Please help me with 17 and 18!!!!!! (It's related to 16) It's due today!!!!! NO LINK PLEASE!!!!!!!!
Answers
Answer:17: A wave can be defined as follows: It is important to realize that a wave is quite a different object than a particle. A baseball thrown though a window transfers energy from one point to another, but this involves the movement of a material object between two points.
Explanation:
18: In this way, we classify waves into electromagnetic and mechanical waves. The main difference between mechanical and electromagnetic waves is that electromagnetic waves do not require a medium to propagate whereas mechanical waves require a medium in order to propagate.
Related Questions
When copper combines with oxygen to form copper(II) oxide, the charge of the copper ion is
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When you think of the word "respiration," you might think about the process of breathing, which is actually called ventilation. (The respiratory system consists of the windpipe, lungs, etc.) How is breathing related to cellular respiration?
Answers
Answer:
Breathing and cellular respiration are complementary processes that enable the body to produce energy by taken in oxygen which is required for the chemicals contained in food to be broken down there by producing, energy, water and carbon dioxide. The breathing and cellular respiration process also enables the removal of the produced carbon dioxide finally through nose and/or mouth
Explanation:
In cellular respiration, glucose molecules in the presence of oxygen gas are broken down into carbon dioxide and water aerobically in living cells, to release energy and produce ATP as follows;
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
During breathing, oxygen is inhaled into the lungs from the atmosphere and carbon dioxide is exhaled from the longs into the atmosphere, such that the carbon dioxide produced during cellular respiration is transported out of the body through the veins respiratory system, from where is passes out through the nose, while oxygen used in cellular respiration comes from breathing in oxygen into the respiratory system
The oxygen is then transported to the cells through by blood in the blood vessels of the circulatory system to the cells, where the cells use the oxygen for cellular respiration to release energy.
Which of the following describes half-life? Choose which apply.
A. Half-life is the amount of time it takes for half of a sample to decay.
B. The shorter the half-life, the more unstable the nuclide.
C. Half-life cannot be calculated for nuclides.
D. The longer the half-life, the more stable the nuclide
Answers
Answer:
дангггггггггггггггггггггггггггггггггггггггггггггг
Answer: D.
Explanation: I took the test
Solved Exa
Example 1. An iron ball of mass 3 kg is
released from a height of 125 m and falls
freely to the ground. Assuming that the
value of g is 10 m/s2, calculate
(i) time taken by the ball to reach the
ground
(ii) velocity of the ball on reaching the
ground
(iii) the height of the ball at half the time it
takes to reach the ground.
Answers
According to the equations of motion, the time taken to reach the ground is 5 seconds.
Using;
s = ut + 1/2gt^2
s = distance
u = initial velocity
t = time taken
g = acceleration due to gravity
Note that u = 0 m/s since the object was dropped from a height
Substituting values;
125 = 1/2 × 10 × t^2
125 = 5t^2
t^2 = 125/5
t^2 = 25
t = 5 secs
Velocity on reaching the ground is obtained from
v = u + gt
Where u = 0 m/s
v = gt
v = 10 × 5
v = 50 m/s
At half the time it takes to reach the ground;
s = ut + 1/2gt^2
Where u = 0 m/s
s = 1/2gt^2
s = 1/2 × 10 × (2.5)^2
s = 31.25 m
Learn more about equation of motion: https://brainly.com/question/8898885
Answer:
(i) time taken by the ball to reach the
ground is 5 sec.
(ii) velocity of the ball on reaching the
ground is 50 m/s.
(iii) the height of the ball at half the time it
takes to reach the ground is 31.25 m.
Step-by-step explanation:
Solution :(i) time taken by the ball to reach the
ground
[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 \times t + \dfrac{1}{2} \times 10 \times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 + \dfrac{10}{2} \times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 + 5\times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 5\times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{125}{5}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{ \cancel{125}}{\cancel{5}}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = 25}}[/tex]
[tex]\longrightarrow{\sf{ \: \: t = \sqrt{25} }}[/tex]
[tex]\longrightarrow \: \: {\sf{\underline{\underline{\red{ t = 5 \: sec}}}}}[/tex]
Hence, the ball taken 5 sec to reach the ground.
