Answer:
w=f×d
=120×5
=600 j...........
If the orbital velocity of a satellite is 2 rad/s then what will be the period of satellite.
Select one:
a. 2 sec
b. 3.14 sec
c. 6 sec
d. 8 sec
Answer:
Using the orbital velocity as deg/time or the angular speed:
1 rev / sec = 2 * pi rad / sec since there are 2 pi rad in a revolution
2 rad/sec = 1 / pi rev/sec = f from above
P = 1 / f = pi sec/rev = 3.14 sec/rev
Weight is the downward pull of
on mass. What one word completes the sentence?
The word "gravity" belongs between "of" and "on".
Which is a vector quantity?
speed
time
acceleration
distance
Answer:
the quantity which has both magnitude and direction is called vector quantity
which statement describes the effects of forces on an object
Answer:
Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.
Explanation:
Which type of exercise program involves a series of exercises interspersed with rest periods?
a
circuit training
b
interval training
c
calisthenics training
d
weight training
Answer:
B) interval training
Explanation:
Interval training is a type of training in which the period of intense activity alternates with the period of active recovery. The duration and intensity of the work interval together with the duration and intensity of the recovery interval make up one series.
When planning interval training, it is necessary to determine: 1. the duration and intensity of the working interval, 2. the duration and intensity of the recovery interval, and 3. the total number of series.
Precisely because of the larger number of variables and the unlimited possibility of combinations, interval training is more efficient and interesting than continuous training.
4. When a ray of light is incident at a critical angle in denser medium, the angle
of refraction in rarer medium is
A 0°
B 45°
C 90°
D 180°
Answer:
C. 90°
Explanation:
The critical angle is that angle of incidence in the dense medium where the angle of refraction is 90°.
In this case, light travels from the more optically dense medium to the less optically dense medium.
When the angle of incidence in the dense medium is equal to the critical angle, the angle of refraction is 90°.
An empty can of soda is yeeted (thrown) into a crowd. Then, a full can of soda is yeeted into a crowd. Throwing the full can took more force to than the empty one to reach the same acceleration. Which law does this show?
Answer:
Newton's third law of motion.
Explanation:
We are told the force needed to throw the full soda can was more than that needed to throw the empty can.
Now, the weight of the full soda can will be more than that of the empty can. Therefore, the full can will demand more force than that of the empty can due to Newton's third law of motion which states that to every action, there is an equal and opposite reaction.
Positive and negative charged objects will affect which type of field?
• gravitational
• electric
• magnetic
Answer:
Electric
Explanation:
Because they are charged objects
According to the law of conservation of energy, which changes would
increase the total energy of a system?
A. An addition of 400 J of GPE and a loss of 250 J of thermal energy
B. An addition of 100 J of thermal energy and a loss of 450 J of
kinetic energy
C. An addition of 200 J of kinetic energy and a loss of 250 J of
thermal energy
D. An addition of 300 J of thermal energy and a loss of 450 J of
kinetic energy
Answer:
Correct option is (a)
Explanation:
According to conservation of energy: Total energy of system remains conserved or we can say total energy = constant
(a) 400J of GPE is added and 250J of thermal energy is lost
⇒ Total energy = 400-250 J = 150 J
hence, 150J energy is increased
(b) 100J of thermal energy is added and 450J of kinetic energy is lost
⇒ Total energy = 100-450 J = -350 J
hence, 350J energy is decreased or lost by system
(c)200J of kinetic energy is added and 250J of thermal energy is lost
⇒ Total energy = 200-250 J = -50 J
hence, 50J energy is decreased or lost by system
(d)300J of thermal energy is added and 450J of kinetic energy is lost
⇒ Total energy = 300-450 J = -150 J
hence, 150J energy is decreased or lost by system
Therefore, correct option is (a)
Explanation:
According to conservation of energy: Total energy of system remains conserved or we can say total energy = constant
(a) 400J of GPE is added and 250J of thermal energy is lost
⇒ Total energy = 400-250 J = 150 J
hence, 150J energy is increased
(b) 100J of thermal energy is added and 450J of kinetic energy is lost
⇒ Total energy = 100-450 J = -350 J
hence, 350J energy is decreased or lost by system
(c)200J of kinetic energy is added and 250J of thermal energy is lost
⇒ Total energy = 200-250 J = -50 J
hence, 50J energy is decreased or lost by system
(d)300J of thermal energy is added and 450J of kinetic energy is lost
⇒ Total energy = 300-450 J = -150 J
hence, 150J energy is decreased or lost by system
Therefore, correct option is (a)
What layer of the atmosphere is hot but does not have enough gas molecules to transfer heat to you (i.e., you would not feel the heat of the layer)?
