I don't understand this, I really need help!!!!!! quickly

Answer:

B

Step-by-step explanation:

Plug in 8 for y in each equation to see if it's true

6+5(8)=46

6+40=46 ✔️

Answer:

I'm think its parallel ||

Step-by-step explanation:

[tex]40 - (40 \div 100 \times 65) = \\ = 40 - (0.4 \times 65) = \\ = 40 - 26 = \\ = 14[/tex]

Answer:

-7/4

Step-by-step explanation:

Hi,

To find the slope of the line, get two points, and divide the change in y over the change in x. So, let's find two points.

(1,-3) and (-3,4)

Change in y: 4 - (-3) = 7 (Remember when you subtract a negative, you add)

Change in x: -3 - 1 = -4

7/-4 = -7/4

-7/4 is your slope.

I hope this helps :)

Answer:

7 will be the answer.

Step-by-step explanation:

The angles are complementary angles i.e their sum is 90°.

(5a+3)°+52°=90°

5a+55°=90°

5a=90°-55°

5a=35°

a=35°/5

a=7

Answer:

$4.40

Explanation:

8/100 = 0.08

55*0.08 = 4.4

Answer:

B

Step-by-step explanation:

The first probability is 10/24, and the second is 9/23. If you multiply these two fractoins you get 15/92. 15/92 is approximately equal to 16%.

Answer:

25

Step-by-step explanation:

A = 70*M

B = 500 + 50*M

Costing the same means equal, so we have the equation:

70M = 500 + 50M

-50M           -50M

20M = 500

20M / 20 = 500 / 20

m- 25 months

Step-by-step explanation:

X+y+4z=2

X+y+x=4-2

X+y+z=2

Answer:

The coordinates of point B are (-3,-3).

Step-by-step explanation:

Let [tex]A(x,y) = (6,-6)[/tex], [tex]C(x,y) = (-6,-2)[/tex] and [tex]\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}[/tex], then we have the following formula by vectorial definition of a line segment:

[tex]\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}[/tex]

[tex]B(x,y) -A(x,y) = \frac{3}{4}\cdot [C(x,y)-A(x,y)][/tex]

[tex]B(x,y) = \frac{3}{4}\cdot C(x,y) +\frac{1}{4}\cdot A(x,y)[/tex]

[tex]B(x,y) = \frac{3}{4}\cdot (-6,-2)+\frac{1}{4}\cdot (6,-6)[/tex]

[tex]B(x,y) = (-3, -3)[/tex]

Answer:

D is one of them

Step-by-step explanation:

the 1st, 2nd, and 3rd are correct

Answer:

Yes.

10 > 9

Step-by-step explanation:

This inequality is true because 10 is greater than 9.

y > 2x + 7

10 > 2(1) + 7

10 > 2 +7

10 > 9

Answer:

b/c

Step-by-step explanation:

Answer:

Yes.

Step-by-step explanation:

Well if the sum of the angles is equal to 180, then it's a triangle. Since [tex]52+18+110=180[/tex], a triangle with the measures 52°, 18°, and 110° is possible. Hope this helps!

Answer:

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{1.3}{\sqrt{1384}} = 0.1[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 3 - 0.1 = 2.9 pounds

The upper end of the interval is the sample mean added to M. So it is 3 + 0.01 = 3.1 pounds

The 99% confidence interval for the mean consumption of meat among males over age 43 is between 2.9 pounds and 3.1 pounds.

Answer:

can you show the graph please?

Answer:

1.86/2 = 0.93/2 = 0.465/2 = 0.2325

Step-by-step explanation:

Answer:

just upload the file

Step-by-step explanation:

Answer:

1:Add the x for the number of tbs 2: Add all the values together.

Step-by-step explanation:

Hope this helped!

Answer:

  7(1 +3x)

Step-by-step explanation:

The simplest monomial is a constant that is a prime number. That constant is a factor of the coefficient of the only other monomial in the expression, so it can factored from both terms.

  = 7 + 7·3x

  = 7(1 +3x)

Answer:

No, Andre is not correct.

