deviation of the  aptitude test = 10.6

Given three scores extracted from the test are 178,122,100

The average of the extracted scores = ∑x / n

The average of the extracted scores

                                        = [tex]\frac{178 +122 +100}{3}[/tex]

                                        = 133.33

Final answer:-

The average of the extracted scores  = 133.33

Answer:

Band: 30%

Chorus: 18%

Painting: 21%

Robotics: 14%

Coding: 17%

Answer:

20 hours

Step-by-step explanation:

first calculate volume:

12x10x3=360

then divide by 18

360/18=20

So 20 hours in total

Answer:

So since the formula for a square is w*h

That means that the area is 1*1 or 1 unit^2

I knew it was a joke question.

:))))

Step-by-step explanation:

Answer:

Don and Mary received a discount of 50%.

Step-by-step explanation:

Initially, we use a rule of three to find the percentage of the initial price that they paid.

The discount is 100% subtracted by the percentage they paid.

Percentage they paid:

The normal price for a couple is $1340, which is 100%.

They paid $670, which is x%. We have to find x.

$1340 - 100%

$670 - x%

[tex]1340x = 100*670[/tex]

[tex]x = \frac{100*670}{1340}[/tex]

[tex]x = 50[/tex]

They paid 50% of the original price.

What discount percent did Don and Mary recieve?​

100 - 50% = 50%

Don and Mary received a discount of 50%.

Answer:

120 ways

Step-by-step explanation:

There are 3 spots and 6 options

_ _ _

1  2 3

6 ways for 1st chair to be chosen

5 ways for 2nd chair to be chosen (1st chair is chosen already, so there are 5 players left)

4 ways for 3rd chair to be chosen (1st and 2nd are already chosen, only 4 players left)

Multiply 6*5*4 to find the total number of ways (120)

Answer:

Area of the figure = 254.5 cm²

Step-by-step explanation:

Area of rectangle = Length × Width

Area of triangle = 1/2(base × Height)

Dividing the figure into parts for convenience

So,

Rectangle 1  (the uppermost):

4 × 6 = 24 cm²

Rectangle 2 (below rectangle 1):

15 × 8 = 120 cm²

Rectangle 3 (with rectangle 2):

11 × 4 = 44 cm²

Triangle 1 :

1/2(7 × 19) = 133/2 = 66.5 cm²

Now adding up all to get the area of the figure:

Area of the figure = 24 + 120 + 44 + 66.5

Area of the figure = 254.5 cm²

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars). The listed values correspond to cars​ A, B,​ C, D,​ E, F, and​ G, respectively.

514 541 302 400 507 406 369

Find the

a.​ mean,

b.​ median,

c.​ midrange,

d. mode for the data.

Also complete parts e. and f.

e. Which car appears to be the safest?

f. Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

Answer:

a) Mean = 434.14

b) Median = 406

c) Midrange = 421.5

d) Mode = 0

e) Car C appears to be the safest

f) The small cars does not appear to have about the same risk of head injury in a crash.

Step-by-step explanation:

We are given the head injury measurements from small cars that were tested in crashes.

The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion.

The listed values are;

A = 514

B = 541

​C = 302

D = 400

​E = 507

F = 406

G = 369

a)​ Mean

The mean of the measurements is given by

Mean = Sum of measurements/ Number of measurements

Mean = (514 + 541 + 302 + 400 + 507 + 406 + 369)/7

Mean = 3039/7

Mean = 434.14

b)​ Median

Arrange the measurements in ascending order (low to high)

302, 369, 400, 406, 507, 514, 541

The median is given by

Median = (n + 1)/2

Median = (7 + 1)/2

Median = 8/2

Median = 4th

Therefore, the 4th measurement is the median that is 406

Median = 406

c)​ Mid-range

The midrange is given by

Midrange = (Max + Min)/2

The maximum measurement in the data set is 541

The minimum measurement in the data set is 302

Midrange = (541 + 302)/2

Midrange = 843/2

Midrange = 421.5

d)​ Mode for the data

The mode of the data set is the most repeated measurement.

302, 369, 400, 406, 507, 514, 541

In the given data set we don't have any repeated measurement therefore, there is no mode or we can say the mode of this data set is 0.

Mode = 0

e) Which car appears to be the safest?

Since we are given that the measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars)

The lowest hic value corresponds to car C that is 302

Therefore, car C appears to be the safest among other cars.

f) Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

302, 369, 400, 406, 507, 514, 541

As you can notice, the hic values differ a lot from each other therefore, we can conclude that the small cars does not appear to have about the same risk of head injury in a crash.

================================================

Explanation:

When we talk about "odds in favor", we will use a colon to separate two whole numbers. The first number represents the number of ways for Evelyn to be chosen treasurer (just one way) and the second number represents all the ways she doesn't get chosen (the four other people)

Put another way, writing "odds in favor are 1:4" basically means "there's 1 way to get Evelyn elected and 4 ways for her to not get elected"

Instead of writing 1:4 you could write "1 to 4"

-----------

Side note: Contrast this with "odds against" and the ratio would flip from 1:4 to 4:1. Same idea, but the number of failures is listed first because we're focusing on the "against" (instead of "favor") portion. We read "4:1" as "4 to 1".

The odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.

To determine the odds in favor of Evelyn becoming treasurer, we need to know the total number of possible outcomes and the number of favorable outcomes.

There are five members in the club, so there are five possible outcomes for the treasurer position, one for each member. Since Evelyn is one of the five members, she has one favorable outcome.

Therefore, the odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.

Learn more about odds in favor here:

https://brainly.com/question/32587212

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Answer:

The percentage would be 20% (5x20=100)

Step-by-step explanation:

Answer:

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Step-by-step explanation:

Given that:

A tank contains 180 liters of fluid in which 50 grams dissolved inside.

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

The salt pumped out[tex]= \dfrac{6 L}{180 L} = \dfrac{1}{30}[/tex] of initial amount added salt

At (t = 0) = 50

To determine the number A (t)

[tex]\dfrac{dA}{dt}=Rate_{in} - Rate _{out}[/tex]

[tex]A' = 6 - \dfrac{1}{30}A[/tex]

[tex]A' + \dfrac{1}{30}A = 6[/tex]

Integrating factor  [tex]y = e^{\int\limits pdt[/tex]

[tex]y = e^{\int\limits \dfrac{1}{30}dt}[/tex]

[tex]y = e^{\dfrac{t}{30}}[/tex]

[tex](e^{ \frac{t}{30}}A)' =4 e ^{\dfrac{t}{30}}+c[/tex]

Taking integral on the both sides;

[tex]Ae ^{\dfrac{t}{30}}= 6 * 30 e^{\dfrac{t}{30}} + c[/tex]

[tex]A = 180+ ce^ {-\dfrac{t}{30}}[/tex]

At  A(t = 0) = 50

50 = 180  + C            (assuming C = [tex]ce ^{-\dfrac{t}{30}}[/tex])

C = 50 - 180

C = 130

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Answer:

D . P(x)=-0.5

Step-by-step explanation:

i think please mark my answer as a brainliest answer and follow me.

Answer:

6 4 5 6 7

Step-by-step explanation:

The mode would be 5. The first 2 letters of MODE are MO, which can be an abbreviation for MOST OFTEN.

Answer:

40 - 59 ⇒ 6

60 - 79 ⇒ 5

Answer:

40-59: 6

60-79: 5

Step-by-step explanation:

If you just added up, you can find all the values.