Group of answer choices
Thermosphere
Tropopause
Stratopause
Answer:
thermosphere...........
PLEASE HELP Due Soon!
What are two examples of chemical energy being transformed?
Answer:
Hope I can help you.
Explanation:
Here u go here are some that you can choose from! :)
1) Air bags are activated by a chemical reaction inside the bag. A sensor turns on an electrical circuit, and then sodium azide is ignited. The reaction that occurs generates nitrogen gas, which fills the bag at an extremely rapid rate.
2) Baking soda and vinegar produce carbon dioxide gas when mixed. As this gas grows in volume, it puts pressure on whatever container it is in, and will erupt out of an opening in the container, creating a volcano effect. This chemical reaction is safe, making it a great science activity for kids.
3) Batteries have two terminals: the anode and the cathode. They're separated by an electrolyte, a chemical that allows the anode and cathode to transmit a charge. When something's connected to a battery, chemical reactions take place along the electrodes to produce electricity. Of course, you can't see the energy in the battery when the battery is just sitting around; it is when the electricity is produced that the energy is seen.
4) Explosives: when an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy. Just because chemical energy is being released, it doesn't mean an explosion will occur. But, when a solid material quickly changes into a hot, expanding gas, you may be looking at an explosion. Take TNT, for example. Two units of solid TNT can instantly change into 15 units of hot gas, creating a dark and sooty explosion.
5) Food: chemical energy in food is released when the food is digested and the molecules of food are broken down into smaller pieces. Our bodies digest food by mixing it with acids and enzymes in the stomach. This process turns carbohydrates into glucose. The stomach (and small intestine) then release that glucose into the bloodstream, serving as energy for our bodies.
6) Heating packs (used to warm up cold hands or soothe sore muscles) have chemicals inside them. A lot of them function by "cracking" (or bending) them. This is because they're filled with iron. Once you crack the heating pack, the iron is exposed to the air. As the iron reacts to the oxygen, it transforms into iron oxide, a chemical that can produce heat.
7) Wood, when dry, stores chemical energy. This chemical energy is released as the wood burns, and it is converted into heat, or thermal energy. This also produces light energy. As a result of burning, the wood turns into an entirely new substance - ashes.
what is fuse short answer
Answer:
Its a fuse.
Explanation:
Start Point: an unlit match. End Point: a lit match.
Answer:
Ok
Explanation:
what is the moment produced by 15n force ?
Answer:
12mA
Explanation:
3. When water droplets are pushed through sand, gravel and carbon filters is the
water clean and ready to drink? Why or why not?
Answer:
i think yes, because the sand together with the filters catches all the impurities of the water that will pass through them. (btw sorry for my English, this is translated from my language in translator, so don't mind my English pls)
6. A 55 kg skier is at the top of a slope, as shown in the illustration below. At the
initial point A, the skier is 10.0 m vertically above the final point B.
a. Set the zero level for gravitational potential energy at B, and find the gravitational
potential energy associated with the skier at A and at B. Then find the difference
in potential energy between these two points.
b. Repeat this problem with the zero level at point A
c. Repeat this problem with the zero level midway down the slope, at a height of 5.0
m.
The question mentions an illustration that is not provided, but I can solve the problem anyway.
Answer:
Ua - Ub = 5,390 J regardless of the reference height
Explanation:
Gravitational Potential Energy
Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or [tex]9.8 m/s^2[/tex].
The problem is about proving the difference in potential energy does not depend on the reference used to calculate them.
a. Let's set the zero level for gravitational potential energy at B, i.e., h=0 at B.
The m=55 kg skier is at the top of the slope (point A) at a height of h=10 m.
The gravitational potential energy Ua is:
Ua = 55 * 9.8 * 10 = 5,390 J
The gravitational potential energy Ub (h=0) is:
Ub = 55 * 9.8 * 0 = 0 J
The difference is:
Ua - Ub = 5,390 J - 0 J = 5,390 J
b. Now fix the zero level at point A (h=0).
The gravitational potential energy Ua (h=0) is:
Ua = 55 * 9.8 * 0 = 0 J
Point B is at a height h=-10 m since it's below the reference.
The gravitational potential energy Ub (h=-10) is:
Ub = 55 * 9.8 * (-10) = -5,390 J
The difference is:
Ua - Ub = 0 J - (-5,390 J) = 5,390 J
We get the same value.
c. Finally, fix the reference at the midpoint between A and B.
Point A is at a height h=5 m since it's 5 m above the reference.
The gravitational potential energy Ua is:
Ua = 55 * 9.8 * 5 = 2695 J
Point B is at a height h=-5 m since it's 5 m below the reference.
The gravitational potential energy Ub is:
Ub = 55 * 9.8 * (-5) = -2695 J
The difference is:
Ua - Ub = 2695 J - (-2695 J) = 5,390 J
Again, we get the same value.
