John bought a new home in 2002. The value of the home increases 4% each year. If the price of the house is $375,000 in 2020, how much did he pay for it in 2002?

Answer:

240 degrees

Step-by-step explanation:

Mathematically, the area of a circle is

A = 2 * pi * r^2

we need to calculate the radius of the circle first

18pi = 2pi * r^2

divide both sides by 2pi

r^2 = 9

r = 3 inches

Area of sector = angle/360 * pi * r^2

6pi = angle/360 * pi * 3^2

6pi = angle/360 * 9pi

(360 * 6pi)/9pi = angle

40 * 6 = 240 degrees

Answer:

[tex]r=\frac{44}{\pi }[/tex]

Step-by-step explanation:

[tex]88=2\pi r[/tex]

[tex]\mathrm{Switch\:sides}\\2\pi r=88\\\frac{2\pi r}{2\pi }=\frac{88}{2\pi }\\r=\frac{44}{\pi }\\or\\r=14.00563[/tex]

Answer:

2 metres

Step-by-step explanation:

Circumference = 2 × π × r

→ Substitute in the values

88 = 2 ×  [tex]\frac{22}{7}[/tex]  × r

→ Divide both sides by 2 to isolate  [tex]\frac{22}{7}[/tex]  and r

44 =  [tex]\frac{22}{7}[/tex]  × r

→ Multiply everything by 7 to get rid of the fraction

308 = 22 × 7r

→ Divide the equation by 22 to isolate 7r

14 = 7r

→ Divide the equation by 7 to isolate r

2 = r

The radius of the circle with a circumference of 88 meters is 2 metres

Answer:

Step-by-step explanation:

tan x-cot x

[tex]=\frac{sin~x}{cos~x} -\frac{cos~x}{sin ~x} \\=\frac{sin^2x-cos^2 x}{sin ~x~cos~x} \\=\frac{-2(cos^2x-sin^2x)}{2 sin ~x~cos~x} \\=\frac{-2 cos~2x}{sin~2x} \\=-2 cos ~2x~cosec~2x[/tex]

Answer:

8a^3.

Step-by-step explanation:

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

(a+b)^3+(a-b)^3=2a^3+6ab^2

According to the question

(a+b)^3+(a-b)^3+6a(a^2-b^2)

Put in the value

=2a^3+6ab^2 +6a^3–6ab^2

=8a^3

In the simplest form expression (a + b)³ + (a - b)³ + 6a(a² - b²) can be written as,  8a³

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Given that,

A algebraic identity,

(a + b)³ + (a - b)³ + 6a(a² - b²)

It is known that,

(a + b)³  = a³ + b³ + 3ab(a + b)

(a - b)³  =  a³ - b³ - 3ab(a - b)

So, now we can substitute expressions

(a + b)³ + (a - b)³ + 6a(a² - b²)

a³ + b³ + 3ab(a + b) + a³ - b³ - 3ab(a - b) +  6a(a² - b²)

a³ + b³ +  3a²b + 3ab² + a³ - b³ -3a²b + 3ab² + 6a³ - 6ab²

8a³

Hence, the simplest form is 8a³

To know more about algebraic expressions check:

https://brainly.com/question/24875240

#SPJ2

Answer:

4

Step-by-step explanation:

g(3) = -2(3)^2 -4 = 2(9) -4 = 18-4 = 14

|f(2)| = | 2^2 -3| = | 4-3| = 1

(g(3) +2) = (14+2) = 16

4*  |f(2)|  = 4*1 = 4

16/4 = 4

f(x)=x²−4x−21

The degree is the biggest power of x.  That's a polynomial of degree 2, also called a quadratic function.  Let's find its zeros.

0 = x²−4x−21 = (x - 7)(x+3)

x=7 or x=-3

The fundamental theorem guarantees every non-constant polynomial with complex coefficients has a complex zero, let's call it r.  If we divide the polynomial by x-r there won't be any remainder and we'll get a new polynomial, one degree less.  The fundamental theorem again applies and (if it's not a constant polynomial) we are assured of another zero, s.  We divide by x-s and get a new polynomial of degree one less.  We repeat all this until we get a constant polynomial (degree zero).    So we get a zero for every degree. They're not necessarily all different.

Answer:

The degree of f(x) is 2. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly 2 zeros. Those zeros are 7 and -3.

Answer:

The fourth choice is the correct one.

Step-by-step explanation:

If the count of negative signs is even, the product is even (positive).

This does not apply to the first choice; this expression is odd.

Same for the second choice.

Same for the third choice.  The expression is odd.

The fourth choice is POSITIVE because there are an even number (2) of negative signs.

Answer:

The graph of the function starts high ends low

Step-by-step explanation:

I put the equation into Desmos

Answer:

7x^2+5x-12

Step-by-step explanation:

(6x^2+5x-3)+(x^2-9)

Combine like terms

(6x^2+ x^2+5x-3-9)

7x^2+5x-12

Answer:

x=5/13

Step-by-step explanation:

2/3+7/2=9x+5/6+4x

2/3+7/2-5/6=9x+4x

lcm of 2,3,6=6

2/3=4/6      7/2=21/6       5/6=5/6

4/6+21/6-5/6=9x+4x

30/6=13x

5=13x

x=5/13

Steps:

Step 1: Simplify both sides of the equation.

