A washing machine heats 10kg of water in each wash cycle. How much energy is saved by washing at 30'c instead of 50'c if the starting temperature of the cold water is 16'c? The specific heat capacity of water is 4200 J/Kg'c
The two equations you can use is in the picture.
Answers
8.4 × 10⁵ Joules of heat energy can be saved assuming that there is no heat exchange between the washing machine and the environment.
What is Heat energy?Heat energy is the result of movement of tiny particles called as atoms, molecules, or ions in solids, liquids and gas substances. Heat energy can be transferred from one object to another object.
Let m denote the mass of water and the specific heat capacity of water. The energy required to raise the temperature of that much water by would be:
Q = m × c × ΔT
Washing at 30°C would require a temperature change of
ΔT = 30°C - 16°C = 14°C
Washing at 50°C would require a temperature change of
ΔT = 50°C - 16°C = 34°C
In both situations, c = 4.2 × 10³J.kg/ °C while m = 10kg.
Calculate the energy required in either of the situations as:
Washing at 30°C:
Q(30°C) = c × m × ΔT
Q = 4.2 × 10³J.kg/ °C × 10kg × 14°C
Q = 588000 Joules
Washing at 50°C :
Q (50°C) = c × m × ΔT
Q = 4.2 × 10³J.kg/ °C × 10kg × 34°C
Q = 1428000 Joules
1428000 Joules - 588000 Joules = 8.4 × 10⁵ Joules
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Related Questions
the force of attraction between two masses is 3.60 Newtons if one of the masses is tripled and the distance between the masses is quadrupled what is the new force of attraction
Answers
Answer: F = 19.2 N
Explanation: Given that the initial Force = 3.6N
The formula involved is
F = GMm/r^2
Substitute the force F
3.6 = GMm/r^2
If one of the masses is tripled and the distance between the masses is quadrupled. We have
3.6 = (G × 3Mm)/(4r)^2
Where G will be constant.
3.6 = 3GMm/16r^2
Separate the fraction of number
3.6 = 3/16 × GMm/r^2
Make GMm/r^2 the subject of formula
(3.6 × 16)/3 = GMm/r^2
19.2 = GMm/r^2
Therefore, the new force of attraction is 19.2 N
Does anyone know how to do this question???
Force = 7kN
Pressure = 1mPa
Area = ?
Answers
Answer:
7000 m^2
Explanation:
Pressure=Force/Area
1=7000/Area
1(Area)=7000
Area=7000 m^2
how has E=MC2 helped us with our understanding of how stars like our Sun create energy?
Answers
Answer: please find the answer in the explanation
Explanation:
E = MC^2
Where
E = energy
M = mass
C = speed of light.
This equation is an eyes opener about the relationship between matter and energy. Its explanation about how matter can become energy and how energy can also give information about matter.
It helps us to understand the fusion and fission of both sun and star particles which eventually give us the result of the magnitude of energy they emit or radiate.
Identify the clean sources of energy.
Answers
Answer:
biomass, geothermal, hydropower, solar, and wind.
hope this helped!
What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 465 K? For m, use 0.0202 kg.
Answers
Answer: 757m/s
Explanation:
Given the following :
Mole of neon gas = 1.00 mol
Temperature = 465k
Mass = 0.0202kg
Using the ideal gas equation. For calculating the average kinetic energy molecule :
0.5(mv^2) = 3/2 nRt
Where ;
M = mass, V = volume. R = gas constant(8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles
Plugging our values
0.5(0.0202 × v^2) = 3/2 (1 × 8.31 × 465)
0.0101 v^2 = 5796.225
v^2 = 5796.225 / 0.0101
v^2 = 573883.66
v = √573883.66
v = 757.55109m/s
v = 757m/s
How is work related to force and displacement?
Answers
Answer:
Displacement is the distance and direction an object is moved. Force and work are directly proportional to each other, while force and displacement are indirectly propotional. The equation showing the relationship is W= Fd. OR Work is a scalar. The rate at which work is done or at which energy is transferred. Work is equal to the force parallel to the displacement.
Explanation:
Work is related to force and displacement as the work is the product of the displacement and the force.
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
The SI unit of work done by an object is Joules.
IJ is the work done when a force of 1 N displaces an object by 1 m .
work is the product of displacement and force.
Work Done = Force * Displacement
For example, let us suppose a force of 100 N is used to displace an object by a displacement of 50 m then the work done on the object can be calculated by the above-mentioned formula
work done = 100 N ×50 m
=5000 N m
Thus, we can say the work done on an object depend on the force as well as the displacement, as the work is the product of the force and the displacement
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What do we call the quantity force multiplied by distance
Answers
Answer:
When the force is multiplied by the time of its application, we call the quantity impulse, which changes the momentum of that object.Explanation:
Answer:The quantity force multiplied by distance is called work
Explanation:This is because work is the measure of energy in applying force over a certain distance.
_______ force can be thought of as either a push or a pull, as long as it
makes the object move in a circular path.
Answers
Answer: Centripetal
Explanation: The centripetal force refers to the acting on a body moving in a circular path. This force acts in the direction of the center of rotation. The centripetal force is given by :
F = mv^2 / r
Where m = mass of th body
v. = Velocity
r = radius of the circular path.
For an object to move in a circular path, the force required is called the centripetal force. It is measured in Kgms^-2. It is directly proportional to the product of the Mass and square of it Velocity and varies inversely to the Radius of its path.