Answer: D. Along the surface of the hill toward the top of the hill.
Hope I helped you!
D. Along the surface of the hill toward the top of the hill.
What quantities belong in cells X and Y?
X: centripetal acceleration
Y: period
X: tangential speed
Y: radius
X: radius
Y: centripetal acceleration
X: period
Y: tangential speed
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
The quantities belonging in cells X and Y is to be considered as the
X: period
Y: tangential speed
Quantities belong in cells X and Y:The equation for centripetal acceleration is
= v² / r
here, v should be the tangential velocity of the body
And the radius of curvature.
So based on this, we can say that
Column X. Tangential Speed
Column Y. radius
Learn more about cell here: https://brainly.com/question/15182235
You are attempting to move a new couch into your house. You apply 200 N of force and
your friend Jake applies 150 N of force in the same direction. The friction of the couch
on the carpet resists the pushing with 100 N of force. There are five forces
Explanation:
try to write complete question
but
200 Newton + 150 Newton -100 Newton
if you are asking this
A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
which is more important while hitting a home run a heavier bat or faster swing? why?
Answer:
Explanation:
the hitting should be in the almost top so the more faster and strong u hit more the ball more at top will go and more far will go
Una barra de hierro cuya longitud inicial es de 2m se le incrementa su temperatura de 20 °C a 120 °C ¿Cuál es la longitud final de la barra? (considera que el coeficiente de dilatación del hierro) es 1,2 x 10-5 1/°C ( 3 puntos)
Answer:
1.9976 m
Explanation:
An iron bar whose initial length is 2m has its temperature increased from 20 ° C to 120 ° C. What is the final length of the bar? (consider that the coefficient of expansion of iron) is 1.2 x 10-5 1 / ° C (3 points)
Given that,
Initial length of an iron bar, [tex]L_0=2\ m[/tex]
The temperature increased from 20°C to 120°C
The coefficient of expansion of iron is [tex]1.2\times 10^{-5}\ /^{\circ} C[/tex]
We need to find the final length of the bar.
The linear expansion equation is given by :
[tex]\Delta L=\alpha L\Delta T[/tex]
Where [tex]\Delta L[/tex] is the change in length
[tex]\Delta L=1.2\times 10^{-5}\times 2\times (120-20)\\\\=0.0024\ m[/tex]
Also, [tex]\Delta L = L_o-L[/tex]
L is final length
[tex]0.0024= 2-L\\\\L=2-0.0024\\\\=1.9976\ m[/tex]
So, the final length of the bar is 1.9976 m
Hi.
1. Define Position
2. Explain Distance
3. Differentiate between distance and position.
Note : All these questions are under Physics.
Answer:
1-Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side. The time interval of each complete vibration is the same
2-Distance is a numerical measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria (e.g. "two counties over"). The distance from a point A to a point B is sometimes denoted as
3-Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time. Displacement is the difference in the object's position from one time to another. Distance is the total amount the object has traveled in a certain period of time.
Explanation:
hope it help
How can mindfulness meditation help you with your well-being?
Answer:
It can really give you a new light and sense of your surroundings. With a well meditated mind, you can see things and feel different almost, but mostly same. But basically, with a meditated mind, you're more focused on what you're doing at the moment or what you're about to do.
Explanation:
~Hope this helps! If this wasn't the answer you were looking for, please don't hesitate to comment here or private message me! Have a nice day/night! :)))~
What is an electromagnetic wave?
A. An induced electric current
B. Vibrating electric and magnetic fields
C. Oscillating electric current
D. An electromagnet
what is the peacocks displacement from 2 to 3 seconds
A roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it reaches a velocity of 35\,\dfrac{\text{m}}{\text{s}}35
s
m
35, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction over 41\,\text{m}41m41, start text, m, end text. We want to find the initial velocity of the roller coaster before it started to accelerate.
Which kinematic formula would be most useful to solve for the target unknown?
Answer:
This one:
Explanation:
Khan academy answer
What do scientists use to measure force?