Step-by-step explanation:

I believe Andre is not correct because each 1 on the left balances with a 1 on the right. So taking away the two 1s on the left only leaves the hanger balanced if two 1s are removed on the right. This leaves on the left and three 1s on the right, so x=3. This is like x+2=5 if you subtract 2 from the x side then you get x=3. Hope this helps!

Answer:

I think it's false

Step-by-step explanation

Answer:

Radius: [tex]r =\frac{\sqrt {21}}{6}[/tex]

[tex]Center = (-\frac{3}{2}, -\frac{2}{3})[/tex]

Step-by-step explanation:

Given

[tex]9x^2 + 9y^2 + 27x + 12y + 19 = 0[/tex]

Solving (a): The radius of the circle

First, we express the equation as:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where

[tex]r = radius[/tex]

[tex](h,k) =center[/tex]

So, we have:

[tex]9x^2 + 9y^2 + 27x + 12y + 19 = 0[/tex]

Divide through by 9

[tex]x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0[/tex]

Rewrite as:

[tex]x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}[/tex]

Group the expression into 2

[tex][x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}[/tex]

[tex][x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}[/tex]

Next, we complete the square on each group.

For [tex][x^2 + 3x][/tex]

1: Divide the [tex]coefficient\ of\ x\ by\ 2[/tex]

2: Take the [tex]square\ of\ the\ division[/tex]

3: Add this [tex]square\ to\ both\ sides\ of\ the\ equation.[/tex]

So, we have:

[tex][x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}[/tex]

[tex][x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2[/tex]

Factorize

[tex][x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2[/tex]

Apply the same to y

[tex][x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2[/tex]

[tex][x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2[/tex]

[tex][x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}[/tex]

Add the fractions

[tex][x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}[/tex]

[tex][x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}[/tex]

[tex][x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}[/tex]

[tex][x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}[/tex]

Recall that:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

By comparison:

[tex]r^2 =\frac{7}{12}[/tex]

Take square roots of both sides

[tex]r =\sqrt{\frac{7}{12}}[/tex]

Split

[tex]r =\frac{\sqrt 7}{\sqrt 12}[/tex]

Rationalize

[tex]r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}[/tex]

[tex]r =\frac{\sqrt {84}}{12}[/tex]

[tex]r =\frac{\sqrt {4*21}}{12}[/tex]

[tex]r =\frac{2\sqrt {21}}{12}[/tex]

[tex]r =\frac{\sqrt {21}}{6}[/tex]

Solving (b): The center

Recall that:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where

[tex]r = radius[/tex]

[tex](h,k) =center[/tex]

From:

[tex][x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}[/tex]

[tex]-h = \frac{3}{2}[/tex] and [tex]-k = \frac{2}{3}[/tex]

Solve for h and k

[tex]h = -\frac{3}{2}[/tex] and [tex]k = -\frac{2}{3}[/tex]

Hence, the center is:

[tex]Center = (-\frac{3}{2}, -\frac{2}{3})[/tex]

Answer:

21

Step-by-step explanation:

(g o f) (-3) = g ( f(-3) )

First, let's find f(-3):

f(x)=2x²+6x+9

f(-3)=2(-3²)+6(-3)+9

f(-3)=18-18+9

f(-3)=9

Now that we know the value of f(-3), we can sub this into g(f(-3)):

g ( f(-3) ) = g(9)

Find g(9):

g(9)=3x-6

g(9)=3(9)-6

g(9)=27-6

g(9)=21

Answer:

The answer to your problem is 1 5/6

Answer:

11/6

Step-by-step explanation:

First you need to get a common denomintor in order to add fractions.  Here you can multiply 6/3 by two to get 12/6.  Then you can just do 12/6-1/6 since adding a negative number is the same as subtracting, leaving you with 11/6, which cannot be reduced so that is your final answer.

Answer:

it would take her 5 hours

Step-by-step explanation:

16 1/2 divided by 3.25 is 5

Brainliest plz

Answer:

6x-23+3m

6x+3m-27 we can't add them b/c they have d/t

variables so the answer is 6x+3m-27

Answer:

18:45

Step-by-step explanation: