Find the coordinates of the other endpoint of the​ segment, given its midpoint M and one
endpoint Q.
​M(c​,n​), ​Q(h​,s​)
The second endpoint is P

Answers

Answer 1

Answer:

P(2c - h, 2n - s )

Step-by-step explanation:

If there are two points (x1,y1) and (x2,y2) on the coordinate plane

then midpoint is given by (x1+x2)/2 , (y1+y2)/2

_________________________________________________

in the problem midpoint is m(c,n)

one point is Q(h,s)

let other point be P(x,y)

By using midpoint formula given above

for point P(x,y) and Q(h,s)

midpoint = (x+h)/2, (y+s)/2

also midpoint is m(c,n)

comparing m(c,n) with (x+h)/2, (y+s)/2

c = x+h/2

=> 2c = x+h

=> 2c - h = x

n = (y+s)/2

=> 2n = y+s

=> 2n - s = y

Thus, second endpoint is P(x,y) = P(2c - h, 2n - s )


Related Questions

What’s the correct answer for this question?

Answers

Volume of cone : V=1/3pie r^2h

Answer:

A

Step-by-step explanation:

Volume of cone = (1/3) πr²h

A U.S.-based Internet company offers an online proficiency course in basic accounting. Completing this online course satisfies the "Fundamentals of Accounting" course requirement in many MBA programs. In the first semester, 315 students have enrolled in the course. The marketing research manager divided the country into seven regions of approximately equal population. The course enrollment values for each of the seven regions are given below. The management wants to know if there is equal interest in the course across all regions. Region Enrollment 1 45 2 60 3 30 4 40 5 50 6 55 7 35 The CEO looked at the data presented and said no they are not equal. It is obvious, since the enrollment in one region is 60 and another 30. However, the CFO said that using a Chi-Square Goodness of Fit Test with a 1% significance level, the frequencies in the regions are not significantly different. Which one is correct? Use statistics to support your answer.

Answers

Answer:

[tex]Expected \ mean = \dfrac{sum \ of \ values }{n}[/tex]

[tex]Expected \ mean = \dfrac{315 }{7}[/tex]

Expected mean = 45

The Chi - Square Value = 15.556

Conclusion:

We conclude that there is equal number of average interest in the course across all regions.  

Thus, the CFO is correct, the the frequencies in the regions are not significantly different by using a Chi-Square Goodness of Fit Test with a 1% significance level.

Step-by-step explanation:

From the question; Let state our null hypothesis and alternative hypothesis

Null Hypothesis

[tex]\mathbf{H_0:}[/tex]There is equal number of average interest in the course across all regions.  

Alternative Hypothesis

[tex]\mathbf{H_a:}[/tex] At least one of the region differs in average number of interest in the course.

The table can be better structured as :

Region          Enrollment

1                       45

2                       60

3                       30

4                       40

5                       50

6                       55

7                       35

From above; we know the number of sample = 7

Then our expected mean can be calculated as :

[tex]Expected \ mean = \dfrac{sum \ of \ values }{n}[/tex]

[tex]Expected \ mean = \dfrac{315 }{7}[/tex]

Expected mean = 45

SO, let's construct our Chi-Square  Statistics Test Table as follows:

Observed       Expected       Expected       (O-E)²         [tex]\dfrac{(O-E)^2}{E}[/tex]

(O)                         (E)            proportion    

45                          45           0.142857          0                   0

60                          45           0.142857       225                 5

30                          45           0.142857        225                5

40                          45           0.142857          25               0.556

50                          45           0.142857          25               0.556

55                          45           0.142857         100               2.222

35                          45           0.142857          100              2.222

                                                                                          15.556

The Chi - Square Value = 15.556

Degree of freedom = n- 1

Degree of freedom = 7 - 1

Degree of freedom = 6

Level of significance ∝ = 1% = 0.01

The Critical value of Chi Square test statistic at df = 6 and 0.01 significance level is 16.812

The Decision rule is to reject the Null hypothesis if The Chi Square test statistic X² > 16.812

Thus , since  the Chi Square test statistic is lesser than the critical value,

i.e  15.556 < 16.812 ,we accept null hypothesis [tex]\mathbf{H_0}[/tex]

Conclusion:

We conclude that there is equal number of average interest in the course across all regions.  

Thus, the CFO is correct, the the frequencies in the regions are not significantly different by using a Chi-Square Goodness of Fit Test with a 1% significance level.