Answer:
force meter
Explanation:
Answer:
Wrong, the correct answer is "newton"
Explanation:
1 Newton = 1 kilogram-meter per second2
Una persona de 80 kg de masa corre a una velocidad cuya magnitud es de 9m/s. Cual es la magnitud de la cantidad de movimiento? Que magnitud de velocidad debe llevar una persona de 55 kg para tener la misma magnitud de la cantidad de movimiento que la persona de 80 kg?
Responder:
13,01 m / s
Explicación:
Paso uno:
datos dados
masa de la persona 1 m = 80 kg
velocidad de la persona 1 v = 9 m / s
masa de la persona 2 M = 55kg
velocidad de la persona 2 v =?
Segundo paso:
la expresión del impulso se da como
P = mv
para la primera persona, el impulso es
P = 80 * 9
P = 720N
Paso tres:
queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser
720 = 55v
v = 720/55
v = 13,09
v = 13,01 m / s
Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.
Please can you solve it?How to find the complete displacement of a body in this case:
calculating the area under the graph by dividing it
into a triangles and rectangles
A2 = 0.5 × h × b
= 0.5 × 10 × 5 = 25
A1 = 0.5 × 10 × 15 = 75
A4 = 0.5 × 15 × 10 = 75
A4 = h × b = 10 × 35 = 350
total displacement = 25 + 75 + 75 + 350 = 525
I need help with physics
Answer:
mass (m) = 0.075 kg
acceleration (a) = 550000 m/[tex]s^{2}[/tex]
F = ( 0.075 kg )( 550000 m/[tex]s^{2}[/tex] ) = 41250 N
Explanation:
F = ma ; force is equal to mass times acceleration
mass (m) = 0.075 kg
acceleration (a) = 550000 m/[tex]s^{2}[/tex]
F = ( 0.075 kg )( 550000 m/[tex]s^{2}[/tex] ) = 41250 N.
do you get these options in the drop down?
On a seismogram, higher lines drawn in the paper indicate weaker seismic waves.
True
False
True- just pick true
Explanation: it's true
What happens when an electrically charged balloon is placed close to an uncharged soda can?
The balloon attracts the can.
The balloon is negatively charged.
The can attracts the balloon.
The can becomes positively charged.
Answer:
The surface closest to the balloon becomes positively charged, while the far side of the can becomes negatively charged. This results in an attractive force that draws the can to the balloon.
Explanation:
Answer:
The balloon is negatively charged.
Explanation:
hope it helps
for which colour of light is. the index of refraction of glass largest
Answer:
don't know sorry for the irreverent answer..
Answer:
The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.
In the diagram below, a 10-kilogram ball is fired with a
velocity of 500 meters per second from a 1,000 kilogram
cannon. What is the recoil velocity of the cannon?
A. 5 m/s
B. B) 2 m/s
C. C) 10 m/s
D. D) 500 m/s
Answer:
A) 5m/s
Explanation:
Momentum of ball in one direction=momentum of cannon in other direction
mv = mv
(10)(500)=(1000)v
5000=1000v
∴v=5m/s
When a ball is fired with a velocity its momentum remains conserved. The recoil velocity of the cannon is 5m/s.
The velocity with which the cannon is pushed backwards after firing is called the recoil velocity.
The momentum remains conserved . So, according to the momentum conservation principle, initial momentum is equal to the final momentum.
Mu +mu=Mv +mv
where, M is the mass of cannon and m is the mass of ball.
u is the initial velocity and v is the final velocity.
10 kg ball is fired with a velocity of 500 meters per second from a 1,000 kg cannon.
mu = Mv
(10)(500)=(1000)v
5000=1000v
v=5m/s
Thus, the recoil velocity of the cannon is 5 m/s.
Learn more about recoil velocity.
https://brainly.com/question/18837832
#SPJ2
A fossil mammoth bone was found to contain 6.25% carbon-14 percent isotope and 93.75% nitrogen-14 daughter isotope. If the half-life of carbon-14 is 5700 years old, how old is the mammoth bone?
Answer:
The mammoth bone is 22726 years old.