Conclusion:
Ua - Ub = 5,390 J regardless of the reference height
a.) What happens when a force is applied to an atom? b.) What is this called?
Answer:
it binds the negatively charged electrons to the positively charged atomic nucleus.
Explanation:
its called Electromagnetic Force
_____ is the sum of all potential and kinetic energy.
Group of answer choices
Law of Conservation of Energy
Gravitational Potential Energy
Stored energy
Mechanical Energy
Answer:
Mechanical EnergyExplanation:
Mechanical energy is the sum of all potential energy and kinetic energy .
I HOPE IT HELPS ❤❤a ball kicked with a velocity of 8m/s at an angle of 30 degree to horizontal. calculate the time of flight of the ball. (g=10ms^2)
Answer:
Approximately [tex]0.8\; \rm s[/tex] (assuming that air resistance is negligible.)
Explanation:
Let [tex]v_0[/tex] denote the initial velocity of this ball. Let [tex]\theta[/tex] denote the angle of elevation of that velocity.
The initial velocity of this ball could be decomposed into two parts:
Initial vertical velocity: [tex]v_0(\text{vertical}) = v_0 \cdot \sin(\theta)[/tex].Initial horizontal velocity: [tex]v_0(\text{vertical}) = v_0 \cdot \cos(\theta)[/tex].If air resistance on this ball is negligible, [tex]v_0(\text{vertical})[/tex] alone would be sufficient for finding the time of flight of this ball.
Calculate [tex]v_0(\text{vertical})[/tex] given that [tex]v_0 = 8 \; \rm m \cdot s^{-1}[/tex] and [tex]\theta = 30^\circ[/tex]:
[tex]\begin{aligned}& v_0(\text{vertical}) \\ &= v_0 \cdot \sin(\theta) \\ &= \left(8 \; \rm m \cdot s^{-1} \right) \cdot \sin\left(30^{\circ}\right) \\ &= 4\;\rm m \cdot s^{-1} \end{aligned}[/tex].
Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.
Since [tex]v_0(\text{vertical}) = 4\; \rm m \cdot s^{-1}[/tex], the vertical velocity of this ball right before landing would be [tex]v_1(\text{vertical}) = -4\; \rm m \cdot s^{-1}[/tex].
Calculate the change to the vertical velocity of this ball:
[tex]\begin{aligned}& \Delta v(\text{vertical}) \\ & = v_1(\text{vertical}) - v_0(\text{vertical}) \\ &= -8\; \rm m \cdot s^{-1}\end{aligned}[/tex].
In other words, the vertical velocity of this ball should have change by [tex]8\; \rm m \cdot s^{-1}[/tex] during the entire flight (from the launch to the landing.)
The question states that the gravitational field strength on this ball is [tex]g = 10\; \rm m \cdot s^{-2}[/tex]. In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by [tex]10\; \rm m\cdot s^{-1}[/tex] each second. What fraction of a second would it take to change the vertical velocity of this ball by [tex]8\; \rm m \cdot s^{-1}[/tex]?
[tex]\begin{aligned}t &= \frac{\Delta v(\text{initial})}{g} \\ &= \frac{8\; \rm m \cdot s^{-1}}{10\; \rm m \cdot s^{-2}} = 0.8\; \rm s\end{aligned}[/tex].
In other words, it would take [tex]0.8\; \rm s[/tex] to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be [tex]0.8\; \rm s\![/tex].
An object that is falling through the air will feel"weightless because:
Answer: its B
Explanation:
The maximum displacement of an oscillatory motion is A=0.49m. Determine the position x at which the kinetic energy of the particle is half it's elastic potential energy
Answer:
The position x, is ± 0.4 m.
Explanation:
The total mechanical energy of the oscillatory motion is given as;
[tex]E_T = U +K.E\\\\E_T = \frac{1}{2} kA^2\\\\ \frac{1}{2} kA^2 = U +K.E\\\\K.E = \frac{1}{2} kA^2 - U ----equation(1)[/tex]
When the kinetic energy (E) is half of the elastic potential energy (U);
[tex]K.E = \frac{U}{2} ----equation(2)[/tex]
Equate (1) and (2)
[tex]\frac{U}{2} = \frac{1}{2} kA^2 - U\\\\U = kA^2 -2U\\\\U+2U = kA^2\\\\3 U = kA^2\\\\3(\frac{1}{2} kx^2) = kA^2\\\\\frac{3}{2} x^2=A^2\\\\x^2 = \frac{2}{3} A^2\\\\x = \sqrt{\frac{2}{3} A^2} \\\\x = A\sqrt{\frac{2}{3} } \\\\x = 0.49\sqrt{\frac{2}{3} }\\\\x = + /- (0.4 \ m)[/tex]
Thus, the position x, is ± 0.4 m.