Able, ben and cal each played a game.

able scored six times bens score.

cal scored a third of able's score. write down the ratio of able's score to ben;s score to cal's score

Answers

Answer:

Ratio of Able's score to Ben=6:1

Ratio of Ben's score to Cal's=1:2

Ratio of able's score to ben;s score to cal's score=6:1:2

Step-by-step explanation:

Let Ben's score =x

Able scored six times Ben's score

Able=6*x

=6x

Cal scored a third of Able's score

Cal=1/3 of 6x

=1/3(6x)

Ratio of Able's score to Ben

6x:x

=6:1

Ratio of Ben's score to Cal's score

x:1/3(6x)

=x:6x/3

=x:2x

=1:2

Ratio of able's score to ben;s score to cal's score=6:1:2

Two voting districts, C and M, were sampled to investigate voter opinion about tax spending. From a random sample of 100 voters in District C, 22 percent responded yes to the question "Are you in favor of an increase in state spending on the arts?" An independent random sample of 100 voters in District M resulted in 26 percent responding yes to the question. A 95 percent confidence interval for the difference

Answers

Answer:

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p= x/n

Where x = number of success

n = number of samples

For district C,

x = 22

n1 = 100

p1 = 22/100 = 0.22

For district M,

x = 26

n2 = 100

p2 = 26/100 = 0.26

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.025 = 0.975

The z score corresponding to the area on the z table is 1.96. Thus, the z score for the confidence level of 95% is 1.96

Margin of error = 1.96 × √[0.22(1 - 0.22)/100 + 0.26(1 - 0.26)/100]

= 1.96 × √0.00364

= 0.12

Confidence interval = (0.22 - 0.26) ± 0.12

= - 0.04 ± 0.12

The required  95 percent confidence interval for the difference is ( 0.8, 0.16).

Given that,

A random sample of 100 voters in District C, 22 percent responded yes to The question "Are you in favor of an increase in state spending on the arts?"

An independent random sample of 100 voters in District M resulted in 26 percent responding yes to the question.

We have to determine,

A 95 percent confidence interval for the difference.

According to the question,

A random sample of 100 voters in District C, 22 percent responded yes to The question "Are you in favor of an increase in state spending on the arts?"

An independent random sample of 100 voters in District M resulted in 26 percent responding yes to the question.

Confidence interval for the difference in the two proportions is written as,

Difference in sample proportions ± margin of error

Sample proportion, p= x/n

Where x = number of success

n = number of samples

From a random sample of 100 voters in District C,

[tex]x = 22\\\\n_1= 100\\\\p_1 = \dfrac{22}{100} = 0.22[/tex]

From a random sample of 100 voters in District M,

[tex]x = 26\\\\n_1= 100\\\\p_1 = \dfrac{26}{100} = 0.26[/tex]

Therefore,

[tex]Margin \ of \ error = \sqrt{\dfrac{p_1(1-p_1}{n_1} + \dfrac{p_2(1-p_2)}{n_2}}[/tex]

To determine the z score, subtract the confidence level from 100% to get b

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since,  the area in the middle, it becomes

1 - 0.025 = 0.975

The z-score corresponding to the area on the z table is 1.96. Thus, the z score for the confidence level of 95% is 1.96,

[tex]Margin \ of \ error = \sqrt{\dfrac{0.22(1-0.22)}{100} + \dfrac{0.26(1-0.26)}{100}}[/tex]

                           [tex]= \sqrt{\dfrac{0.22(0.78)}{100} +\dfrac{0.26(0.76)}{100}}\\\\= \sqrt{\dfrac{0.17}{100}+ \dfrac{0.19}{100}}\\\\= \sqrt{\dfrac{0.36}{100}}\\\\= \sqrt{0.0036}\\\\= 0.06[/tex]

Then, Confidence interval is given as;

[tex](0.22 - 0.26) \pm 0.12\\\\(-0.4) \pm 0.12\\\\(-0.4+0.12 , -0.4-0.12)\\\\(0.8, 0.16)[/tex]

Hence, The required  95 percent confidence interval for the difference is( 0.8, 0.16)

To know more about Confidence interval click the link given below.

https://brainly.com/question/15349022

g(-4)
Please help!!

Answers

Answer:

1

Step-by-step explanation:

g(-4) means what is the y value when x is -4.

Find x=-4, and when x=-4. y=1

Answer:

1

Step-by-step explanation:

plz answer this asap

Answers

Answer: 20

Step-by-step explanation: 5 times 4 is 20 times 2 is 40, but when you divide by 1/2 you drop down to 20.

You’re answer will be 20

Please help . I’ll mark you as brainliest if correct !

Answers

Answer:

4 ( a+2)

Step-by-step explanation:

The average rate of change is

(f(a) - f(2))/(a-2)

f(a) = 4a^2 -8

f(2) = 4*2^2 -8 = 4*4 -8 = 16-8 = 8

(4a^2 - 8  - 8))/(a-2)

(4a^2 -16) / (a-2)

Factor the numerator

4( a^2 -4) / (a-2)

4( a-2)(a+2) / (a-2)

Cancel

4 ( a+2)

1)Twelve years ago Jane was five times as old as Anne. In three years time,Anne will be half Jane's age How old is each girl at the moment

Answers

Answer:

Step-by-step explanation:

Twelve years ago Jane was five times as old as Anne.  

 J-12=5(A-12)

In three years time, Anne will be half of Jane's age.  

A+3=1/2(J+3)

Simplify and solve this system of equations:

 J-12=5(A-12)

A+3=1/2(J+3)

evaluate will give brainlist

Answers

Answer:

C. 1/25

Step-by-step explanation:

5^-2=5^(2*-1)

5^2=25

25^-1=1/25

Answer:

It is C 1/25 because it won't be -25 because a negative times a negative is a positive

Step-by-step explanation:

The relationship between ttt and rrr is expressed by the equation 2t+3r+6=02t+3r+6=02, t, plus, 3, r, plus, 6, equals, 0. If rrr increases by 444, which of the following statements about ttt must be true?

Answers

Question:

The relationship between t and r is expressed by the equation 2t+3r+6 = 0. If r increases by 4, which of the following statements about t must be true?

Answer:

The value of t is reduced by 6 when the value of r is increased by 4

Step-by-step explanation:

Given

[tex]2t + 3r + 6 = 0[/tex]

Required

What happens when r is increased by 4

[tex]2t + 3r + 6 = 0[/tex] -------- Equation 1

Subtract 2t from both sides

[tex]2t + 3r + 6 - 2t = 0 - 2t[/tex]

[tex]3r + 6 = - 2t[/tex] --- Equation 2

When r is increased by 4, equation 1 becomes

[tex]2T + 3(r+4) + 6 = 0[/tex]

Note that the increment of r also affects the value of t; hence, the new value of t is represented by T

Open bracket

[tex]2T + 3r+12 + 6 = 0[/tex]

Rearrange

[tex]2T + 3r+6 +12 = 0[/tex]

Substitutr -2t for 3r + 6 [From equation 2]

[tex]2T -2t +12 = 0[/tex]

Make T the subject of formula

[tex]2T = 2t - 12[/tex]

Divide both sides by 2

[tex]\frac{2T}{2} = \frac{2t - 12}{2}[/tex]

[tex]T = t - 6[/tex]

This means that the value of t is reduced by 6 when the value of r is increased by 4

(a^2-b^2) (c^2-d^2) +4abcd​

Answers

[tex]a^{2} {c}^{2} - {a}^{2} {d}^{2} - {b}^{2} {c}^{2} + {b}^{2} {d}^{2} + 4abc[/tex]

Find the midpoint of (9,2) and (-7,-9)

Answers

Answer:

(1,-7/2)

Step-by-step explanation:

The midpoint of (9,2)(-7,-9) is (1,-7/2)

When writing expressions for complex numbers, what does i represent?

Answers

Answer:

see below

Step-by-step explanation:

i is the imaginary number and it represents the square root of -1

Jose predicted that he would sell 48 umbrellas. He actually sold 72 umbrellas.What are the values of a and b in the table below. Round to the nearest tenth if necessary

Answers

Answer:

The answer is A

Step-by-step explanation:

You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building. At a certain instant the elevator is 500 feet away from you, and its distance from you is decreasing at a rate of 16 ft/sec. How fast is the elevator descending at that instant?

Answers

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

[tex]h=\sqrt{x^2+y^2}[/tex]

The rate of change for the distance between you and the elevator is given by:

[tex]\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}[/tex]

[tex]-16=\frac{dh}{dy}*\frac{dy}{dt}[/tex]

[tex]\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\[/tex]

Applying the chain rule:

[tex]u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}[/tex]

Therefore, at x=300 and y = 500, dy/dt is:

[tex]-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s[/tex]

The elevator is descending at 18.66 ft/s.

Alex has a bag of stuffed animals containing nine bears, six lions, and three monkeys. The probability that Alex will randomly pull out a bear and then a lion is . Using this probability, determine if the event of pulling out a bear and the event of pulling out a lion was independent, dependent, both, or neither.

Answers

Answer:

P = 0.1764

The events are dependent

Step-by-step explanation:

We have a total of 9 + 6 + 3 = 18 stuffed animals.

The probability of the first animal pulled being a bear is:

P(bear) = N(bear) / N(total)

P(bear) = 9 / 18 = 0.5

Then, for the second animal, we now have only 17 stuffed animals in total.