Explanation:
We can find how hold is the mammoth bone using the decay equation:
[tex]N(t) = N_{0}*e^{-\lambda t}[/tex] (1)
Where:
N(t): is the quantity at time t = 6.25%N₀
N₀: is the initial quantity
λ: is the decay constant
First, we need to find λ:
[tex] \lambda = \frac{ln(2)}{t_{1/2}} = \frac{ln(2)}{5700 y} = 1.22 \cdot 10^{-4} y [/tex]
Now, by solving equation (1) for t we have:
[tex]t = \frac{ln(\frac{N(t)}{N_{0}})}{-\lambda} = \frac{ln(0.0625)}{-1.22 \cdot 10^{-4}} = 22726 y[/tex]
Therefore, the mammoth bone is 22726 years old.
I hope it helps you!
How would you use a diet diary or nutrition log to evaluate your eating habits?
Answer:
to see how much you are getting of something
Explanation:
Answer:
I would use it to track everything nutrition wise.
Explanation:
I would use it to track everything nutrition wise. Meaning that if I do anything that is in the process of eating or consuming food, I would log it down. A good example of what goes in a dietary log would be how much you ate, the amount of calories you ate, and occasionally the amount of serving you ate based off the recommended serving size. It should be important to keep a fitness log if you are interested in keeping a diet diary; to further track calories!
Hope this helps <3
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?
Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
What task requires the most work, lifting a 12-kg sack 2 meters or lifting a 25-kg sack 1 meter?
a.) the 12-kg sack
b.) the 25-kg sack
c.) Both require the same amount of work.
d.) Impossible to determine without knowing the contents of the sack
Please answer ASAP!! Thank you!!
Multiply the masses by the respective distances:
(12 kg) (2 m) = 24 J
(25 kg) (1 m) = 25 J
so the heavier bag takes more work to lift, and (b) is the answer.
(d) is technically correct if the sacks are carrying different contents whose masses are not equal, but since we don't know what's inside each sack, assume 12 kg and 25 kg are the masses of each sack *and* their contents.
Al inicio de un paseo recorrerá una distancia de 200 km/h, los primeros 120 km lo hará a una velocidad constante de 60 km/h y el resto a una velocidad constante de 90 km/h,¿Cuánto tiempo en horas total durará el viaje?
Responder:
1 hora 20 min
Explicación:
Paso uno:
datos dados
Durante los primeros 120 km, se nos dice que la velocidad es de 60 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
distancia = 60t -------------------- 1
Segundo paso:
Durante los segundos 80 km, se nos dice que la velocidad es de 90 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
desatancia = 90t ------------------- 2
La distancia total recorrida es de 200 km.
entonces 200 = 60t + 90t
200 = 150t
t = 200/150
t = 1,3 horas
Por lo tanto, el viaje tendrá una duración de 1 hora y 20 minutos aproximadamente.
You are an astronomer on planet tirth, which orbits a distant star. it has recently been accepted that tirth is spherical in shape, though no one knows its size. one day, you learn that on the equinox your sun is directly overhead in the city of tyene, located 750 kilometers due north of you. on the equinox, you go outside in alectown and observe that the altitude of your sun is 87.0 ∘.
Answer:
The circumference of planet tirth is [tex]C = 90000 \ km[/tex]
Explanation:
From the question we are told that
The distance of tyene from the observer is [tex]d = 750 \ km[/tex]
The altitude of the sun from the equinox is [tex]\theta_s = 87.0^o[/tex]
Generally given that on the equinox your sun is directly overhead in the city of tyene , then the altitude of the tyene from the equinox is [tex]\theta_e = 90 ^o[/tex]
Generally the angular distance between tyene and the sun as observed from the equinox is mathematically represented as
[tex]\theta _d = \theta_e - \theta_s[/tex]
=> [tex]\theta _d = 90 -87[/tex]
=> [tex]\theta _d =3^o[/tex]
Generally the ratio of [tex]\theta _d =3^o[/tex] to [tex]360^o[/tex] which is the total angle in a circle is equal to the ratio of [tex]d = 750 \ km[/tex] to the circumference of the planet
So
[tex]\frac{\theta_d}{360} = \frac{750}{C}[/tex]
=> [tex]\frac{3}{360} = \frac{750}{C}[/tex]
=> [tex]C = 90000 \ km[/tex]
What does it mean when work is positive?