[tex]\begin{gathered}\end{gathered}[/tex]
(ii) velocity of the ball on reaching the
ground
[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {u}^{2} = 2as}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {0}^{2} = 2 \times 10 \times 125}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 20 \times 125}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 2500}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v} = \sqrt{2500} }}[/tex]
[tex]\longrightarrow{\sf{ \: \: \underline{\underline{ \red{{v} = 50 \: m/s }}}}}[/tex]
Hence, the velocity of ball is 50 m/s.
[tex]\begin{gathered}\end{gathered}[/tex]
(iii) the height of the ball at half the time it
takes to reach the ground.
[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= 0 \times \dfrac{5}{2} + \dfrac{1}{2} \times 10 \times { \left( \dfrac{5}{2} \right)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= 0 + \dfrac{10}{2} \times { \left( \dfrac{5}{2} \times \dfrac{5}{2} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{5 \times 5}{2 \times 2} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{25}{4} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times \dfrac{25}{4}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10 \times 25}{2 \times 4}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{250}{8}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{\cancel{250}}{\cancel{8}}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {\underline{\underline{\red{s= 31.25 \: m}}}}}}[/tex]
Hence, the height of the ball to reach the ground is 31.25 m.
[tex]\underline{\rule{220pt}{3.5pt}}[/tex]
The energy used to move against the magnetic force is stored as (pick one: potential or kinetic)
Answers
(Click the picture)
What is the source of energy that will send the arrow flying toward the target?
A- The archers ability to aim correctly
B- The arrow’s distance from the ground
C- The springiness of the bow
D- The time it takes to release the bow
Answers
Answer:
a
Explanation:
cause her hand is straight and she followed the direction it sould be correctly unless I am messing something
Describe how seismic waves can be used to determine the location of petroleum far beneath the surface.
Answers
Answer: The seismic waves are useful for the oil and gas exploration beneath the earth crust.
Explanation:
The seismic waves are sent beneath the earth crust to determine the location of fossil fuels like petrol, and natural gas. These seismic waves bound back and their pattern of reflection and refraction is recorded by using a receiver that is a geophone or can be a hydrophone (in water). The seismic waves bounce back indicating towards the reservoir of fossil fuel exhibit a characteristic pattern that can help in tracing the location of the fossil fuel.
Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .
Answers
Answer: Medial rotation
Lateral rotation
Supination
Pronation
Opposition
Explanation:
Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.
Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.
Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.
Pronation is the downward motion of hand to put things down.
Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.
Two point charges of magnitude 5.0 nC and -3.0 nC are separated by
35.0 cm. What is the potential difference between a point infinitely far
away and a point midway between the charges?
Answers
Answer:
V = 411.43 V
Explanation:
The two forces as a result of each of the 2 charges are;
F1 = kq1•q/r
F2 = kq2.q/r
Where r = r/2 since we are dealing with potential difference at a point midway between the charges.
q1 = 5 nC = 5 × 10^(-9) C
q2 = 3 nC = 3 × 10^(-9) C
k = 9 × 10^(9) N.m²/C²
r = 35 cm = 0.35m
r/2 = 0.35/2
Thus;
F1 = (9 × 10^(9) × 5 × 10^(-9) × q)/(0.35/2)²
F1 = 1469.39q
F2 = (9 × 10^(9) × 3 × 10^(-9) × q)/(0.35/2)²
F2 = 881.63q
Net force acting midway is;
F_net = F1 + F2
F_net = 1469.39q + 881.63q
F_net = 2351.02q
Now, we know that formula for electric potential is;
V = kq/r
Thus ;
V = Fr/q derived from the earlier equation for force we used.
Where F is F_net.
V = 2351.02q × r/q
V = 2351.02r
Recall that we are dealing with midpoint and r = r/2
Thus;
V = 2351.02 × 0.35/2
V = 411.43 V
Explain what does a calorimeter measure?
Answers
Measuring the heat of chemical reactions or physical changes.
a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find the magnitude of the thrust.