What is the current in a copper wire if 650C of charge passes through it in 6 minutes
1. 180A
2. 18A
3. 1.8A
4. 108A
Answer:
3. 1.8A
Explanation:
Given the following data;
Quantity of charge, Q = 650C
Time = 6 minutes to seconds = 6 * 60 = 360 seconds.
To find the current l;
Quantity of charge = current * time
Substituting into the equation, we have;
650 = current * 360
Current = 650/360
Current = 1.8 Amperes
WILL MARK BRAINLIEST PLEASE HELP AND SHOW ALL WORK
Consider the system shown in FIGURE 9-35. Assume that after the string breaks the ball falls through the liquid with constant speed. If the mass of the bucket and the liquid is 1.20 kg, and the mass of the ball is 0.150 kg, what is the reading on the scale (a) Before (b) After the string breaks?
a. 13.23 N
b. 13.2
What you need to do is use this equation:
(m1 + m2) x g
hope it helps!
what's beyond the universe
Answer:
Nobody knows...
Explanation:
density of iron is 8000kg/m cube .calculate the mass of iron is 8000kg/m cube .calculate the mass of iron contained by 5m cube of iron block
answer:
40,000 kg
explanation:density=mass/volume
then mass=density×volume
= 8000× 5
=40,000 kg
Water has a relatively low specific heat.
True
False
Answer:
The answer is False
Explanation:
Hope this helps :)
If Sophie climbs a ladder 3.4 m tall, and Sophie has a mass of 48 kg, how much G.P.E. has she gained?
Answer:
Sophie gained 1,599.36 J of GPE
Explanation:
Gravitational Potential Energy (GPE)
Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=mgh
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity ([tex]9.8 m/s^2[/tex])
Sophie has a mass of m=48 Kg and climbs a ladder that takes her to a height of h=3.4 m.
Calculate the GPE she gained:
U = 48 * 9.8 * 3.4
U = 1,599.36 J
Sophie gained 1,599.36 J of GPE
How would you describe the movement of a transverse wave?
Up and down
Back and forth
In zigzags
Linear
Answer:
Up AND Down
Explanation:
a transverse wave goes up and Down
facts about conolizing into mars?
Mars is the focus of much scientific study about possible human colonization. Its surface conditions and the presence of water on Mars make it arguably the most hospitable of the planets in the Solar System, other than Earth. Mars requires less energy per unit mass (delta-v) to reach from Earth than any planet except Venus.
Permanent human habitation on a planetary body other than the Earth is one of science fiction's most prevalent themes. As technology has advanced, and concerns about the future of humanity on Earth have increased, the argument that space colonization is an achievable and worthwhile goal has gained momentum. Other reasons for colonizing space include economic interests, long-term scientific research best carried out by humans as opposed to robotic probes, and sheer curiosity.
One of Elon Musk's stated goals through his company SpaceX is to make such colonization possible by providing transport, and to "help humanity establish a permanent, self-sustaining colony on Mars within the next 50 to 100 years".
Many organizations support the colonization of Mars. They have also given different reasons and ways humans can live on Mars. One of the oldest organizations is the Mars Society. They promote a NASA program that supports human colonies on Mars. The Mars Society have set up Mars analog research stations in Canada and the United States. All other organizations include MarsDrive, who wants to help fund settlements on Mars, and Mars to Stay. Mars to Stay advocates settlements on Mars. In June 2012, Mars One released a statement that they believe could help start a colony on Mars by 2023.
An ice cream maker has a refrigeration unit which can remove heat at 120 Js'. Liquid ice
cream, of mass 0.6kg at a temperature of 20 °C, is added to the container.
container
refrigeration
unit
(a) Calculate how much energy must be removed from the mixture to cool it to its
freezing point of -16°C.
(Specific heat capacity of ice cream = 2100 J kg 1 °C')
Answer:
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C is 45,360 J
Explanation:
The given parameters for the refrigeration unit and the ice cream are;
The power of the refrigeration unit = 120 J/s
The mass of the liquid ice cream, m = 0.6 kg
The initial temperature of the liquid ice cream, T₁ = 20°C
The freezing point temperature of the ice cream, T₂ = -16°C
The specific heat capacity of the ice cream, c = 2,100 J/kg⁻¹·°C⁻¹
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, ΔQ, is given as follows;
ΔQ = m × c × ΔT
Where;
ΔT = T₁ - T₂
∴ ΔQ = m × c × (T₁ - T₂)
Therefore, by substituting the known values, we have;
ΔQ = 0.6 × 2,100 × (20 - (-16)) = 45,360
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C = ΔQ = 45,360 J.