Pls someone help 10points!!!
The count rate of a rodioactive material is 800 count\min. If the half-life of the material is 4 days, what would the count rate be in 16 days later.
Answer:
it is 45
Explanation:
By studying ____________________ scientists have learned about the layers of the Earth.
Answer: By studying seismic waves scientists have learned about the layers of the Earth.
Think about the force that causes a planet to orbit the Sun and the direction of this
force. How does a puck swung by a string on the table relate to a planet orbiting the
Sun? What forces are acting on the puck and what forces are acting on the planet
Answer:
1) For the swung puck tied to the string that has a mass m₁ and having another mass m₂ attached to the string that passes through a hole in the table, such that m₂ > m₁
The swung puck rotating on the table is kept in the circular motion on the table by the centripetal force acting towards the center of its rotation along the string, which is given by the amount the weight of m₂ exceeds m₁, in the same way a planet moving around the Sun is kept in its orbit by the gravitational attraction between the planet and the Sun.
2) i) The forces acting on the puck are;
a) The centripetal force in the string, acting inward, towards the center of rotation provided by the weight of m₂
b) The centrifugal force of the puck, acting outward, tending to continue its motion in a straight line
ii) The forces acting on the planet are;
a) The force of gravitational attraction between the planet and the Sun, acting towards the Sun, such that, the planet revolves around the Sun
b) The centrifugal force of the planet, acting outward, tending to move in a linear or straight path
Explanation:
Forces on Puck Swung
Centrifugal Force (Outwards from puck swung )
Tension( Towards the center)
Forces on the Planet
Centrifugal Force (Outwards from Planets )
Gravitational Force ( Inwards towards Sun )
Let us suppose that the
The puck swung is connected with a center at a distance of radius r
so it is revolving around the point just like planets revolve around the Sun.
The Centrifugal Force and Gravitational Force causes the planetary motion around the sun.
The Centrifugal force is an outward force and is observed from the accelerated frame of reference , In our case Planet and puck swung are the accelerated frame of references.
The Gravitational Force between the Sun and the planets (directed towards Sun) is balanced by Centrifugal Force.
Let us consider that the string of puck swung has negligible mass
So the Tension which is directed towards the center will provide the force to counterbalance the centrifugal force acting on puck swung.
So Tension will act towards the center in case of puck swung and centrifugal force will act outwards.
For more information please refer to the link below
https://brainly.com/question/17167298
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving
upwards and is slowing down at a rate of 2.0 m/s? What is Abdul's apparent weight?
Use g = 10 m/s
Answer:
Abdul has an apparent weight of 600 newtons.
Explanation:
The statement is incorrectly written. Its correct form is:
Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving upwards and is slowing down at a rate of 2.0 m/s2. What is Abdul's apparent weight? Use g = 10 m/s2.
According to the statement, we know that elevator and Abdul himself are moving upwards and decelerating, which means that Abdul feels a force from elevator is the same direction of his weight. From 2nd Newton's Law we find the following equation of equilibrium:
[tex]\Sigma F = F-m\cdot g = m\cdot a[/tex] (1)
Where:
[tex]F[/tex] - Apparent weight, measured in newtons.
[tex]m[/tex] - Mass of Abdul, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration of the elevator-Abdul system, measured in meters per square second.
In (1) we clear the apparent weight:
[tex]F = m \cdot (a+g)[/tex]
If we know that [tex]m = 50\,kg[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]g = 10\,\frac{m}{s^{2}}[/tex], we find that the apparent weight of Abdul is:
[tex]F = (50\,kg)\cdot \left(2\,\frac{m}{s^{2}}+10\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 600\,N[/tex]
Abdul has an apparent weight of 600 newtons.
Where would you find the photosphere