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Answer: 24 kN
Explanation:
Given
The rocket burns propellant at the rate of
[tex]\dfrac{dm}{dt}=3\ kg/s[/tex]
Relative ejection of gases [tex]v=8000\ m/s[/tex]
The magnitude of thrust force is given by
[tex]F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN[/tex]
When the volume of the gas is reduced, what change in property would be the most reasonable to expect?
Answers
Answer:
Two possibities: Increase in pressure or decrease in temperature.
Explanation:
There are two possibilities under the assumption that mass of the gas is conserved and, consquently, the amount of moles is also conserved, a reduction in the volume of the gas leads to an increase in pressure (Boyle's Law) and a decrease in temperature (Gay-Lussac's Law)
Currents of devices that are in a series circuit ar the same, but the __________can be different, which causes __________to be different as well.
Answers
Answer: its flowing, reaction
Explanation: this is because currents in a device have a flowing object inside
Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?
Answer: The image can be either virtual or real.
Answers
Answer:
the image can be rather real or virtual
The brick wall (of thermal conductivity
1.16 W/m ° C) of a building has dimensions
of 5 m by 7 m and is 18 cm thick.
How much heat flows through the wall in
a 17.2 h period when the average inside and
outside temperatures are, respectively, 24°C
and 8°C?
Answer in units of MJ.
Answers
Answer:223.46 MJ
Explanation:
Given
The thermal conductivity of brick wall is [tex]k=1.16\ W/m.^{\circ}C[/tex]
Cross-section of Wall [tex]A=5\m \times 7\ m[/tex]
time period [tex]t=17.2\ h=17.2\times 60\times 60=61,920\ s[/tex]
Inside temperature [tex]T_i=24^{\circ}C[/tex]
Outside temperature [tex]T_o=8^{\circ}C[/tex]
Heat transfer through the bricks
[tex]\dot{Q}=kA\dfrac{dT}{dx}[/tex]
[tex]\dot{Q}=1.16\times 35\times \dfrac{16}{0.18}\\\\\dot{Q}=3608.88\ W[/tex]
Heat flow for 17.2 h
[tex]Q=3608.88\times 61,920=223.46\ MJ[/tex]
a block of mass 3kg slides along a horizontal surface that has neglitjble friction except dor one section what is the magntiude of acerage frictional force exerted on the block by rough section of surface
Answers
A wedge with a mechanical advantage of 0.78 is used to raise a house corner from its foundation. If the output force is 7500 N, what is the input force?
Answers
Therefore, the input force is 9615.38N
Input force calculation.
T0 determine the input force needed 0.78 to raise a house corner from its foundation we need to use the formula for mechanical advantage.
Mechanical advantage = output force/ input force
Given the output force to be 7500N and the mechanical advantage 0.78.
We can rearrange the the formula
IF = 7500/0.78
IF = 9615.38N
Therefore, the input force is 9615.38N
Learn more about input force below.
https://brainly.com/question/29741758
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PLEASEE HELP!!!!!!Why are the youth not getting involved in their communities and voting? How is media influencing the voters?
Answers
Answer:
because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who
If the angle of incidence is 35 degree, what is the angle of reflection?
Answers
Answer:
35
Explanation:
angle of incidence equals angle of reflection
can someone help me but please no links
Answers
Answer:
1. sand and water
2. suspension
mark me as brainliest plz
What do we call the Earth's magnetic field that extends outward from Earth in all
directions?
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Answer:
Geomagnetic Field
Explanation:
PLZZZZZ HELP MEHH ASAP!!!
Answers
Answer:
C
Explanation:
Copper is a conductor because its valence electrons can move freely from atom to atom.
A spring of spring constant 30.0 N/m is attached to a 2.3 kg mass and set in motion. What is the period and frequency of vibration for the 2.3 kg mass?
Answers
Answer:
1. The period is 1.74 s.
2. The frequency is 0.57 Hz
Explanation:
1. Determination of the the period.
Spring constant (K) = 30 N/m
Mass (m) = 2.3 Kg
Pi (π) = 3.14
Period (T) =?
