Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications. A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies: Plant A Plant B Row Total Specification Met 85 35 120 Specification Not Met 15 25 40 Column Total 100 60 160 Find the chi-square test statistic for a hypothesis of independence. Multiple Choice 7.22 14.22 -0.18 14.70

Answer:

Thats not possible

Step-by-step explanation:

There is no:

Answer:

0.902 = 90.2% probability that the flight would leave on time when it is not raining

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Not raining

Event B: Flight leaving on time.

The probability that it will rain is  0.18.

This means that there is a 1 - 0.18 = 0.82 probability of not raining. So [tex]P(A) = 0.82[/tex]

The probability that it  will not rain and the flight will leave on time is 0.74.

This means that [tex]P(A \cap B) = 0.74[/tex]

What is the probability that the  flight would leave on time when it is not raining?

[tex]P(B|A) = \frac{0.74}{0.82} = 0.902[/tex]

0.902 = 90.2% probability that the flight would leave on time when it is not raining

Answer: recantagle

Step-by-step explanation:

Answer:

A) 3, 9, 15, 21, 27, . . .

Step-by-step explanation:

EDGE 2020

Answer:

The second answer is 6.

Step-by-step explanation:

D=6

Answer:

80

Step-by-step explanation:

For every additional 10 hrs, you get 200 more dollars.

Answer:

k  ÷  5  <  25

Step-by-step explanation:

Edg.

Answer:

k ÷ 5 < 25

Step-by-step explanation:

Answer:

Ms. Barclay ordered 9 cupcakes.

Step-by-step explanation:

$1.25x9=11.25

11.25+3.25=$14.50

Answer:

A, W, X, Y, M, O, T, U, V, C, D

Step-by-step explanation:

If you put a line through the middle, then the left and the right side will look the same

Answer:

8n x n x n x n x n x n x n

Step-by-step explanation:

(2n^2)^3 = 8n^ 6

Now just write "n" 6 times and there you go

The given expression without exponents can be written as 8×n×n×n×n×n×n.

The given expression is (2n²)³.

We need to write the given expression without exponents.

The exponent of a number shows how many times the number is multiplied by itself. For example, 2×2×2×2 can be written as 24, as 2 is multiplied by itself 4 times.

Now, the given expression can be simplified as follows:

(2n²)³=2³×(n²)³

=2×2×2×[tex]n^{6}[/tex]  (∵[tex](a^{m}) ^{n}=a^{m\times n}[/tex])

=8×n×n×n×n×n×n

Therefore, the given expression without exponents can be written as 8×n×n×n×n×n×n.

To learn more about exponents visit:

https://brainly.com/question/219134.

#SPJ2

Answer: the answer is 4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

4 on edgunity 2020

Answer:

d = 48 h

Step-by-step explanation:

Lamar's distance traveled is directly proportional to the number of hours be drove.

So distance (d) ∝ hours (h)

Lamar traveled 288 miles in 6 hours

Since d ∝ h

then d = kh    [ where k is the proportionality constant ]

if     288 = k × 6

k =  =288/48

Therefore, equation will be d = 48 h will be the equation

Answer:

The system of equations has a one unique solution

Step-by-step explanation:

To quickly determine the number of solutions of a linear system of equations, we need to express each of the equations in slope-intercept form, so we can compare their slopes, and decide:

1) if they intersect at a unique point (when the slopes are different) thus giving a one solution, or

2) if the slopes have the exact  same value giving parallel lines (with no intersections, and the y-intercept is different so there is no solution), or

3) if there is an infinite number of solutions (both lines are exactly the same, that is same slope and same y-intercept)

So we write them in slope -intercept form:

First equation:

[tex]6x+y=-1\\y=-6x-1[/tex]

second equation:

[tex]-6x-4y=4\\-6x=4y+4\\-6x-4=4y\\y=-\frac{3}{2} x-1[/tex]

So we see that their slopes are different (for the first one slope = -6, and for the second one slope= -3/2) and then the lines must intercept in a one unique point. Therefore the system of equations has a one unique solution.

Answer:

a. P(X>695)=0.026

b. P(X<485)=0.44

Step-by-step explanation:

The question is incomplete:

a. higher than 695 on the test.

b. at most 485 on the test.

We have a normal distribution with mean 500 and standard deviation of 100 for the test scores. We will use the z-scores to calculate the probabilties with the standard normal distribution table.

a. We want to calculate the probability that a randomly selected student scores higher than 695.

We calculate the z-score and then we calculate the probability:

[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{695-500}{100}=\dfrac{195}{100}=1.95\\\\\\P(X>695)=P(z>1.95)=0.026[/tex]

a. We want to calculate the probability that a randomly selected student scores at most 485.

We calculate the z-score and then we calculate the probability:

[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{485-500}{100}=\dfrac{-15}{100}=-0.15\\\\\\P(X<485)=P(z<-0.15)=0.44[/tex]

Answer:

(a)[tex]\dfrac{11}{26}[/tex]

(b)[tex]\dfrac{9}{13}[/tex]

(c)[tex]\dfrac{4}{13}[/tex]

Step-by-step explanation:

Number of cards in a Standard Deck=52

(a)

Number of Diamonds (D)=13

Number of Face Cards(F) = 12

Number of Diamonds that are face cards = 3

[tex]Pr($that the card is a diamond or a face card)=P(D)+P(F)-P(D \cap F)\\=\dfrac{13}{52} +\dfrac{12}{52} -\dfrac{3}{52} \\=\dfrac{22}{52} \\=\dfrac{11}{26}[/tex]

(b)The probability that the card is neither an ace nor a heart.

Number of Aces (A)=4

Number of Hearts(H) = 13

Number of Hearts that are Aces = 1

[tex]Pr($that the card is a Ace or a Heart), P(A \cup H)=P(A)+P(H)-P(A \cap H)\\=\dfrac{4}{52} +\dfrac{13}{52} -\dfrac{1}{52} \\=\dfrac{16}{52} \\$Therefore, probability that the card is neither an ace nor a heart.\\=1-P(A \cup H)\\=1-\dfrac{16}{52}\\=\dfrac{36}{52}\\=\dfrac{9}{13}[/tex]

(c)The probability that the card is a face card or a 3

Number of 3 cards(T)=4

Number of Face Cards(F) = 12

[tex]Pr($that the card is a three or a face card)=P(T)+P(F)\\=\dfrac{4}{52} +\dfrac{12}{52} \\=\dfrac{16}{52} \\=\dfrac{4}{13}[/tex]

Answer:

x = 41 ft

Step-by-step explanation:

35(35+23) = 29(29+x)

2030 = 29(29+x)

70 = 29 + x

x = 41 ft

Answer:

The answer is B.

Step-by-step explanation:

Why do we say that the answer is B?

For each additional class there is a significant increase that represents a minimum value over a total of books, that is, 100% that will always remain, therefore the increase will be an additional average over the other "books" that are already in backpack.

Answer:

The average rate of change is 12x=12.0x.

Description:

Function: x= 1x = 3  convert to short form: x 1x 3

Interval:  x= 1  ,       x 3

Steps:

Input:  Find the average rate of change of f(x)=3x2 on the interval [x,3x].

We have that a=x, b=3x, f(x)=3x2

Thus, f(b)−f(a)b−a=3((3x))2−(3(x)2)3x−(x)=12x.

Answer: the average rate of change is 12x=12.0x.

Please mark brainliest

Hope this helps.

Answer:

3

Step-by-step explanation:

A P E X

Answer:

5 hours and 40 minutes would be class

Step-by-step explanation:

We know that the total time is 7 hours, which in minutes would be:

7 * 60 = 420

420 minutes would be class, now, we subtract the other times that are not to be in class and it would be:

420 - 30 - 50 = 340

So we could say that in class it takes 340 minutes, and if we spend hours it would be:

340/60 = 5.67 hours or also 5 hours and 40 minutes would be class.

Answer:

The correct answer to the following question will be "No". The further explanation is given below.

Step-by-step explanation:

Probability (Keeping the disease out of 1 contact)

= [tex]0.5[/tex]

Probability (not keeping the disease out of 1 contact)

= [tex]1-0.5[/tex]

= [tex]0.5[/tex]

Now,

Probability (not keeping the disease out of 2 contact)

= Keeping the disease out of 1 contact × not keeping the disease out of 1 contact

On putting the estimated values, we get

= [tex]0.5\times 0.5[/tex]

= [tex]0.25[/tex]

So that,

Probability (Keeping the disease out of 2 contact)

= [tex]1-0.25[/tex]

= [tex]0.75 \ i.e., 75 \ percent[/tex]

∴  Not 100%

Answer:

25

Step-by-step explanation:

use a Poisson process to model the arrival.

the mean rate of arrivals  is λ=4.5

The standard deviation is calculated as:

σ==√λ =2.1213

The z-value for a 98% CI is z=2.3262.

If the 98% CI has to be within a error of 0.5 then:

Ul-Ll=2z*σ/√n=2*0.5=1

√n=z*σ=2.3262*2.1213=4.9346

√n=4.9346  and n = 4.9346^2=24.35 rounded to 25

The sample size needed is n=25.

Answer:

The probability that both the male and female student are non-smokers is 0.72.

Step-by-step explanation:

The complete question is:

At a local college,178 of the male students are smokers and 712 are non-smokers. Of the female students,80 are smokers and 720 are nonsmokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers?

Solution:

Let, X denote the number of non-smoker male students and Y denote the number of non-smoker female students.

It is provided that:

X' = 178

X = 712

Tx = 890

Y' = 80

Y = 720

Ty = 800

Compute the probability of selecting a non-smoker male student as follows:

[tex]P (\text{Non-smoker Male student})=\frac{712}{890}=0.80[/tex]

Compute the probability of selecting a non-smoker female student as follows:

[tex]P (\text{Non-smoker Female student})=\frac{720}{800}=0.90[/tex]

Compute the probability that both the male and female student are non-smokers as follows:[tex]P(\text{Non-smoker Male and Female})=P(\text{Non-smoker Male})\times P(\text{Non-smoker Female})[/tex]The event of any female student being a non-smoker is independent of the male students.

[tex]P(\text{Non-smoker Male and Female})=0.80\times 0.90[/tex]

                                                 [tex]=0.72[/tex]

Thus, the probability that both the male and female student are non-smokers is 0.72.

Answer:

The difference of two numbers is 5 and the difference of their reciprocals is 1/10. find the no.s

Step-by-step explanation:

⇒ x(x-5) = 50

⇒ x2 - 5x - 50 = 0  

⇒  x2 - 10x + 5x - 50 = 0  

⇒ x (x - 10) + 5 (x - 10) = 0

⇒  (x+5) (x-10) = 0

⇒   (x+5) (x-10) = 0  

⇒ x =  -5 or 10  

⇒ x = 10 (x = -5 , rejected)

Answer:

Step-by-step explanation:

The following is the information provided

number of students is 5

The number of math major = 3

The number of statistic major = 2

Label math students as A, B, C

And statistic students as D, E

The total number of ways to select two students from 5 students is 10

The sample space is S = {AB,AC,BC,AD,AE,BD,BE,CD,CE,DE}

Yes , in the sample space the events are equally alike

What is the probability that both selected students are statistics majors

The selected students of statistic major are DE

the probability that both selected students are statistics majors is [tex]\frac{1}{10}[/tex]

= 1/10

What is the probability that both students are math majors

The selected students of statistic major are AC,AB,BC

the probability that both selected students are math majors is [tex]\frac{3}{10}[/tex]

= 3/10

What is the probability that at least one of the students selected is a statistics major

Number of ways to select at least one of the students selected is a statistic major is {AD,AE,BD,BE,CD,CE,DE}

the probability that at least one of the students selected is a statistics major is [tex]\frac{7}{10}[/tex]

7/10

What is the probability that the selected students have different majors

Number of ways to select students with different major is  {AD,AE,BD,BE,CD,CE,}

the probability that the selected students have different majors is [tex]\frac{6}{10}[/tex]

6/10

Answer:

150

Step-by-step explanation:

If you draw a diagram, this will be a rectangle and the line across cuts it into a right triangle, with a base of 120 and a height of 90. The need to know the length of the hypotenuse of the triangle, so we can use the pythagorean theorem.

90^2 + 120^2 = c^2

c=150

Answer: 5 (estimate)

Step-by-step explanation:

x - 17 4/5 = -13 1/5

Estimate:  x - 18 = -13

x - 18 + 18 = -13 + 18

x = 5

actual answer without estimating using exact numbers is 4 3/5 (so estimate is reasonable)

Answer:

103

Step-by-step explanation:

A number to the power of a negative exponent, means 1 divided by that same number to the power of the positive exponent.

1/(216^(-2/3)) + 1/(256^(-3/4)) + 1/(243^(-1/5))

Break it apart into three pieces.

1/(216^(-2/3))

216^(2/3) = 36

1/(256^(-3/4))

256^(3/4) = 64

1/(243^(-1/5))

243^(1/5) = 3

So...

1/(216^(-2/3)) = 36

1/(256^(-3/4)) = 64

1/(243^(-1/5)) = 3

Add the numbers gives:

36 + 64 + 3 = 103

Answer: circumference of the circle is 11.31 meters

C=\pi d\\C=\pi (2r)\\C=2\pi r

Where radius (r) is half of diameter (d)

Since radius of the circle shown in 1.8m, we plug it in the formula and get:

C=2\pi r\\C=2\pi (1.8)\\C=11.31

So C = 11.31 meters

Answer:

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

[tex]\int\limits {0.5 + \frac{6}{(t+4)^{3} } } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} } } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \ where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C[/tex]

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

[tex]\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet[/tex]

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

[tex]\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\ = 1.439 - 0.9167\\= 0.5223feet[/tex]

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

[tex]\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\ = 0.9167 - 0.1875\\= 0.7292feet[/tex]