So the probability of the second animal pulled being a lion, given the first animal was a bear, is:

P(lion | bear) = N(lion) / N(total)

P(lion | bear) = 6 / 17 = 0.3529

So the final probability is the product of these probabilities:

P = P(bear) * P(lion | bear) = 0.5 * 0.3529 = 0.1764

To find if the events are dependent or independent, let's find the probability of the first pick being a lion:

P(lion) = N(lion) / N(total)

P(lion) = 6 / 18 = 0.3333

The probability of picking a lion is different from the probability of picking a lion given we already picked a bear, so the events are dependent.

Simplify (4.5)(5)(-2)

Answers

Answer:

[tex] - 45[/tex]

[tex]2.25( - 2) = - 45 \\ - 45[/tex]

what is the name of the shape graphed by the function: r=2cos theta

Answers

Answer:

Circle

Step-by-step explanation:

r = 2 cos θ

Multiply both sides by r.

r² = 2r cos θ

Convert to rectangular.

x² + y² = 2x

x² − 2x + y² = 0

Complete the square.

x² − 2x + 1 + y² = 1

(x − 1)² + y² = 1

This is a circle with center (1, 0) and radius 1.

The given function r = 2 cos θ is a circle with a center (1, 0) and radius of 1.

What is a circle?

A circle is a shape consisting of all points in a plane that are given the same distance from a given point called the center.

Given function is r = 2 cos θ

Now, Multiply both sides by r.

r² = 2r cos θ

Convert to rectangular form;

x² + y² = 2x

x² − 2x + y² = 0

Using Complete the square.

x² − 2x + 1 + y² = 1

(x − 1)² + y² = 1

Hence, This is a circle with a center (1, 0) and radius of 1.

Learn more about circle here;

brainly.com/question/12512221

#SPJ2


A farmer knows that every 50 eggs his chickens lay, only 45 will be marketable. If his
chickens lay 1000 eggs in a week, how many of them will be marketable?

Answers

Answer:

900 eggs

Step-by-step explanation:

45/50 are marketable

divide the top and bottom by 5

9/10

Multiply this fraction by the 1000 eggs laid

9/10 *1000

900 eggs will be marketable

Answer:

900

Step-by-step explanation:

The area of a circle is 497 squared meters.
What is the radius, in meters?

Answers

Answer: r= 12.58m

Step-by-step explanation:

100% SURE

Could someone please help me with the steps for this problem? Factor by grouping: w²+3w+w+3

Answers

Answer:

Please see steps below

Step-by-step explanation:

In order to factor by grouping, we divide the four terms given into two groups, and extract on each group any common factor  we can.

In our example, we can select the terms: [tex]w^2[/tex]  and [tex]w[/tex] as one of our groups, and [tex]3w[/tex] and 3 in the other group. Then we re-organize the expression as:

[tex](w^2+w)+(3x+3)[/tex]

Now we extract from the first binomial group, the factor [tex]w[/tex] as a common factor of both terms, and from the second group we extract the factor "3" as common factor of those two terms:

[tex](w^2+w)+(3x+3)\\w(w+1)+3(w+1)[/tex]

We notice now that after the extraction, we are left with two exactly equal binomial factors [tex](w+1)[/tex] that appeared in the first group and in the second group. We proceed then to extract it as common factor for the two groups:

[tex]w(w+1)+3(w+1)\\(w+1)(w+3)[/tex]

this last product of two binomials ([tex](w+1)\,(w+3)[/tex] is the result of factoring the original expression.

A tank contains 24 gallons of water when all of a sudden the water begins draining at a constant rate of 2 gallons per hour. Let t represent the number of hours since the water began draining and let v represent the volume of water in the tank.

Required:
a. Write a formula that expresses v in terms of t.
b. As t increases from 3 to 6, v varies from _________ to _________

Answers

Answer:

a) [tex]V(t) = 24 - 2t[/tex]

b) As t increases from 3 to 6, v varies from 18 gallons to 12 gallons.

Step-by-step explanation:

The volume of the tank in terms of the time can be described by the following equation:

[tex]V(t) = V(0) - at[/tex]

In which V(0) is the initial volume and a is the hourly decrease rate.

a. Write a formula that expresses v in terms of t.

The tank initially contains 24 gallons of water, which means that [tex]V(0) = 24[/tex]

Drains at a constant rate of 2 gallons per hour, so [tex]a = 2[/tex]

Then

[tex]V(t) = V(0) - at[/tex]

[tex]V(t) = 24 - 2t[/tex]

b. As t increases from 3 to 6, v varies from _________ to _________

[tex]V(t) = 24 - 2t[/tex]

[tex]V(3) = 24 - 2*3 = 18[/tex]

[tex]V(6) = 24 - 2*6 = 12[/tex]

So as t increases from 3 to 6, v varies from 18 gallons to 12 gallons.

Which one of the following is always true?a. The coefficient of variation measures variability in a positively skewed data set relative to the size of the median.b. None of the suggested answers are correctc. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale.d. The interquartile range is very unique in the sense that it is a measure of central tendency as well as a measure of dispersion.e. The coefficient of variation should only be used to compare positive data on an interval scale.

Answers

Answer:

C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale

Step-by-step explanation:

Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:

[tex]CV = \frac{\sigma_{x} }{\mu_{x} } * 100%[/tex]

Where [tex]\sigma{x}[/tex] is the Standard Deviation

and [tex]\mu_{x}[/tex] is the sample mean

From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.

Coefficient of variation can be used to compare positive as well as negative data on the ratio and interval scale, it is not only used for positive data.

The Interquartile Range is not a measure of central tendency, it is a measure of dispersion.

A store, on average, has 500 customers per day.
a) what can be said about the probability that it will have at least 700 customers on a given day?
from now on, suppose in addition that the variance of the numbers of customers per day is 100.
b) what can be said about the probability that it will have at least 700 customers on a given day?
c) what can be said about the probability that there will be more than 475 and less than 525 customers on a given day?

Answers

Answer:

a) We can not estimate the probability.

b) Zero probability.

c) There is a probability between 95% and 99% that they have between 475 and 525 customers on a given day.

Step-by-step explanation:

a) We can not said nothing because we only know the average of customers per day. We need to know the probability distribution of the amount of customers per day to answer this question.

b) Now that we know that the variance is 100, although we do not know the exact distribution of the values, we can use the empirical rules to estimate the probability of having at least 700 customers on a given day.

If the variance is 100, the standard deviation is √100=10.

Applying the empirical rule (68-95-99.7 rule), we know that there is probability 0.15% of having at least 500+3*10=530 customers per day (more than 3 deviations from the mean).

Then, we can conclude that the probability of having at least 700 customers per day is zero.

c) To estimate this probability, we have to calculate how many deviations from the mean this values represent:

[tex]\Delta_1=475-500=-25=2.5\sigma\\\\\Delta_2=525-500=25=2.5\sigma[/tex]

We have an interval that have a width of ±2.5 deviations from the mean.

For 2 deviations from the mean, it is expected to have 95% of the data.

For 3 deviations from the mean, it is expected to have 99.7% of the data.

Then, for the interval 475 to 525, we can estimate a probability between 95% and 99%.

A random sample of adult female reaction times has a sample mean of x¯=394.3 milliseconds and sample standard deviation of s=84.6 milliseconds. Use the Empirical Rule to determine the approximate percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds.

Answers

Answer:

The percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds is 99.7%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 394.3 ms

Standard deviation = 84.6 ms

Use the Empirical Rule to determine the approximate percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds.

140.5 = 394.3 - 3*84.6

So 140.5 is 3 standard deviations below the mean.

648.1 = 394.3 + 3*84.6

So 648.1 is 3 standard deviations above the mean.

By the Empirical Rule,

The percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds is 99.7%.


Solve for x in the diagram below

Answers

Answer:

So the diagram couldn't come due to coronavirus?

Answer:

there is no diagram

Step-by-step explanation:

What is the y-intercept of a line that has a slope of -3 and passes through point (0, -7)?

Answers

Answer:

Step-by-step explanation:

line equation:  y=mx + C

substitute given values

-7 = -3*0 + C

C=y= -7      ANS

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.

Answers

Answer:

B. (f - g)(x) = [tex]3^x-2x+14[/tex]

Step-by-step explanation:

→Set it up, like so:

[tex](3^x+10)-(2x-4)[/tex]

→Distribute the -1 to (2x - 4):

[tex]3^x+10-2x+4[/tex]

→Add like terms (10 and 4):

[tex]3^x-2x+14[/tex]

Please help me on this

Answers

Answer19/40=x/3.6

By cross multiplication

19*3.6=40*x

68.4 =40x

x=68.4/40

x=1.71

x=

Answer: C

Step-by-step explanation:

[tex]\frac{19}{40} = \frac{x}{3.6}[/tex]     solve by cross product

40x = 68.4   Divide both sides by 40

x =  1.71

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How do you find the axis of symmery in the form f(x) = 3(x - 4)^2 + 5?

Answers

Answer:

so the axis of symmetry is x=4

Answer: X = 4

Explanation: Hope it helps you♡

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