The period of the vibration can be obtained as follow:
T = 2π√(m/K)
T = 2 × 3.14 × √(2.3 / 30)
T = 6.28 × √(2.3 / 30)
T = 1.74 s
Thus, the period of the vibration is 1.74 s.
2. Determination of the frequency.
Period (T) = 1.74 s
Frequency (f) =?
The frequency of the vibration can be obtained as follow:
f = 1/T
f = 1/1.74
f = 0.57 Hz
Thus, the frequency of the vibration is 0.57 Hz
The period of the vibration is 1.76 s and the frequency of the vibration is 0.57 s-1.
Using the formula;
T = 2π√(m/K)
Where;
T = period
m = mass
K = spring constant
Substituting values;
T = 2(3.142)√2.3/30
T = 6.284 × 0.28
T = 1.76 s
Recall that the period is the inverse of frequency;
f = 1/T
f = 1/1.76 s
f = 0.57 s-1
Learn more about spring constant: https://brainly.com/question/4291098
how many oxygen atoms are there in the products of this equation: C6H12O6+6O2 ➪6CO2+6H2O+energy?
Answers
(6 oxygen atoms)
Write the SI unit of time and temperature
Answers
Answer:
The SI unit of time is second (s) and temperature is Kelvin (K)
Explanation:
hope it is helpful to you
Find the direction of the sum of
these two vectors:
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How does the frequency of infrared electromagnetic waves compare with the frequency of radio and microwaves?
A. The frequency of infrared is higher than radio and microwaves
B. The frequency of infared is lower than radio and microwaves.
C. The frequency of infared is the same as radio and microwaves.
Answers
Answer:
Answer is B.
Because the wavelength of infrared is shorter than microwave radiation
AM and FM stand for two different processes that are used to code voices and music for transmission. What does AM stand for? 1. Amplitude Modulation 2. Amplitude Mediation A
Answers
Answer:
1. Amplitude Modulation
Explanation:
AM is an acronym for Amplitude Modulation and it's refers to a process that is typically used for coding sounds such as voices and music for transmission from one point to another.
On the other hand, FM is an acronym for frequency modulation used for the propagation and transmission of sound waves.
Basically, the two forms of modulation are used for broadcasting in radio transmission.
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
explain the differences between pitch and loudness and what are they connected to?
Answers
Answer:
Loudness and pitch are distinct properties of sound. Loudness is related to the amplitude of the sound wave; pitch is related to its frequency
Explanation:
A 1036 nm film with an index of refraction n=2.62 is placed on the surface of glass n=1.52. Light (λ=520.0 nm) falls hits the perpendicular to the surface from air. You want to increase the thickness so the reflected light cancels. What is the minimum thickness of the film that you must add?
Answers
Answer:
[tex]55.64\ \text{nm}[/tex]
Explanation:
[tex]\lambda[/tex] = Wavelength falling on film = 520 nm
n = Refractive index of film = 2.62
T = Thickness of film
m = Order
We have the relation
[tex]2T=\dfrac{m\lambda}{n}\\\Rightarrow T=\dfrac{m\lambda}{2n}\\\Rightarrow T=\dfrac{m\times 520}{2\times 2.62}\\\Rightarrow T=99.24m[/tex]
The thickness should be greater than 1036 nm. This means [tex]m=11[/tex]
[tex]T=99.24\times 11=1091.64\ \text{nm}[/tex]
Thickness of the film to be added would be
[tex]\Delta T=1091.64-1036=55.64\ \text{nm}[/tex]
Thickness of the film to be added is [tex]55.64\ \text{nm}[/tex].
Answer:
Explanation:
The ray of light is passing from high refractive index medium to low refractive index medium so condition for cancellation of reflected light is as follows .
2μt = (2n+1) λ/2
where μ is refractive index of the medium , t is thickness , λ is wavelength of light and n is a integer .
Putting n = 10
2x 2.62 x t = 21 x 520 / 2 nm
5.24 t = 5460 nm
t = 1042 nm
Thickness required to be added
= 1042 - 1036 = 6 nm .