2/3−4x+7/2=−9x+5/6

2/3+−4x+7/2=−9x+5/6

(−4x)+( 2/3 + 7/2 )=−9x+ 5/6 (Combine Like Terms)

−4x+25/6=−9x+5/6

−4x+25/6=−9x+5/6

Step 2: Add 9x to both sides.

−4x+25/6+9x=−9x+5/6+9x

5x+25/6=5/6

Step 3: Subtract 25/6 from both sides.

5x+25/6−25/6=5/6−25/6

5x=−10/3

Step 4: Divide both sides by 5.

5x/5=−10/3/5

=  x=-2/3

Answer:  x=-2/3

Please mark brainliest

Hope this helps.

Answer:

To eliminate y- terms

Multiply equ(1) by 3 and equ(2) by -4

To eliminate y- terms

Multiply (1) by 3 and (2) by -5

Step-by-step explanation:

5x - 4y = 28 (1)

3x - 3y = 30 (2)

To eliminate y- terms

Multiply equ(1) by 3 and equ(2) by -4

15x-12y=84

-12x+12y= -120

Add equ (3) and (4)

3x=84-120

3x=-36

x=-36/3

= -12

x=-12

To eliminate x- terms

5x-4y=28

3x-3y=30

Multiply (1) by 3 and (2) by -5

15x-12y=84

-15x+15y=-150

Add the new equation

3y= -66

y= -22

Answer:

18 square meters

Step-by-step explanation:

Answer:

solution,

The given figure if a Trapezium whose parallel sides are of 3 m and 2 m respectively.

Distance between the parallels sides

i.e. height is 3 m

Now,

[tex]area = \frac{1}{2} \times sum \: of \: parallel \: sides \times height \\ = \frac{1}{2} \times (3 + 2) \times 3 \\ = \frac{1}{2} \times 5 \times 3 \\ = \frac{15}{2} \\ = 7.5 \: {m}^{2} [/tex]

Hope this helps...

Good luck on your assignment...

Answer:

When we divide the inequality by 3 we get x < -2 so the answer is A.

f(x)=(x-1)(x+2)(x-2) over all it equals to zero

Answer:

(x-1) (x-2) (x+2)

Step-by-step explanation:

1. Factorice x^2 y -4 de la expresion.

x^2(x-1) -4(x-1)

2. Luego, debemos de factorizar x-1 de la expresion.

(x-1)(x^2 -4)

3. Usando a^2 - b^2= (a-b)(a+b) factorice la expresion.

(x-1) (x-2) (x+2)

Answer:

The car travels 45 miles in one hour.

Step-by-step explanation:

Knowing that one hour is 60 minutes and that the car travels 0.75 miles every minute, you can multiply 60 and 0.75 which gives you 45 miles per hour meaning in one hour the car travels 45 miles.

Answer:

i think it's s d because that's how many sq. there are

[tex]answer \\ 20 \: cm \\ solution \\ volume = 20000 \: {cm}^{3} \\ length = 40 \: cm \\ breadth = 25 \: cm \\ height = \\ now \\ v = l \times b \times h \\ \: \: \: \: \: \: or \: 20000 = 40 \times 25 \times h \\ or \: 20000 = 1000 \times h \\ or \: h = \frac{20000}{1000} \\ h = 20 \: cm \\ hope \: it \: helps[/tex]

Answer:

[tex]20cm[/tex]

Step-by-step explanation:

[tex]volume = length \times width \times height \\ 20000= 40 \times 25 \times h \\ 2000 0= 1000h \\ \frac{20000}{1000} = \frac{1000h}{1000} \\ h = 20[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

C. (1,-1)

Step-by-step explanation:

Lines are intersecting each other at point (1, - 1).

Hence, the system of equations graphed here would be (1, - 1)

Answer:

The volume of the sphere is 32 π /3 cm^3

Step-by-step explanation:

Mathematically, the volume of a sphere can be calculated using the formula below;

V = 4/3 * pi * r^3

Now since we have the radius and diameter = 2 * radius

radius = diameter/2 = 4/2 = 2

Substituting this value into the volume equation;

V = 4/3 * pi * 2^3 = 32pi/3

Answer:

The correct answer is A

Step-by-step explanation:

Answer:

He saves £133 every week

Answer:

[tex]-y^2+6y+16[/tex]

Step-by-step explanation:

[tex]-(y+2)(y-8)[/tex]

[tex]-1(y+2) \times (y-8)[/tex]

[tex](-y-2)\times (y-8)[/tex]

[tex]-y(y-8)-2(y-8)[/tex]

[tex]-y^2+8y-2y+16[/tex]

[tex]-y^2+6y+16[/tex]

Answer:

Option (2).

Step-by-step explanation:

This question is incomplete; here is the complete question and find the figure attached.

In the diagram of a circle O, what is the measure of ∠ABC?

27°

54°

108°

120°

m(minor arc [tex]\widehat {AC}[/tex]) = 126°

m(major arc [tex]\widehat {AC}[/tex]) = 234°

By the intersecting tangents theorem,

If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.

m∠ABC = [tex]\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})][/tex]

             = [tex]\frac{1}{2}(234-126)[/tex]

             = 54°

Therefore, Option (2) will be the answer.

Answer:

B.

Step-by-step explanation:

The right answer is 7/3

please see the attached picture for full solution

hope it helps..

Good luck on your assignment

Answer:

[tex]slope = \frac{7}{3} [/tex]

Step-by-step explanation:

[tex](5 \: \: , \: \: 9) = > (x1 \: \: \:, \: y1) \\ (2 \: \: , \: \: 2) = > (x2 \: \: \:, \: \: y2)[/tex]

[tex] slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{9 - 2}{5 - 2} \\ = \frac{7}{3} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Step-by-step explanation:

[tex]r = \sqrt{ \frac{ax - p}{q + bx} } \\ {r}^{2} = \frac{ax - p}{q + bx} [/tex]

r² (q + bx) = ax - p

qr² + bxr² = ax - p

qr² + p = ax - bxr²

qr² + p = x (a - br²)

[tex]x = \frac{q {r}^{2} + p}{a - b {r}^{2} } [/tex]

Answer:

[tex]\displaystyle x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]

Step-by-step explanation:

[tex]R=\sqrt{\frac{ax-P}{Q+bx}}[/tex]

[tex]\mathrm{Square\:both\:sides}[/tex]

[tex]R^2=\left(\sqrt{\frac{ax-P}{Q+bx}}\right)^2[/tex]

[tex]R^2=\frac{ax-P}{Q+bx}[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}Q+bx[/tex]

[tex]\math{R}^2\left(Q+bx\right)=\frac{ax-P}{Q+bx}\left(Q+bx\right)[/tex]

[tex]\math{R}^2\left(Q+bx\right)=ax-P[/tex]

[tex]\math{R}^2Q+\math{R}^2bx=ax-P[/tex]

[tex]\mathrm{Subtract\:}\math{R}^2Q\mathrm{\:from\:both\:sides}[/tex]

[tex]\math{R}^2Q+\math{R}^2bx-\math{R}^2Q=ax-P-\math{R}^2Q[/tex]

[tex]\math{R}^2bx=ax-P-\math{R}^2Q[/tex]

[tex]\mathrm{Subtract\:}ax\mathrm{\:from\:both\:sides}[/tex]

[tex]\math{R}^2bx-ax=ax-P-\math{R}^2Q-ax[/tex]

[tex]\math{R}^2bx-ax=-P-\math{R}^2Q[/tex]

[tex]\mathrm{Factor}\:\math{R}^2bx-ax[/tex]

[tex]x\left(\math{R}^2b-a\right)=-P-\math{R}^2Q[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}\math{R}^2b-a[/tex]

[tex]\frac{x\left(\math{R}^2b-a\right)}{\math{R}^2b-a}=-\frac{P}{\math{R}^2b-a}-\frac{\math{R}^2Q}{\math{R}^2b-a}[/tex]

[tex]x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]

Answer:

The value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

Step-by-step explanation:

Solve the equation as follows:

[tex]4\times 6^{x}-7=1[/tex]

     [tex]4\times 6^{x}=7+1[/tex]

           [tex]6^{x}=\frac{8}{4}[/tex]

           [tex]6^{x}=2[/tex]

Take log on both sides.

[tex]\log(6^{x})=\log(2)[/tex]

[tex]x\log (6)=\log(2)[/tex]

        [tex]x=\frac{\log(2)}{\log(6)}[/tex]

Thus, the value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

Answer:

Since the full percentage of something is 100% thats because 1*100 = 100.

So since it has 40% chance of rain what would 100-40 be? Well it would be 60. So the probability that it will not rain is

Answer:

Initial population = 313

Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]

Step-by-step explanation:

Let initial population = [tex]x[/tex]

It is given that population gets doubled every 10 minutes.

Population after 10 minutes = [tex]2x[/tex]

Population after 20 minutes = [tex]2^{2} x[/tex]

:

:

Population after 80 minutes = [tex]2^{8} x[/tex] and it is given as 80000.

[tex]\Rightarrow 2^{8} x = 80000\\\Rightarrow x = \dfrac{80000}{256}\\\Rightarrow x = 313[/tex]

So, initial population is 312.5 = ~313

To find, population after 5 hours i.e. 5 [tex]\times[/tex] 60 = 300 minutes

Population after 300 minutes =

[tex]2^{30} x\\\Rightarrow 2^{30} \times 313\\\Rightarrow 3.36 \times 10^{11}[/tex]

So, the answers are:

Initial population = 313

Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]

Answer:

The answer is C 3- sqrt 11

Step-by-step explanation: